How can I return the sum and average of an int array?

Question

I need to define two methods for returning the sum and average of an int array. The method defining is as follow:-

public int Sum(params int[] customerssalary)
{
           
         // I tried the following but it fails   return customerssalary.sum();
}

Another question is, how can I return the average of these int values?

Answer 1

customerssalary.Average();
customerssalary.Sum();

Answer 2

This is the way you should be doing it, and I say this because you are clearly new to C# and should probably try to understand how some basic stuff works!

public int Sum(params int[] customerssalary)
{
   int result = 0;

   for(int i = 0; i < customerssalary.Length; i++)
   {
      result += customerssalary[i];
   }

   return result;
}

with this Sum function, you can use this to calculate the average too...

public decimal Average(params int[] customerssalary)
{
   int sum = Sum(customerssalary);
   decimal result = (decimal)sum / customerssalary.Length;
   return result;
}

the reason for using a decimal type in the second function is because the division can easily return a non-integer result

---

Others have provided a Linq alternative which is what I would use myself anyway, but with Linq there is no point in having your own functions anyway. I have made the assumption that you have been asked to implement such functions as a task to demonstrate your understanding of C#, but I could be wrong.

Answer 3

Using ints.sum() has two problems:

• The variable is called customerssalary, not ints
• C# is case sensitive - the method is called Sum(), not sum().

Additionally, you'll need a using directive of

using System.Linq;

Once you've got the sum, you can just divide by the length of the array to get the average - you don't need to use Average() which will iterate over the array again.

int sum = customerssalary.Sum();
int average = sum / customerssalary.Length;

or as a double:

double average = ((double) sum) / customerssalary.Length;

Answer 4

Though the answers above all are different flavors of correct, I'd like to offer the following solution, which includes a null check:

decimal sum = (customerssalary == null) ? 0 : customerssalary.Sum();
decimal avg = (customerssalary == null) ? 0 : customerssalary.Average();

Answer 5

You have tried the wrong variable, ints is not the correct name of the argument.

public int Sum(params int[] customerssalary)
{
    return customerssalary.Sum();
}

public double Avg(params int[] customerssalary)
{
    return customerssalary.Average();
}

But do you think that these methods are really needed?

Answer 6

If you are using visual studio 2005 then

public void sumAverageElements(int[] arr)
{
     int size =arr.Length;
     int sum = 0;
     int average = 0;

     for (int i = 0; i < size; i++)
     {
          sum += arr[i];
     }

     average = sum / size; // sum divided by total elements in array

     Console.WriteLine("The Sum Of Array Elements Is : " + sum);
     Console.WriteLine("The Average Of Array Elements Is : " + average);
}

Answer 7

i refer so many results and modified my code its working

foreach (var rate in rateing)
                {
                    sum += Convert.ToInt32(rate.Rate);
                }
                if(rateing.Count()!= 0)
                {
                    float avg = (float)sum / (float)rateing.Count();
                    saloonusers.Rate = avg;
                }
                else
                {
                    saloonusers.Rate = (float)0.0;
                }