Update MongoDB field using value of another field

Question

In MongoDB, is it possible to update the value of a field using the value from another field? The equivalent SQL would be something like:

UPDATE Person SET Name = FirstName + ' ' + LastName

And the MongoDB pseudo-code would be:

db.person.update( {}, { $set : { name : firstName + ' ' + lastName } );

Answer 1

The best way to do this is in version 4.2+ which allows using the aggregation pipeline in the update document and the updateOne, updateMany, or update(deprecated in most if not all languages drivers) collection methods.

MongoDB 4.2+

Version 4.2 also introduced the $set pipeline stage operator, which is an alias for $addFields. I will use $set here as it maps with what we are trying to achieve.

db.collection.<update method>(
    {},
    [
        {"$set": {"name": { "$concat": ["$firstName", " ", "$lastName"]}}}
    ]
)

Note that square brackets in the second argument to the method specify an aggregation pipeline instead of a plain update document because using a simple document will not work correctly.

MongoDB 3.4+

In 3.4+, you can use $addFields and the $out aggregation pipeline operators.

db.collection.aggregate(
    [
        { "$addFields": { 
            "name": { "$concat": [ "$firstName", " ", "$lastName" ] } 
        }},
        { "$out": <output collection name> }
    ]
)

Note that this does not update your collection but instead replaces the existing collection or creates a new one. Also, for update operations that require "typecasting", you will need client-side processing, and depending on the operation, you may need to use the find() method instead of the .aggreate() method.

MongoDB 3.2 and 3.0

The way we do this is by $projecting our documents and using the $concat string aggregation operator to return the concatenated string. You then iterate the cursor and use the $set update operator to add the new field to your documents using bulk operations for maximum efficiency.

Aggregation query:

var cursor = db.collection.aggregate([ 
    { "$project":  { 
        "name": { "$concat": [ "$firstName", " ", "$lastName" ] } 
    }}
])

MongoDB 3.2 or newer

You need to use the bulkWrite method.

var requests = [];
cursor.forEach(document => { 
    requests.push( { 
        'updateOne': {
            'filter': { '_id': document._id },
            'update': { '$set': { 'name': document.name } }
        }
    });
    if (requests.length === 500) {
        //Execute per 500 operations and re-init
        db.collection.bulkWrite(requests);
        requests = [];
    }
});

if(requests.length > 0) {
     db.collection.bulkWrite(requests);
}

MongoDB 2.6 and 3.0

From this version, you need to use the now deprecated Bulk API and its associated methods.

var bulk = db.collection.initializeUnorderedBulkOp();
var count = 0;

cursor.snapshot().forEach(function(document) { 
    bulk.find({ '_id': document._id }).updateOne( {
        '$set': { 'name': document.name }
    });
    count++;
    if(count%500 === 0) {
        // Excecute per 500 operations and re-init
        bulk.execute();
        bulk = db.collection.initializeUnorderedBulkOp();
    }
})

// clean up queues
if(count > 0) {
    bulk.execute();
}

MongoDB 2.4

cursor["result"].forEach(function(document) {
    db.collection.update(
        { "_id": document._id }, 
        { "$set": { "name": document.name } }
    );
})

Answer 2

You should iterate through. For your specific case:

db.person.find().snapshot().forEach(
    function (elem) {
        db.person.update(
            {
                _id: elem._id
            },
            {
                $set: {
                    name: elem.firstname + ' ' + elem.lastname
                }
            }
        );
    }
);

Answer 3

Apparently there is a way to do this efficiently since MongoDB 3.4, see styvane's answer.

---

Obsolete answer below

You cannot refer to the document itself in an update (yet). You'll need to iterate through the documents and update each document using a function. See this answer for an example, or this one for server-side eval().

Answer 4

For a database with high activity, you may run into issues where your updates affect actively changing records and for this reason I recommend using snapshot()

db.person.find().snapshot().forEach( function (hombre) {
    hombre.name = hombre.firstName + ' ' + hombre.lastName; 
    db.person.save(hombre); 
});

http://docs.mongodb.org/manual/reference/method/cursor.snapshot/

Answer 5

Starting Mongo 4.2, db.collection.update() can accept an aggregation pipeline, finally allowing the update/creation of a field based on another field:

// { firstName: "Hello", lastName: "World" }
db.collection.updateMany(
  {},
  [{ $set: { name: { $concat: [ "$firstName", " ", "$lastName" ] } } }]
)
// { "firstName" : "Hello", "lastName" : "World", "name" : "Hello World" }

• The first part {} is the match query, filtering which documents to update (in our case all documents).

• The second part [{ $set: { name: { ... } }] is the update aggregation pipeline (note the squared brackets signifying the use of an aggregation pipeline). $set is a new aggregation operator and an alias of $addFields.

