Android - ListView - performItemClick

Question

I'm facing some difficults when I try to use the performItemClick funcion of the ListView.

All I want to do is to perform a click programatically in the first item of the list.

How can I do that? I looked up that function in the documentation, but I didn't really understand its parameters.

I tried something like:

 myListView.performItemClick(myListView.getChildAt(0), 0, myListView.getChildAt(0).getId());

But it didn't work (myListView.getChildAt(0) returns null)

Thank you in advance!

are you solve this problem ?If yes please the write answer.Because I am stuck with same problem.Thanks in advance. — Sachin D, Apr 30 '12 at 09:48
use a delay for use myListView.performItemClick() after myListView.setAdapter(adapter); — Ali Bagheri, Jan 06 '20 at 15:02

score 66 · Answer 1 · edited Jun 03 '13 at 09:18

66

mList.performItemClick(
        mList.getAdapter().getView(mActivePosition, null, null),
        mActivePosition,
        mList.getAdapter().getItemId(mActivePosition));

Where mActivePosition is your click position! All the best! :)

edited Jun 03 '13 at 09:18

sulai

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answered Apr 29 '13 at 11:54

Arun Jose

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13

I got best results when using `mList.getChildAt(mActivePosition)` as first parameter. – sulai Jun 03 '13 at 09:24
where i want to put this code?in setOnItemClickListener? – tej shah Jul 31 '15 at 12:57
1

@sulai, I think it should be `mList.getChildAt(mList.getHeaderViewsCount()+mActivePosition)` – Ninja Aug 22 '16 at 07:02
This should be after `setOnItemClickListener(...)`(if any).. common thing, yet I succeeded to miss it. – Prabs Jun 20 '17 at 10:51
this does not set the item highlihted if chocieMode is `singleChoice` – ibubi Jun 15 '20 at 15:46

score 29 · Answer 2 · answered Feb 03 '12 at 23:42

This worked for me.

listView.performItemClick(
    listView.getAdapter().getView(position, null, null), position, position);

use the adapter to get the view for the position of the item. The other 2 parameters I didn't want so I left them null. Leaving convertView null causes the adapter to render a new view. It's a performance issue but since this is only happening once in a while it wont have much effect. I don't need to specify the parent for anything because I'm not using it.

position is just the spot where your item is located. Additionally these 2 lines of code before your performItemClick create the illusion of having the list item selected. They also ensure the appropriate item is on the screen.

listView.requestFocusFromTouch();
listView.setSelection(position);

Shouldn't the last argument in performItemClick be listView.getAdapter().getItemId(position)? — raydowe, Nov 08 '12 at 22:54

score 16 · Answer 3 · answered Jun 13 '13 at 19:04

16

This works best for me. Run this on the main thread.

new Handler().post(new Runnable() {
    @Override
    public void run() {
        mList.performItemClick(
                mList.getChildAt(mActivePosition),
                mActivePosition,
                mList.getAdapter().getItemId(mActivePosition));
    }
});

This is similar to Arun Jose's answer, but it will queue a message to the main thread to give the ListView some time to initiate.

answered Jun 13 '13 at 19:04

sulai

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I will use your answer in another answer as comments don't format code :/. Thanks for the handler – denispyr Jun 26 '13 at 21:19
1

I don't know why but after orientation change this method does not work – Jongz Puangput Jun 10 '14 at 13:53
@JongzPuangput One possible cause: your `ListView` has been re-created and you need to get a new reference for it after orientation change: `mList = getView().findViewById(R.id.list);` – sulai Feb 20 '15 at 10:05
its woring for me.. I did use BaseAdapter.. Thankx – Amitabha Biswas Jun 21 '15 at 12:43
2

This will not always work, since ViewGroup#getChildAt(int index) will work only on the currently visible items on screen, use getView(position, null, null) instead! – Maxim Rahlis Jul 14 '15 at 12:24

score 5 · Answer 4 · answered Jan 25 '12 at 10:38

5

I tried the code below and it worked.

getListView().performItemClick(null, 0, getListAdapter().getItemId(0));

The first parameter (view) can be null.

answered Jan 25 '12 at 10:38

Blehi

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while @Arun Jose 's code work fine, setting the first param to null, as proposed here, crashes the app – denispyr Jun 26 '13 at 21:04
Good question. For me it is working properly. Please check the LogCat. Maybe you will find the reason. – Blehi Jun 28 '13 at 08:04
This works for me too. I also found that the id seems to be ignored. – stevehs17 Feb 15 '18 at 00:13

score 4 · Answer 5 · answered Jan 01 '13 at 20:48

4

I went with

listView.getAdapter().getView(position, null, null).performClick();

answered Jan 01 '13 at 20:48

koljaTM

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score 2 · Answer 6 · edited Jun 13 '17 at 01:12

When using Listview (simple array adapter or custom adapter) define listview and other finally make perform click.

