indexOf method in an object array?

Question

How can I simply and directly find the index within an array of objects meeting some condition?

For example, given this input:

var hello = { hello: 'world', foo: 'bar'};
var qaz = { hello: 'stevie', foo: 'baz'}

var myArray = [];
myArray.push(hello, qaz);

How can I search myArray to find the index of the element whose hello property equals 'stevie' (in this case, the result should be 1)?

Answer 1

I think you can solve it in one line using the map function:

const pos = myArray.map(e => e.hello).indexOf('stevie');

Answer 2

Array.prototype.findIndex is supported in all browsers other than IE (non-edge). But the polyfill provided is nice.

var indexOfStevie = myArray.findIndex(i => i.hello === "stevie");

The solution with map is okay. But you are iterating over the entire array every search. That is only the worst case for findIndex which stops iterating once a match is found.

---

There's not really a concise way (when devs had to worry about IE8), but here's a common solution:

var searchTerm = "stevie",
    index = -1;
for(var i = 0, len = myArray.length; i < len; i++) {
    if (myArray[i].hello === searchTerm) {
        index = i;
        break;
    }
}

or as a function:

function arrayObjectIndexOf(myArray, searchTerm, property) {
    for(var i = 0, len = myArray.length; i < len; i++) {
        if (myArray[i][property] === searchTerm) return i;
    }
    return -1;
}
arrayObjectIndexOf(arr, "stevie", "hello"); // 1

Just some notes:

1. Don't use for...in loops on arrays
2. Be sure to break out of the loop or return out of the function once you've found your "needle"
3. Be careful with object equality

For example,

var a = {obj: 0};
var b = [a];
b.indexOf({obj: 0}); // -1 not found

Answer 3

In ES2015, this is pretty easy:

myArray.map(x => x.hello).indexOf('stevie')

or, probably with better performance for larger arrays:

myArray.findIndex(x => x.hello === 'stevie')

Answer 4

var idx = myArray.reduce( function( cur, val, index ){

    if( val.hello === "stevie" && cur === -1 ) {
        return index;
    }
    return cur;

}, -1 );

Answer 5

I like Pablo's answer, but Array#indexOf and Array#map don't work on all browsers. Underscore will use native code if it's available, but has fallbacks as well. Plus it has the pluck method for doing exactly what Pablo's anonymous map method does.

var idx = _.chain(myArray).pluck("hello").indexOf("Stevie").value();

Answer 6

Or prototype it :

Array.prototype.indexOfObject = function arrayObjectIndexOf(property, value) {
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][property] === value) return i;
    }
    return -1;
}

myArr.indexOfObject("name", "stevie");

Answer 7

While, most other answers here are valid. Sometimes, it's best to just make a short simple function near where you will use it.

// indexOf wrapper for the list of objects
function indexOfbyKey(obj_list, key, value) {
    for (index in obj_list) {
        if (obj_list[index][key] === value) return index;
    }
    return -1;
}
// Find the string in the list (default -1)
var test1 = indexOfbyKey(object_list, 'name', 'Stevie');
var test2 = indexOfbyKey(object_list, 'last_name', 'some other name');

It depends on what is important to you. It might save lines of code and be very clever to use a one-liner, or to put a generic solution somewhere that covers various edge cases. But sometimes it's better to just say: "here I did it like this" rather than leave future developers to have extra reverse engineering work. Especially if you consider yourself "a newbie" like in your question.

Answer 8

Brief

myArray.indexOf('stevie','hello')

Use Cases :

  /*****NORMAL****/  
[2,4,5].indexOf(4) ;//OUTPUT 1
 /****COMPLEX*****/
 [{slm:2},{slm:4},{slm:5}].indexOf(4,'slm');//OUTPUT 1
 //OR
 [{slm:2},{slm:4},{slm:5}].indexOf(4,function(e,i){
   return e.slm;
});//OUTPUT 1
/***MORE Complex**/
[{slm:{salat:2}},{slm:{salat:4}},{slm:{salat:5}}].indexOf(4,function(e,i){
   return e.slm.salat;
});//OUTPUT 1

API :

