Java String remove all non numeric characters but keep the decimal separator

Question

Trying to remove all letters and characters that are not 0-9 and a period. I'm using Character.isDigit() but it also removes decimal, how can I also keep the decimal?

[myStr = myStr.replaceAll( "\[^\\d\]", "" )][1] [1]: http://stackoverflow.com/questions/1533659/how-do-i-remove-the-non-numeric-character-from-a-string-in-java — Bitmap, Apr 29 '12 at 14:30
This is a strange way to say this. Isn't "all letters and characters that are not 0-9 and a period" equivalent to simpler "all characters that are not 0-9 and a period"? I mean, letters are characters which are not 0-9 nor the period. — Adam Zalcman, Apr 29 '12 at 14:30

score 612 · Accepted Answer · edited May 30 '12 at 06:26

612

Try this code:

String str = "a12.334tyz.78x";
str = str.replaceAll("[^\\d.]", "");

Now str will contain "12.334.78".

edited May 30 '12 at 06:26

Andriy M

76,112
17
94
154

answered Apr 29 '12 at 14:30

Óscar López

232,561
37
312
386

26

This could also work: > str = str.replaceAll("[\\D.]", ""); – yeaaaahhhh..hamf hamf Jan 26 '15 at 14:39
1

@Óscar López: how to include negative numbers also? I mean, I have to replace everything that is not a positive/negative number with an empty space. How to do that? – Pankaj Singhal Sep 06 '15 at 09:07
4

@PankajSinghal simply include the minus sign in the regex: `[^\\d.-]` – Óscar López Sep 06 '15 at 14:36
4

@yeaaaahhhh..hamfhamf no, that won't work. We have to negate the whole group (including numbers and dots), your suggested code only negates the numbers, and the result won't include dots, as required. Did you _test_ it? using the sample code above, your code returns `"1233478"`, which is incorrect. – Óscar López Sep 06 '15 at 14:42
Works very well even in Android. Thanks. – juanram0n May 20 '16 at 11:12
i have a array with of numbers and char in it i.e [1,4,7,a,6,d,9,3,5]. I want to filter out all the char from the array. what should i do? – Dishank Jindal Feb 14 '18 at 15:35
how about if we want to remove the dot as well...? – gumuruh Mar 26 '18 at 06:43
@gumuruh Add it to the regex, escaping it: \\. – Óscar López Mar 26 '18 at 14:25
going to revoke my upvote to keep the number at 420. 8-) – ChumiestBucket Nov 01 '18 at 20:21
For Kotlin, use string.replace("[^\\d.]".toRegex(), "") – Kishan Solanki Feb 05 '21 at 15:17

Peter Lawrey · Answer 2 · 2012-04-29T14:37:30.287

122

I would use a regex.

String text = "-jaskdh2367sd.27askjdfh23";
String digits = text.replaceAll("[^0-9.]", "");
System.out.println(digits);

prints

2367.2723

You might like to keep - as well for negative numbers.

edited Apr 29 '12 at 14:37

answered Apr 29 '12 at 14:31

Peter Lawrey

525,659
79
751
1,130

You should not escape the dot in your regexp. – Adam Zalcman Apr 29 '12 at 14:33
Could you please put some explanation for what does `^` and `.` mean in this statement? – Mansour Fahad Aug 19 '14 at 15:32
2

@MansourFahad In a regex `[^` means not these characters and inside a `[]` a `.` is just a `.` – Peter Lawrey Aug 19 '14 at 20:42
1

Since a `.` is just a `a` and doesn’t mean anything, can I just get rid of it? – Mansour Fahad Aug 24 '14 at 11:41
@MansourFahad only if you want no `.`s in your result. – methodsignature Jun 22 '19 at 21:08
this answer is good but small update for newer dart versions. `text.replaceAll(RegExp("[^0-9.]"), "");` – l1nuxuser Jul 02 '19 at 10:14

score 70 · Answer 3 · edited Jul 06 '21 at 13:48

70

Solution

With dash

String phoneNumberstr = "Tel: 00971-557890-999";
String numberRefined = phoneNumberstr.replaceAll("[^\\d-]", "");

Result: 0097-557890-999.

Without dash

If you also do not need "-" in String you can do like this:

String phoneNumberstr = "Tel: 00971-55 7890 999";      
String numberRefined = phoneNumberstr.replaceAll("[^0-9]", "");

Result: 0097557890999.

edited Jul 06 '21 at 13:48

Sergey Vyacheslavovich Brunov

17,291
7
48
81

answered Feb 24 '15 at 12:53

Fakhar

3,946
39
35

Thanks for the great answe!!r – Shridutt Kothari May 25 '16 at 10:07

score 23 · Answer 4 · edited Oct 01 '15 at 11:41

23

With guava:

String input = "abx123.5";
String result = CharMatcher.inRange('0', '9').or(CharMatcher.is('.')).retainFrom(input);

see http://code.google.com/p/guava-libraries/wiki/StringsExplained

edited Oct 01 '15 at 11:41

Kerem Baydoğan

10,475
1
43
50

answered Apr 29 '12 at 14:33

@egorikem if your project is already using guava, you can use it at no extra cost.. – stan Feb 19 '19 at 16:04

score 23 · Answer 5 · edited Mar 27 '17 at 20:52

23

str = str.replaceAll("\\D+","");

edited Mar 27 '17 at 20:52

Robert

10,403
14
67
117

answered Mar 27 '17 at 13:59

Angoranator777

334
2
6

Dunno why people downvoted your solution... Helped me alot, thanks! Votes up! – Zarial Apr 10 '17 at 10:34
Thanks Zarial, I see Robert actually edited my answer from str = str.replaceAll("\D+",""); to str = str.replaceAll("\\D+",""); ... So i made this mistake when pasting it into StackO's editor box thingy. So thank you Robert for fixing. Now it works! – Angoranator777 Oct 19 '17 at 23:26
it's downvoted cause it's a repost. Exact same answer has already been sublitted 5 years ago !! see above : https://stackoverflow.com/a/10372905/704246 – Saad Benbouzid Dec 13 '17 at 15:50
@SaadBenbouzid huh? what is your definition of the exact same answer? – Boris Treukhov Jan 31 '18 at 16:36
@BorisTreukhov see comment from "yeaaaahhhh..hamf hamf" from "Jan 26 '15 at 14:39" on the same page – Saad Benbouzid Jan 31 '18 at 17:03
4

@SaadBenbouzid 1) that is comment and not an answer 2) that is a completely different regex 3) not all answers which use regex D are identical it's like pointing that all C language answers which use `printf()` are duplicates. Also if you see an answer in comment you can ask mod to convert it to an answer or even add an answer on your own - answers in comments are discouraged on StackOverlow. – Boris Treukhov Jan 31 '18 at 17:20

score 10 · Answer 6 · answered May 25 '16 at 12:40

10

Simple way without using Regex:

Adding an extra character check for dot '.' will solve the requirement:

public static String getOnlyNumerics(String str) {
    if (str == null) {
        return null;
    }
    StringBuffer strBuff = new StringBuffer();
    char c;
    for (int i = 0; i < str.length() ; i++) {
        c = str.charAt(i);
        if (Character.isDigit(c) || c == '.') {
            strBuff.append(c);
        }
    }
    return strBuff.toString();
}

answered May 25 '16 at 12:40

Shridutt Kothari

7,326
3
41
61

1

Since the `StringBuffer` is only being used inside the function, and not shared between threads, it would be recommended, for performance reasons, to use `StringBuilder`, instead. See: https://stackoverflow.com/a/4793503/679240 and https://stackoverflow.com/a/2771852/679240 – Haroldo_OK Feb 24 '22 at 12:35

Maher Abuthraa · Answer 7 · 2020-09-25T09:40:54.553

Currency decimal separator can be different from Locale to another. It could be dangerous to consider . as separator always. i.e.

╔════════════════╦═══════════════════╗
║    Locale      ║      Sample       ║
╠════════════════╬═══════════════════╣
║ USA            ║ $1,222,333.44 USD ║
║ United Kingdom ║ £1.222.333,44 GBP ║
║ European       ║ €1.333.333,44 EUR ║
╚════════════════╩═══════════════════╝

I think the proper way is:

Get decimal character via DecimalFormatSymbols by default Locale or specified one.
Cook regex pattern with decimal character in order to obtain digits only

And here how I am solving it:

code:

import java.text.DecimalFormatSymbols;
import java.util.Locale;

    public static String getDigit(String quote, Locale locale) {
    char decimalSeparator;
    if (locale == null) {
        decimalSeparator = new DecimalFormatSymbols().getDecimalSeparator();
    } else {
        decimalSeparator = new DecimalFormatSymbols(locale).getDecimalSeparator();
    }

    String regex = "[^0-9" + decimalSeparator + "]";
    String valueOnlyDigit = quote.replaceAll(regex, "");
    try {
        return valueOnlyDigit;
    } catch (ArithmeticException | NumberFormatException e) {
        Log.e(TAG, "Error in getMoneyAsDecimal", e);
        return null;
    }
    return null;
}

I hope that may help,'.

Although this was not asked, but this is the only solution that works with localization. — Herrbert74, Sep 25 '20 at 09:19

score 6 · Answer 8 · answered Mar 15 '19 at 17:41

6

For the Android folks coming here for Kotlin

val dirtyString = " Account Balance: $-12,345.67"
val cleanString = dirtyString.replace("[^\\d.]".toRegex(), "")

Output:

cleanString = "12345.67"

This could then be safely converted toDouble(), toFloat() or toInt() if needed

answered Mar 15 '19 at 17:41

Michael

9,639
3
64
69

Or Number , in pure Java. – Alex Byrth Jun 11 '20 at 22:52

score 3 · Answer 9 · answered Nov 15 '16 at 20:14

A way to replace it with a java 8 stream:

public static void main(String[] args) throws IOException
{
    String test = "ab19198zxncvl1308j10923.";
    StringBuilder result = new StringBuilder();

    test.chars().mapToObj( i-> (char)i ).filter( c -> Character.isDigit(c) || c == '.' ).forEach( c -> result.append(c) );

    System.out.println( result ); //returns 19198.130810923.
}

score 2 · Answer 10 · answered Jul 19 '22 at 17:46

2

The below code should remove all non-digit characters and allow periods.

String newString = currentString.replaceAll("[\\D.]", "");

answered Jul 19 '22 at 17:46

David K

73
4

score 1 · Answer 11 · answered Apr 01 '19 at 21:25

This handles null inputs, negative numbers and decimals (you need to include the Apache Commons Lang library, version 3.8 or higher, in your project):

import org.apache.commons.lang3.RegExUtils;
result = RegExUtils.removeAll(input, "-?[^\\d.]");

Library reference: https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/RegExUtils.html

Java String remove all non numeric characters but keep the decimal separator

11 Answers11

Solution

With dash

Without dash

Linked

Related