PHP function to get the subdomain of a URL

Question

Is there a function in PHP to get the name of the subdomain?

In the following example I would like to get the "en" part of the URL:

en.example.com

Answer 1

Here's a one line solution:

array_shift((explode('.', $_SERVER['HTTP_HOST'])));

Or using your example:

array_shift((explode('.', 'en.example.com')));

EDIT: Fixed "only variables should be passed by reference" by adding double parenthesis.

EDIT 2: Starting from PHP 5.4 you can simply do:

explode('.', 'en.example.com')[0];

Answer 2

Uses the parse_url function.

$url = 'http://en.example.com';

$parsedUrl = parse_url($url);

$host = explode('.', $parsedUrl['host']);

$subdomain = $host[0];
echo $subdomain;

For multiple subdomains

$url = 'http://usa.en.example.com';

$parsedUrl = parse_url($url);

$host = explode('.', $parsedUrl['host']);

$subdomains = array_slice($host, 0, count($host) - 2 );
print_r($subdomains);

Answer 3

You can do this by first getting the domain name (e.g. sub.example.com => example.co.uk) and then use strstr to get the subdomains.

$testArray = array(
    'sub1.sub2.example.co.uk',
    'sub1.example.com',
    'example.com',
    'sub1.sub2.sub3.example.co.uk',
    'sub1.sub2.sub3.example.com',
    'sub1.sub2.example.com'
);

foreach($testArray as $k => $v)
{
    echo $k." => ".extract_subdomains($v)."\n";
}

function extract_domain($domain)
{
    if(preg_match("/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[a-z\.]{2,6})$/i", $domain, $matches))
    {
        return $matches['domain'];
    } else {
        return $domain;
    }
}

function extract_subdomains($domain)
{
    $subdomains = $domain;
    $domain = extract_domain($subdomains);

    $subdomains = rtrim(strstr($subdomains, $domain, true), '.');

    return $subdomains;
}

Outputs:

0 => sub1.sub2
1 => sub1
2 =>
3 => sub1.sub2.sub3
4 => sub1.sub2.sub3
5 => sub1.sub2

Answer 4

http://php.net/parse_url

<?php
  $url = 'http://user:password@sub.hostname.tld/path?argument=value#anchor';
  $array=parse_url($url);
  $array['host']=explode('.', $array['host']);

  echo $array['host'][0]; // returns 'sub'
?>

Answer 5

As the only reliable source for domain suffixes are the domain registrars, you can't find the subdomain without their knowledge. There is a list with all domain suffixes at https://publicsuffix.org. This site also links to a PHP library: https://github.com/jeremykendall/php-domain-parser.

Please find an example below. I also added the sample for en.test.co.uk which is a domain with a multi suffix (co.uk).

<?php

require_once 'vendor/autoload.php';

$pslManager = new Pdp\PublicSuffixListManager();
$parser = new Pdp\Parser($pslManager->getList());
$host = 'http://en.example.com';
$url = $parser->parseUrl($host);

echo $url->host->subdomain;


$host = 'http://en.test.co.uk';
$url = $parser->parseUrl($host);

echo $url->host->subdomain;

Answer 6

PHP 7.0: Use the explode function and create a list of all the results.

list($subdomain,$host) = explode('.', $_SERVER["SERVER_NAME"]);

Example: sub.domain.com

echo $subdomain; 

Result: sub

echo $host;

Result: domain

Answer 7

Simply...

    preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $url, $match);

Just read $match[1]

Working example

It works perfectly with this list of urls

$url = array(
    'http://www.domain.com', // www
    'http://domain.com', // --nothing--
    'https://domain.com', // --nothing--
    'www.domain.com', // www
    'domain.com', // --nothing--
    'www.domain.com/some/path', // www
    'http://sub.domain.com/domain.com', // sub
    'опубликованному.значения.ua', // опубликованному ;)
    'значения.ua', // --nothing--
    'http://sub-domain.domain.net/domain.net', // sub-domain
    'sub-domain.third-Level_DomaIN.domain.uk.co/domain.net' // sub-domain
);

foreach ($url as $u) {
    preg_match('/(?:http[s]*\:\/\/)*(.*?)\.(?=[^\/]*\..{2,5})/i', $u, $match);
    var_dump($match);
}

Answer 8

Simplest and fastest solution.

$sSubDomain = str_replace('.example.com','',$_SERVER['HTTP_HOST']);

Answer 9

$REFERRER = $_SERVER['HTTP_REFERER']; // Or other method to get a URL for decomposition

$domain = substr($REFERRER, strpos($REFERRER, '://')+3);
$domain = substr($domain, 0, strpos($domain, '/'));
// This line will return 'en' of 'en.example.com'
$subdomain = substr($domain, 0, strpos($domain, '.')); 

Answer 10

There isn't really a 100% dynamic solution - I've just been trying to figure it out as well and due to different domain extensions (DTL) this task would be really difficult without actually parsing all these extensions and checking them each time:

.com vs .co.uk vs org.uk

The most reliable option is to define a constant (or database entry etc.) that stores the actual domain name and remove it from the $_SERVER['SERVER_NAME'] using substr()

defined("DOMAIN")
    || define("DOMAIN", 'mymaindomain.co.uk');



function getSubDomain() {

    if (empty($_SERVER['SERVER_NAME'])) {

        return null;

    }

    $subDomain = substr($_SERVER['SERVER_NAME'], 0, -(strlen(DOMAIN)));

    if (empty($subDomain)) {

        return null;

    }

    return rtrim($subDomain, '.');

}

Now if you're using this function under http://test.mymaindomain.co.uk it will give you test or if you have multiple sub-domain levels http://another.test.mymaindomain.co.uk you'll get another.test - unless of course you update the DOMAIN.