    Array.prototype.indexOfOld=Array.prototype.indexOf

    Array.prototype.indexOf=function(e,fn){
      if(!fn){return this.indexOfOld(e)}
      else{ 
       if(typeof fn ==='string'){var att=fn;fn=function(e){return e[att];}}
        return this.map(fn).indexOfOld(e);
      }
    };

Answer 9

If your object is the same object of the ones you are using within the array, you should be able to get the index of the Object in the same way you do as if it was a string.

var hello = {
    hello: 'world',
    foo: 'bar'
};
var qaz = {
    hello: 'stevie',
    foo: 'baz'
}

var qazCLONE = { // new object instance and same structure
    hello: 'stevie',
    foo: 'baz'
}

var myArray = [hello,qaz];

myArray.indexOf(qaz) // should return 1
myArray.indexOf(qazCLONE) // should return -1

Answer 10

I compared several methods and received a result with the fastest way to solve this problem. It's a for loop. It's 5+ times faster than any other method.

Here is the test's page: https://jsbench.me/9hjewv6a98

Answer 11

you can use findIndex() method:

cosnt myIndex=myArray.findIndex(el=>el.hello==='stevie')

if myIndex < 0 that means is not exist

Answer 12

I did some performance testing of various answers here, which anyone can run them self:

https://jsperf.com/find-index-of-object-in-array-by-contents

Based on my initial tests in Chrome, the following method (using a for loop set up inside a prototype) is the fastest:

Array.prototype.indexOfObject = function (property, value) {
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][property] === value) return i;
    }
    return -1;
}

myArray.indexOfObject("hello", "stevie");

This code is a slightly modified version of Nathan Zaetta's answer.

In the performance benchmarks I tried it with both the target being in the middle (index 500) and very end (index 999) of a 1000 object array, and even if I put the target in as the very last item in the array (meaning that it it has to loop through every single item in the array before it's found) it still ends up the fastest.

This solution also has the benefit of being one of the most terse for repeatedly executing, since only the last line needs to be repeated:

myArray.indexOfObject("hello", "stevie");

Answer 13

array.filter(function(item, indx, arr){ return(item.hello === 'stevie'); })[0];

Mind the [0].

It is proper to use reduce as in Antonio Laguna's answer.

Apologies for the brevity...

Answer 14

Try this:

console.log(Object.keys({foo:"_0_", bar:"_1_"}).indexOf("bar"));

https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Object/keys

Answer 15

simple:

myArray.indexOf(myArray.filter(function(item) {
    return item.hello == "stevie"
})[0])

Answer 16

You can use a native and convenient function Array.prototype.findIndex() basically:

The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.

Just a note it is not supported on Internet Explorer, Opera and Safari, but you can use a Polyfill provided in the link below.

More information:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex

var hello = {
  hello: 'world',
  foo: 'bar'
};
var qaz = {
  hello: 'stevie',
  foo: 'baz'
}

var myArray = [];
myArray.push(hello, qaz);

var index = myArray.findIndex(function(element, index, array) {
  if (element.hello === 'stevie') {
    return true;
  }
});
alert('stevie is at index: ' + index);

Answer 17

If you are only interested into finding the position see @Pablo's answer.

pos = myArray.map(function(e) { return e.hello; }).indexOf('stevie');

However, if you are looking forward to finding the element (i.e. if you were thinking of doing something like this myArray[pos]), there is a more efficient one-line way to do it, using filter.

element = myArray.filter((e) => e.hello === 'stevie')[0];

See perfomance results (~ +42% ops/sec): http://jsbench.github.io/#7fa01f89a5dc5cc3bee79abfde80cdb3

Answer 18

I have made a generic function to check the below is the code & works for any object

function indexOfExt(list, item) {
    var len = list.length;

    for (var i = 0; i < len; i++) {
        var keys = Object.keys(list[i]);
        var flg = true;
        for (var j = 0; j < keys.length; j++) {
            var value = list[i][keys[j]];
            if (item[keys[j]] !== value) {
                flg = false;
            }
        }
        if (flg == true) {
            return i;
        }
    }
    return -1;
}

var items = [{ "hello": 'world', "foo": 'bar' }];
var selectedItem = { "hello": 'world', "foo": 'bar' };
alert(items.indexOf(selectedItem));
alert(indexOfExt(items, selectedItem));

The first alert will return -1 (means match not found) & second alert will return 0 (means match found).