For example:

 //At onCreate function:

lv = (ListView) findViewById(R.id.listView);
        lv.setAdapter(new CustomAdapter(List_item.this, list, images));


lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id)    {
// on click function works
    }
}


int position = 0;
lv.performItemClick(lv.getAdapter().getView(position, null, null), position, lv.getAdapter().getItemId(position));

Note: After creating the setOnItemClickListener only you should call perform click. Otherwise, it will not correctly.

score 1 · Answer 7 · answered Apr 15 '15 at 05:40

this may be old but this may help :

lvList.performItemClick(null, index, lvList.getItemIdAtPosition(index) );

NOTE : the first param is null and will still work, if you have a custom adapter, convertView will be filled with custom layout and view and such.

-cheers / happy codings.

score 1 · Answer 8 · edited May 28 '15 at 14:07

1

mList.performItemClick(
    mList.getChildAt(mActivePosition),
    mActivePosition,
    mList.getAdapter().getItemId(mActivePosition));

where mActivePosition is the position of the child view in List View.

edited May 28 '15 at 14:07

Benoit Esnard

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answered May 28 '15 at 13:30

nick9999

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3

score 0 · Answer 9 · answered Jun 26 '13 at 21:25

Using the code @sulal proposed, you may place it in onLoadFinished, if you use a LoaderManager. Eg something like

@Override
public void onLoadFinished(Loader<Cursor> loader, Cursor data) {
    //....
    // mSelectedId keeps the currently selected id
    // INVID is an invalid value
    if (mSelectedId == INVID) { // nothing selected
        // sulal's code
        new Handler().post(new Runnable() {
            @Override
            public void run() {
                mList.performItemClick(
                        mList.getChildAt(mActivePosition),
                        mActivePosition,
                        mList.getAdapter().getItemId(mActivePosition));
                mSelectedId = mList.getAdapter().getItemId(mActivePosition);
            }
        });            
    }

mActivePosition may be 0 (ie position on the first item) or a position kept during eg onPause

score 0 · Answer 10 · answered Apr 04 '14 at 11:53

At Firstly I tried to use this code in my Fragment(Master/Detail -> NameListFragment)

getListView().performItemClick(null, 0, getListView().getAdapter().getItemId(0));

But it didn't work. When I did @Override onStart() method in fragment and I moved my code to onStart(). After that it works properly for me.

score 0 · Answer 11 · edited May 23 '17 at 11:47

0

If you are working on a unit test case. Try to use getInstrumentation().waitForIdleSync(), to wait the list be loaded, and extend the ActivityInstrumentationTestCase2 See this answer.

edited May 23 '17 at 11:47

Community

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answered May 27 '14 at 17:48

dinhokz

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score 0 · Answer 12 · answered Mar 18 '15 at 06:46

I just meet this freak problem today , and I try me best to deal with it. My condition is , when I first init the layout , I need make some item checked. But when I use gridView.getChildAt(position) , always return null. I met this problem before , caused by Not finishing drawing layout . So I send a post message . handler.postDelayed( .. , ..) , It works. Thanks who motion this Exception.

score 0 · Answer 13 · answered Dec 12 '15 at 14:04

This work for me If you would get weird result when using getView, this is because the list item you want does not exist within visible parts. Use below:

private View getViewFromAdapterByPosition(int position, ListView listView) 
{
        View view;
        int firstVisiblePos = listView.getFirstVisiblePosition();
        int lastVisiblePos = listView.getLastVisiblePosition();

        if (position < firstVisiblePos || position > lastVisiblePos) {
            view = listView.getAdapter().getView(position, null, listView);
        } else {
            view = listView.getChildAt(position - firstVisiblePos);
        }
        return view;
    }

And then,

listView.performItemClick(getViewFromAdapterByPosition(index, listView), index, 0);

score 0 · Answer 14 · answered Aug 16 '17 at 14:47

Try this one:

public static boolean performClicKOnLisViewFromIndex(ListView listView, int index){
        if(listView != null){
            if(listView.getAdapter()!= null && listView.getAdapter().getCount() >0 && listView.getAdapter().getCount() > index ){
                listView.performItemClick(
                        listView.getAdapter().getView(index, null, null),
                        index, listView.getItemIdAtPosition(index));
                return true;
            }
        }
        return  false;
    }

score 0 · Answer 15 · answered Jan 06 '20 at 15:10

myListView.getChildAt(0) returns null because used this very soon.

use a delay for it.

or use below code:

private class MyAdapter extends BaseAdapter
{
private final Context context;
private HashMap<Integer, View> views;

public MyAdapter(Context context)
{
    this.context = context;
    views = new HashMap<>();
}

@Override
public View getView(int position, View convertView, ViewGroup parent)
{
    if(convertView == null)
    {
        if(views.get(position) == null)
        {
            final LayoutInflater layoutInflater = LayoutInflater.from(context);
            convertView = layoutInflater.inflate(R.layout.my_grid, null, false);

            views.put(position, convertView);
        }
        else
            convertView = views.get(position);
    }

