Regex number between 1 and 100

Question

I searched a lot and can't find the solution for this RegExp (I have to say I'm not very experienced in Reg. Expressions).

Regex = ^[1-9]?[0-9]{1}$|^100$

I would like to test a number between 1 and 100, excluding 0

Why not parse as number, and test for `(x >= 1) AND (x <= 100)`? — Martijn, Nov 20 '12 at 12:48
possible duplicate of [regular expression for csv numbers from 1 to 1000](http://stackoverflow.com/questions/12909137/regular-expression-for-csv-numbers-from-1-to-1000) — lanzz, Nov 20 '12 at 12:52
@Martijn: One reason is that ASP.NET webforms validation controls use offer RegEx-based validation. And this would not only ensure numeric input but a range for input of a percentage with a single validation control. — Daniel Przybylski, May 27 '15 at 22:29
@DanielPrzybylski: ASP.NET webform validation controls also include *RangeValidator*, which would be far more appropriate in this case. — Martijn, May 29 '15 at 09:37
I hit this question because I'm dealing with a 3rd party xml in a programming app, and there's no choice but to use regex. ASP.NET was an example, but not the only one so it doesn't matter if there's a better choice in THAT problem space. — loctrice, Apr 01 '16 at 16:46

Ankur · Accepted Answer · 2012-11-20T13:17:49.517

121

Try:

^[1-9][0-9]?$|^100$

Working fiddle

EDIT: IF you want to match 00001, 00000099 try

^0*(?:[1-9][0-9]?|100)$

FIDDLE

edited Nov 20 '12 at 13:17

answered Nov 20 '12 at 12:51

Ankur

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Interesting website Ankur, but I would love to found a list to choose the regex engine. – Gilles Quénot Nov 20 '12 at 12:56
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@sputnick I don't know about other engines but http://regexpal.com/ tests for javascript regex – Ankur Nov 20 '12 at 13:00
@GillesQuenot You can pick the regex flavour from the left side bar – Ben Lorantfy Feb 04 '20 at 19:19
This works for me, hence the upvote for Ankur. Thanks. – Nurhak Kaya Apr 13 '21 at 09:48

score 16 · Answer 2 · answered Jan 17 '18 at 10:44

16

For integers from 1 to 100 with no preceding 0 try:

^[1-9]$|^[1-9][0-9]$|^(100)$

For integers from 0 to 100 with no preceding 0 try:

^[0-9]$|^[1-9][0-9]$|^(100)$

Regards

answered Jan 17 '18 at 10:44

bytepan

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Mercury · Answer 3 · 2022-02-08T21:01:20.267

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Here are very simple regex's to understand (verified, and no preceding 0)

Between 0 to 100 (Try it here):

^(0|[1-9][0-9]?|100)$

Between 1 to 100 (Try it here):

^([1-9][0-9]?|100)$

edited Feb 08 '22 at 21:01

answered Jul 22 '19 at 08:00

Mercury

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score 10 · Answer 4 · edited Jul 30 '17 at 06:58

10

Try it, This will work more efficiently.. 1. For number ranging 00 - 99.99 (decimal inclusive)

^([0-9]{1,2}){1}(\.[0-9]{1,2})?$

Working fiddle link

https://regex101.com/r/d1Kdw5/1/

2.For number ranging 1-100(inclusive) with no preceding 0.

(?:\b|-)([1-9]{1,2}[0]?|100)\b

Working Fiddle link

http://regex101.com/r/mN1iT5/6

edited Jul 30 '17 at 06:58

Tim Elsass

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answered Aug 14 '14 at 10:24

Ved

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Check it on fiddle. Link is there. – Ved Aug 14 '14 at 10:38
I have edited the expression. There was slight mistake. Check it now. – Ved Aug 14 '14 at 10:45
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I think it would be more helpful for the OP and further visitor, when you add some explanation to your intension. – Reporter Aug 14 '14 at 11:02
Hmm. Still not - it won't match 100 and will match (for example) 11.33 – GHC Aug 14 '14 at 14:09
This expression is for numbers 1 to 99 including decimal numbers. – Ved Aug 18 '14 at 04:24
In its current form, your regex matches numbers in the range **00 to 99.99**. The OP said he wanted to match numbers from **1 to 100** (inclusive), and he didn't say anything about decimals. I'm pretty sure he didn't want the leading zeroes, either. – Alan Moore Aug 18 '14 at 06:51
Thank you @AlanMoore for suggestion. I have edited my expression. Hope this will as per your expectation. – Ved Aug 18 '14 at 07:43
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...and then some! Correct **and** creative; gets an upvote from me. – Alan Moore Aug 18 '14 at 08:29
the first regex doesn't match the number 20 – Tim Elsass Jul 29 '17 at 17:37
@Ved I have small request, can I have regular expression in between 1 to 100, accept decimal value of maximum two. example 0.24,1.99 ,9.99 99.99 are valid result. Invalid are 00.24, 000.25, 0.245, 999.000 are invalid – kiran Jul 16 '18 at 23:29

score 3 · Answer 5 · answered Nov 20 '12 at 12:57

If one assumes he really needs regexp - which is perfectly reasonable in many contexts - the problem is that the specific regexp variety needs to be specified. For example:

egrep '^(100|[1-9]|[1-9][0-9])$'
grep -E '^(100|[1-9]|[1-9][0-9])$'

work fine if the (...|...) alternative syntax is available. In other contexts, they'd be backslashed like $...\|...$