Answer 19

Use _.findIndex from underscore.js library

Here's the example _.findIndex([{a:1},{a: 2,c:10},{a: 3}], {a:2,c:10}) //1

Answer 20

Using the ES6 findIndex method, without lodash or any other libraries, you can write:

function deepIndexOf(arr, obj) {
  return arr.findIndex(function (cur) {
    return Object.keys(obj).every(function (key) {
      return obj[key] === cur[key];
    });
  });
}

This will compare the immediate properties of the object, but not recurse into the properties.

If your implementation doesn't provide findIndex yet (most don't), you can add a light polyfill that supports this search:

function deepIndexOf(arr, obj) {
  function findIndex = Array.prototype.findIndex || function (pred) {
    for (let i = 0; i < this.length; ++i) {
      if (pred.call(this, this[i], i)) {
        return i;
      }
    }

    return -1;
  }

  return findIndex.call(arr, function (cur) {
    return Object.keys(obj).every(function (key) {
      return obj[key] === cur[key];
    });
  });
}

(from my answer on this dupe)

Answer 21

Furthor of @Monika Garg answer, you can use findIndex() (There is a polyfill for unsupprted browsers).

I saw that people downvoted this answer, and I hope that they did this because of the wrong syntax, because on my opinion, this is the most elegant way.

The findIndex() method returns an index in the array, if an element in the array satisfies the provided testing function. Otherwise -1 is returned.

For example:

var hello = {
  hello: 'world',
  foo: 'bar'
};
var qaz = {
  hello: 'stevie',
  foo: 'baz'
}

var myArray = [];
myArray.push(hello,qaz);

var index = myArray.findIndex(function(element) {
  return element.hello == 'stevie';
});

alert(index);

Answer 22

See this example: http://jsfiddle.net/89C54/

for (i = 0; i < myArray.length; i++) {
    if (myArray[i].hello === 'stevie') {
        alert('position: ' + i);
        return;
    }
}

It starts to count with zero.

Answer 23

This is the way to find the object's index in array

    var myArray = [{  hello: 'world',
        foo: 'bar'
    },{
        hello: 'stevie',
        foo: 'baz'
    }];



    for (i = 0; i < myArray.length; i++) {
        if (myArray[i].hello === 'stevie') {
            alert('position: ' + i);
            return;
        }
    }

Answer 24

This works without custom code

var arr, a, found;
arr = [{x: 1, y: 2}];
a = {x: 1, y: 2};
found = JSON.stringify(arr).indexOf(JSON.stringify(a)) > - 1;
// found === true

Note: this does not give the actual index, it only tells if your object exists in the current data structure

Answer 25

You can simply use

const someId = 2;
const array = [{id:1}, {id:2}, {id:3}];
const index = array.reduce((i, item, index) => item.id === someId ? index : i, -1);
alert('someId ' + someId + ' is at index ' + index);

No underscore, no for, just a reduce.

Answer 26

var hello = {hello: "world",  foo: "bar"};
var qaz = {hello: "stevie", foo: "baz"};
var myArray = [];
myArray.push(hello,qaz);

function indexOfObject( arr, key, value   ) {
    var j = -1;
    var result = arr.some(function(obj, i) { 
        j++;
        return obj[key] == value;
    })

    if (!result) {
        return -1;
    } else {
        return j;
    };
}

alert(indexOfObject(myArray,"hello","world"));

Answer 27

Most answers response here do not resolve all cases. I found this solution better:

const isInarray = myArr.filter((obj) => obj.hello === 'stevie' && obj.foo === 'baz').length > 0;
if (!isInArray) {
 ....
}

Answer 28

You can create your own prototype to do this:

something like:

Array.prototype.indexOfObject = function (object) {
    for (var i = 0; i < this.length; i++) {
        if (JSON.stringify(this[i]) === JSON.stringify(object))
            return i;
    }
}

Answer 29

I will prefer to use findIndex() method:

 var index = myArray.findIndex('hello','stevie');

index will give you the index number.