    TextView tv = convertView.findViewById(R.id.langView);
    tv.setText(languageList.get(position));

    return convertView;
}
}

and

adapter = new MyAdapter(getActivity());
myListView.setAdapter(adapter);

Runnable r = new Runnable()
{
    @Override
    public void run()
    {
        myListView.performItemClick(adapter.getView(position, null, myListView), position, 0);
    }
};

myListView.postDelayed(r, 100);

score 0 · Answer 16 · answered Feb 09 '20 at 08:58

0

just should use performItemClick() and it's okay.

listView.performItemClick(listView.getAdapter().getView(listView.getSelectedItemId, null, null), listView.getSelectedItemId, listView.getAdapter().getItemId(listView.getSelectedItemId));

answered Feb 09 '20 at 08:58

H.Fa8

318
3
10

score 0 · Answer 17 · answered Aug 02 '20 at 02:24

In my case, none of the options solved my problem, so I made an adaptation in my CursorAdapter class. I defined a global variable in the scope, so I just call the class changing this value and check the cursor position by passing the position value

 mProductsAdapter.currentPosition = requiredPosition

in my ProductsAdapter builder

  var currentPosition = 0

in bindView I do the check

 if (cursor.position == currentPosition) {
// perform action
}

score -1 · Answer 18 · answered Apr 22 '13 at 12:03

-1

getListView().performItemClick(null, 0, 0) did the trick for me (for position 0).

answered Apr 22 '13 at 12:03

AlikElzin-kilaka

34,335
35
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277

score -1 · Answer 19 · edited Jun 13 '17 at 01:11

-1

This worked for me:

listView.getAdapter().getView(1, null, null).performClick();

edited Jun 13 '17 at 01:11

Pang

9,564
146
81
122

answered Jan 14 '15 at 14:37

Drilon Kastrati

1

score -1 · Answer 20 · edited Jun 20 '20 at 09:12

-1

Dropping Some Experience.

using listview1.performItemClick, will also trigger your listview1.OnItemClickListener if you are using the listener with same listview in your code.

Hope It helps

edited Jun 20 '20 at 09:12

Community

1
1

answered Sep 03 '15 at 11:05

HourGlass

1,805
1
15
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score -1 · Answer 21 · answered Nov 12 '15 at 05:16

If you would get weird result when using getView, this is because the list item you want does not exist within visible parts. Use below:

private View getViewFromAdapterByPosition(int position, ListView listView) 
{
        View view;
        int firstVisiblePos = listView.getFirstVisiblePosition();
        int lastVisiblePos = listView.getLastVisiblePosition();

        if (position < firstVisiblePos || position > lastVisiblePos) {
            view = listView.getAdapter().getView(position, null, listView);
        } else {
            view = listView.getChildAt(position - firstVisiblePos);
        }
        return view;
    }

And then,

listView.performItemClick(getViewFromAdapterByPosition(index, listView), index, 0);

This is a supplement answer to @Arun Jose 's answer – kenju Nov 12 '15 at 05:16 — kenju, Nov 12 '15 at 05:16

score -1 · Answer 22 · edited Jun 13 '17 at 01:11

-1

This works for me:

listview.getSelectedView().performClick();

edited Jun 13 '17 at 01:11

Pang

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answered Jun 12 '17 at 12:51

hamidjahandideh

177
2
9

score -1 · Answer 23 · answered Nov 11 '11 at 15:58

-1

The performClick is probably called before listview was filled, put breakpoint in getView and on performItemClick and check wich is called first

answered Nov 11 '11 at 15:58

user1034443

9
1

It is being filled. At least it is not null. I have tried put that piece of code even after the adpter has been set but it still didn't work. This is driving me crazy! Any ideas? – Nov 16 '11 at 20:38

score -5 · Answer 24 · answered Nov 11 '11 at 13:18

This is from Begining Android Games. It creates a simple list of items which you can click to open a new activity. Each list item of course, would have to also be added to the AndroidManifest.xml as a separate activity with a .ListItem# name.

public class MainActivity extends ListActivity {
String tests[] = { "ListItem1",
                   "ListItem2",
                   "ListItem3",
                   "ListItem4"};

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setListAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, tests));
}

@Override
protected void onListItemClick(ListView list, View view, int position, long id) {
    super.onListItemClick(list, view, position, id);
    String testName = tests[position];

    try {
        Class<?> classInstance = Class.forName("your.package.name." + testName);
        Intent intent = new Intent(this, classInstance);
        startActivity(intent);
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }
}

}

Thanks for replying, but this is not what I want. I want to perform a click PROGRAMATICALLY in my ListView using the method performItemClick. — , Nov 11 '11 at 13:38

Android - ListView - performItemClick

24 Answers24

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