3

I have to show multiple incomes, type of income and employer name values for a single individual in a single row. So, if 'A' has three different incomes from three different sources,

 id  | Name | Employer     |  IncomeType       | Amount

 123 |  XYZ | ABC.Inc      |   EarningsformJob |  $200.00

 123 |  XYZ | Self         | Self Employment   |  $300.00

 123 | XYZ. |  ChildSupport|   Support         |  $500.00

I need to show them as

 id | Name | Employer1 | Incometype1| Amount1 | Employer2 | incometype2 | Amount2| Employer3 | Incometype3| Amount3.....

 123 |XYZ | ABC.Inc |EarningsformJob |  $200.00|Self  | Self Employment  |  $300.00|ChildSupport|   Support |  $500.00.....

I need both 'fixed number of columns' (where we know how many times employer, incometype and amount colums are going to repeat)logic and 'dynamic display of columns' ( unknown number of times these columns are going to repeat)

Thanks.

Taryn
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user2501777
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  • I think you could do with giving us a bit more info here like any initial stabs at solving the problem. I'd also make sure you tag this with the RDBMS you're using as this code could be very engine-specific – Steph Locke Jun 19 '13 at 15:52
  • Trying to generate a Report in Sql Server for a client. – user2501777 Jun 19 '13 at 16:02
  • possible duplicate of [Multiple column values in a single row](http://stackoverflow.com/questions/14619186/multiple-column-values-in-a-single-row) – Ken White Jun 19 '13 at 16:13

1 Answers1

13

Since you are using SQL Server there are several ways that you can transpose the rows of data into columns.

Aggregate Function / CASE: You can use an aggregate function with a CASE expression along with row_number(). This version would require that you have a known number of values to become columns:

select id,
  name,
  max(case when rn = 1 then employer end) employer1,
  max(case when rn = 1 then IncomeType end) IncomeType1,
  max(case when rn = 1 then Amount end) Amount1,
  max(case when rn = 2 then employer end) employer2,
  max(case when rn = 2 then IncomeType end) IncomeType2,
  max(case when rn = 2 then Amount end) Amount2,
  max(case when rn = 3 then employer end) employer3,
  max(case when rn = 3 then IncomeType end) IncomeType3,
  max(case when rn = 3 then Amount end) Amount3
from
(
  select id, name, employer, incometype, amount,
    row_number() over(partition by id order by employer) rn
  from yourtable
) src
group by id, name;

See SQL Fiddle with Demo.

PIVOT/UNPIVOT: You could use the UNPIVOT and PIVOT functions to get the result. The UNPIVOT converts your multiple columns of Employer, IncomeType and Amount into multiples rows before applying the pivot. You did not specific what version of SQL Server, assuming you have a known number of values then you could use the following in SQL Server 2005+ which uses CROSS APPLY with UNION ALL to unpivot:

select id, name, 
  employer1, incometype1, amount1,
  employer2, incometype2, amount2,
  employer3, incometype3, amount3
from
(
  select id, name, col+cast(rn as varchar(10)) col, value
  from
  (
    select id, name, employer, incometype, amount,
      row_number() over(partition by id order by employer) rn
    from yourtable
  ) t
  cross apply
  (
    select 'employer', employer union all
    select 'incometype', incometype union all
    select 'amount', cast(amount as varchar(50))
  ) c (col, value)
) src
pivot
(
  max(value)
  for col in (employer1, incometype1, amount1,
              employer2, incometype2, amount2,
              employer3, incometype3, amount3)
) piv;

See SQL Fiddle with Demo.

Dynamic Version: Lastly, if you have an unknown number of values then you will need to use dynamic SQL to generate the result.

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT ',' + QUOTENAME(col+cast(rn as varchar(10))) 
                    from
                    (
                      select row_number() over(partition by id order by employer) rn
                      from yourtable
                    ) d
                    cross apply
                    ( 
                      select 'employer', 1 union all
                      select 'incometype', 2 union all
                      select 'amount', 3
                    ) c (col, so)
                    group by col, rn, so
                    order by rn, so
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT id, name,' + @cols + ' 
             from 
             (
                select id, name, col+cast(rn as varchar(10)) col, value
                from
                (
                  select id, name, employer, incometype, amount,
                    row_number() over(partition by id order by employer) rn
                  from yourtable
                ) t
                cross apply
                (
                  select ''employer'', employer union all
                  select ''incometype'', incometype union all
                  select ''amount'', cast(amount as varchar(50))
                ) c (col, value)
            ) x
            pivot 
            (
                max(value)
                for col in (' + @cols + ')
            ) p '

execute(@query);

See SQL Fiddle with Demo. All versions give a result:

|  ID | NAME | EMPLOYER1 |     INCOMETYPE1 | AMOUNT1 |    EMPLOYER2 | INCOMETYPE2 | AMOUNT2 | EMPLOYER3 |     INCOMETYPE3 | AMOUNT3 |
-------------------------------------------------------------------------------------------------------------------------------------
| 123 |  XYZ |   ABC.Inc | EarningsformJob |     200 | ChildSupport |     Support |     500 |      Self | Self Employment |     300 |
Taryn
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  • Hello @bluefeet . I used the method you shared. I came across the problem which I posted here. Can you help please? http://stackoverflow.com/questions/28214838/using-pivoting-in-sql-server-error – Etibar - a tea bar Jan 29 '15 at 12:50