I hope this helps.

Answer 11

Using regex, string functions, parse_url() or their combinations it's not real solution. Just test any of proposed solutions with domain test.en.example.co.uk, there will no any correct result.

Correct solution is use package that parses domain with Public Suffix List. I recomend TLDExtract, here is sample code:

$extract = new LayerShifter\TLDExtract\Extract();

$result = $extract->parse('test.en.example.co.uk');
$result->getSubdomain(); // will return (string) 'test.en'
$result->getSubdomains(); // will return (array) ['test', 'en']
$result->getHostname(); // will return (string) 'example'
$result->getSuffix(); // will return (string) 'co.uk'

Answer 12

What I found the best and short solution is

array_shift(explode(".",$_SERVER['HTTP_HOST']));

Answer 13

For those who get 'Error: Strict Standards: Only variables should be passed by reference.' Use like this:

$env = (explode(".",$_SERVER['HTTP_HOST'])); $env = array_shift($env);

Answer 14

$domain = 'sub.dev.example.com';
$tmp = explode('.', $domain); // split into parts
$subdomain = current($tmp);
print($subdomain);     // prints "sub"

As seen in a previous question: How to get the first subdomain with PHP?

Answer 15

Simply

reset(explode(".", $_SERVER['HTTP_HOST']))

Answer 16

this is my solution, it works with the most common domains, you can fit the array of extensions as you need:

$SubDomain = explode('.', explode('|ext|', str_replace(array('.com', '.net', '.org'), '|ext|',$_SERVER['HTTP_HOST']))[0]);

Answer 17

I'm doing something like this

$url = https://en.example.com

$splitedBySlash = explode('/', $url);
$splitedByDot = explode('.', $splitedBySlash[2]);

$subdomain = $splitedByDot[0];

Answer 18

Suppose current url = sub.example.com

    $host = array_reverse(explode('.', $_SERVER['SERVER_NAME']));

    if (count($host) >= 3){
       echo "Main domain is = ".$host[1].".".$host[0]." & subdomain is = ".$host[2];
       // Main domain is = example.com & subdomain is = sub
    } else {
       echo "Main domain is = ".$host[1].".".$host[0]." & subdomain not found";
       // "Main domain is = example.com & subdomain not found";
    }

Answer 19

// For www.abc.en.example.com 
$host_Array = explode(".",$_SERVER['HTTP_HOST']); // Get HOST as array www, abc, en, example, com
array_pop($host_Array); array_pop($host_Array);   // Remove com and exmaple
array_shift($host_Array);                         // Remove www (Optional)
echo implode($host_Array, ".");                   // Combine array abc.en

Answer 20

I know I'm really late to the game, but here goes.

What I did was take the HTTP_HOST server variable ($_SERVER['HTTP_HOST']) and the number of letters in the domain (so for example.com it would be 11).

Then I used the substr function to get the subdomain. I did

$numberOfLettersInSubdomain = strlen($_SERVER['HTTP_HOST'])-12
$subdomain = substr($_SERVER['HTTP_HOST'], $numberOfLettersInSubdomain);

I cut the substring off at 12 instead of 11 because substrings start on 1 for the second parameter. So now if you entered test.example.com, the value of $subdomain would be test.

This is better than using explode because if the subdomain has a . in it, this will not cut it off.

Answer 21

if you are using drupal 7

this will help you:

global $base_path;
global $base_root;  
$fulldomain = parse_url($base_root);    
$splitdomain = explode(".", $fulldomain['host']);
$subdomain = $splitdomain[0];

Answer 22

$host = $_SERVER['HTTP_HOST'];
preg_match("/[^\.\/]+\.[^\.\/]+$/", $host, $matches);
$domain = $matches[0];
$url = explode($domain, $host);
$subdomain = str_replace('.', '', $url[0]);

echo 'subdomain: '.$subdomain.'<br />';
echo 'domain: '.$domain.'<br />';

Answer 23

From PHP 5.3 you can use strstr() with true parameter

echo strstr($_SERVER["HTTP_HOST"], '.', true); //prints en

Answer 24

function get_subdomain($url=""){
    if($url==""){
        $url = $_SERVER['HTTP_HOST'];
    }
    $parsedUrl = parse_url($url);
    $host = explode('.', $parsedUrl['path']);
    $subdomains = array_slice($host, 0, count($host) - 2 );
    return implode(".", $subdomains);
}

Answer 25

Try this...

$domain = 'en.example.com';
$tmp = explode('.', $domain);
$subdomain = current($tmp);
echo($subdomain);     // echo "en"

Answer 26

you can use this too

echo substr($_SERVER['HTTP_HOST'], 0, strrpos($_SERVER['HTTP_HOST'], '.', -5));

Answer 27

Maybe I'm late, but even though the post is old, just as I get to it, many others do.

Today, the wheel is already invented, with a library called php-domain-parser that is active, and in which two mechanisms can be used. One based on the Public Suffix List and one based on the IANA list.

Simple and effective, it allows us to create simple helpers that help us in our project, with the ability to know that the data is maintained, in a world in which the extensions and their variants are very changeable.

Many of the answers given in this post do not pass a battery of unit tests, in which certain current extensions and their variants with multiple levels are checked, and neither with the casuistry of domains with extended characters.

Maybe it serves you, as it served me.

Answer 28

<?php
// Your code here!

function get_domain($host) {
   $parts = explode('.',$host);
   $extension  = $parts[count($parts)-1];
   $name = $parts[count($parts)-2];
   return  $name.'.'.$extension;
}

echo get_domain("https://api.neoistone.com");
?>

Answer 29

If you only want what comes before the first period:

list($sub) = explode('.', 'en.example.com', 2);