Answer 6

Regarding this answer, the snapshot function is deprecated in version 3.6, according to this update. So, on version 3.6 and above, it is possible to perform the operation this way:

db.person.find().forEach(
    function (elem) {
        db.person.update(
            {
                _id: elem._id
            },
            {
                $set: {
                    name: elem.firstname + ' ' + elem.lastname
                }
            }
        );
    }
);

Answer 7

update() method takes aggregation pipeline as parameter like

db.collection_name.update(
  {
    // Query
  },
  [
    // Aggregation pipeline
    { "$set": { "id": "$_id" } }
  ],
  {
    // Options
    "multi": true // false when a single doc has to be updated
  }
)

The field can be set or unset with existing values using the aggregation pipeline.

Note: use $ with field name to specify the field which has to be read.

Answer 8

I tried the above solution but I found it unsuitable for large amounts of data. I then discovered the stream feature:

MongoClient.connect("...", function(err, db){
    var c = db.collection('yourCollection');
    var s = c.find({/* your query */}).stream();
    s.on('data', function(doc){
        c.update({_id: doc._id}, {$set: {name : doc.firstName + ' ' + doc.lastName}}, function(err, result) { /* result == true? */} }
    });
    s.on('end', function(){
        // stream can end before all your updates do if you have a lot
    })
})

Answer 9

Here's what we came up with for copying one field to another for ~150_000 records. It took about 6 minutes, but is still significantly less resource intensive than it would have been to instantiate and iterate over the same number of ruby objects.

js_query = %({
  $or : [
    {
      'settings.mobile_notifications' : { $exists : false },
      'settings.mobile_admin_notifications' : { $exists : false }
    }
  ]
})

js_for_each = %(function(user) {
  if (!user.settings.hasOwnProperty('mobile_notifications')) {
    user.settings.mobile_notifications = user.settings.email_notifications;
  }
  if (!user.settings.hasOwnProperty('mobile_admin_notifications')) {
    user.settings.mobile_admin_notifications = user.settings.email_admin_notifications;
  }
  db.users.save(user);
})

js = "db.users.find(#{js_query}).forEach(#{js_for_each});"
Mongoid::Sessions.default.command('$eval' => js)

Answer 10

With MongoDB version 4.2+, updates are more flexible as it allows the use of aggregation pipeline in its update, updateOne and updateMany. You can now transform your documents using the aggregation operators then update without the need to explicity state the $set command (instead we use $replaceRoot: {newRoot: "$$ROOT"})

Here we use the aggregate query to extract the timestamp from MongoDB's ObjectID "_id" field and update the documents (I am not an expert in SQL but I think SQL does not provide any auto generated ObjectID that has timestamp to it, you would have to automatically create that date)

var collection = "person"

agg_query = [
    {
        "$addFields" : {
            "_last_updated" : {
                "$toDate" : "$_id"
            }
        }
    },
    {
        $replaceRoot: {
            newRoot: "$$ROOT"
        } 
    }
]

db.getCollection(collection).updateMany({}, agg_query, {upsert: true})

Answer 11

(I would have posted this as a comment, but couldn't)

For anyone who lands here trying to update one field using another in the document with the c# driver... I could not figure out how to use any of the UpdateXXX methods and their associated overloads since they take an UpdateDefinition as an argument.

// we want to set Prop1 to Prop2
class Foo { public string Prop1 { get; set; } public string Prop2 { get; set;} } 

void Test()
{ 
     var update = new UpdateDefinitionBuilder<Foo>();
     update.Set(x => x.Prop1, <new value; no way to get a hold of the object that I can find>)
}

As a workaround, I found that you can use the RunCommand method on an IMongoDatabase (https://docs.mongodb.com/manual/reference/command/update/#dbcmd.update).

var command = new BsonDocument
        {
            { "update", "CollectionToUpdate" },
            { "updates", new BsonArray 
                 { 
                       new BsonDocument
                       {
                            // Any filter; here the check is if Prop1 does not exist
                            { "q", new BsonDocument{ ["Prop1"] = new BsonDocument("$exists", false) }}, 
                            // set it to the value of Prop2
                            { "u", new BsonArray { new BsonDocument { ["$set"] = new BsonDocument("Prop1", "$Prop2") }}},
                            { "multi", true }
                       }
                 }
            }
        };

 database.RunCommand<BsonDocument>(command);

Answer 12

MongoDB 4.2+ Golang

result, err := collection.UpdateMany(ctx, bson.M{},
    mongo.Pipeline{
        bson.D{{"$set",
          bson.M{"name": bson.M{"$concat": []string{"$lastName", " ", "$firstName"}}}
    }},
)