CodeIgniter optional parameter

Question

I'm trying to use routing in CI to create a signup form

signup is re-routed to user/signup

But my signup function can contain a paramater: function signup($type = 1)

How can I make this optional via routing? I tried $route['signup/?(:num)'] = 'user/signup/$1';, but when going to /signup I'm getting a 404, only /signup/1/ works.

Wesley Murch · Accepted Answer · 2013-01-06T15:03:28.513

26

The clearest way to express this would probably be to declare both routes:

$route['signup'] = "user/signup";
$route['signup/(:num)'] = "user/signup/$1";

edited Jan 06 '13 at 15:03

answered Jan 06 '13 at 14:52

Wesley Murch

101,186
37
194
228

That works fine, didn't think of it, I was trying to figure out how to make it optional. Thanks! – woutr_be Jan 06 '13 at 14:54
The edit doesn't seem to work, it doesn't seem to send the parameter with it – woutr_be Jan 06 '13 at 15:02
Thanks, I think I prefer your first solution, easier to read / remember. – woutr_be Jan 06 '13 at 15:04
@Wesley Thanks! This little tip saved a whole lot of time! – Kanchana Randika May 02 '17 at 06:05

score 24 · Answer 2 · answered Apr 18 '16 at 11:44

24

For anyone else reading this in due course - I believe the answer should be $route['signup/?(:num)?'] which makes the number optional as well. I had similar issues on something else.

answered Apr 18 '16 at 11:44

Ukuser32

2,147
2
22
32

score 8 · Answer 3 · answered Aug 26 '17 at 22:51

The trouble with @Ukuser32's answer is that it allows for URIs like signup69 to be accepted, which in this case might be innocuous but in the general case is undesirable. Just put the slash in with the captured :num

$route['signup(/:num)?'] = "user/signup$1"

And note that if you have multiple optional segments, then you will need to nest them....

CodeIgniter optional parameter

3 Answers3

Linked