Ωmega · Answer 6 · 2012-11-20T13:04:32.427

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There are many options how to write a regex pattern for that

^(?:(?!0)\d{1,2}|100)$
^(?:[1-9]\d?|100)$
^(?!0)(?=100$|..$|.$)\d+$

edited Nov 20 '12 at 13:04

answered Nov 20 '12 at 12:58

Ωmega

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score 1 · Answer 7 · edited Mar 24 '20 at 10:10

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I use for this angular 6

try this.

^([0-9]\.[0-9]{1}|[0-9]\.[0-9]{2}|\.[0-9]{2}|[1-9][0-9]\.[0-9]{1}|[1-9][0-9]\.[0-9]{2}|[0-9][0-9]|[1-9][0-9]\.[0-9]{2})$|^([0-9]|[0-9][0-9]|[0-99])$|^100$

it's validate 0.00 - 100. with two decimal places.

hope this will help

<input matInput [(ngModel)]="commission" type="number" max="100" min="0" name="rateInput" pattern="^(\.[0-9]{2}|[0-9]\.[0-9]{2}|[0-9][0-9]|[1-9][0-9]\.[0-9]{2})$|^([0-9]|[0-9][0-9]|[0-99])$|^100$" required #rateInput2="ngModel"><span>%</span><br>

Number should be between 0 and 100

edited Mar 24 '20 at 10:10

Werner Henze

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answered Mar 24 '20 at 09:41

aruna

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more accurate one ^([0-9]\.[0-9]{1}|[0-9]\.[0-9]{2}|\.[0-9]{2}|[1-9][0-9]\.[0-9]{1}|[1-9][0-9]\.[0-9]{2}|[0-9][0-9]|[1-9][0-9]\.[0-9]{2})$|^([0-9]|[0-9][0-9]|[0-99])$|^100$ – aruna Mar 24 '20 at 09:42
This works perfectly for me where the answer's expression allows for 3+ decimal places. – TaeKwonJoe Aug 10 '21 at 01:35

score 0 · Answer 8 · answered Aug 30 '19 at 18:31

0

Regular Expression for 0 to 100 with the decimal point.

^100(\.[0]{1,2})?|([0-9]|[1-9][0-9])(\.[0-9]{1,2})?$

answered Aug 30 '19 at 18:31

Radadiya Nikunj

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Aleksandar · Answer 9 · 2019-09-08T08:52:07.853

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Just for the sake of delivering the shortest solution, here is mine:

^([1-9]\d?|100)$

working fiddle

edited Sep 08 '19 at 08:52

answered Sep 08 '19 at 08:06

Aleksandar

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score 0 · Answer 10 · edited Nov 19 '19 at 07:32

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1 - 1000 with leading 0's

/^0*(?:[1-9][0-9][0-9]?|[1-9]|1000)$/;

it should not accept 0, 00, 000, 0000.

it should accept 1, 01, 001, 0001

edited Nov 19 '19 at 07:32

Gaslan

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answered Nov 19 '19 at 06:34

Avik Chanda

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Juzbird · Answer 11 · 2023-04-09T13:40:23.180

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The simplest one

^([1-9][0-9]?|100)$

Edit

The explanation detail
[1-9] matches between 1 and 9
[0-9]? is optional one between 0 and 9
| means OR
100 means 100

The combination matches between 1 and 100.

edited Apr 09 '23 at 13:40

answered Apr 07 '23 at 00:16

Juzbird

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Explaining it would make it a better answer – Rohit Gupta Apr 07 '23 at 12:30
Please add some explanation to your code rather than posting only code. – user67275 Apr 07 '23 at 22:25

score -1 · Answer 12 · edited Feb 04 '20 at 19:05

-1

between 0 and 100

/^(\d{1,2}|100)$/

or between 1 and 100

/^([1-9]{1,2}|100)$/

edited Feb 04 '20 at 19:05

abSiddique

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answered Feb 02 '18 at 17:34

figuarnieri

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This isn't a very good answer. The first version matches 0, which the question says not to match. The second version doesn't match two-digit numbers. – Kenster Feb 02 '18 at 18:52

score -6 · Answer 13 · edited Feb 17 '16 at 02:07

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This is very simple logic, So no need of regx.

Instead go for using ternary operator

var num = 89;
var isValid = (num <=  100 && num > 0 ) ? true : false;

It will do the magic for you!!

edited Feb 17 '16 at 02:07

wogsland

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answered Aug 18 '14 at 09:09

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Except for where you need a regex. For instance, say an xml template that is predefined, where the only way to limit input is by putting a regex in the template. Then there's no magic here. – loctrice Apr 01 '16 at 16:42

Regex number between 1 and 100

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