This may seem like a strange request. I was wondering if there is a way using a $http interceptor to catch the first URL that has a response status of 500, then stop all subsequent requests and processes and do something?
3 Answers
Thomas answer is correct, but this solution is currently deprecated. You should do something like this answer.
app.factory('errorInterceptor', function ($q) {
var preventFurtherRequests = false;
return {
request: function (config) {
if (preventFurtherRequests) {
return;
}
return config || $q.when(config);
},
requestError: function(request){
return $q.reject(request);
},
response: function (response) {
return response || $q.when(response);
},
responseError: function (response) {
if (response && response.status === 401) {
// log
}
if (response && response.status === 500) {
preventFurtherRequests = true;
}
return $q.reject(response);
}
};
});
app.config(function ($httpProvider) {
$httpProvider.interceptors.push('errorInterceptor');
});
You can catch all responses through $httpProvider.responseInterceptors
.
To do this you have to create a factory like this:
app.factory('SecurityHttpInterceptor', function($q) {
return function (promise) {
return promise.then(function (response) {
return response;
},
function (response) {
if (response.status === 500) {
//DO WHAT YOU WANT
}
return $q.reject(response);
});
};
});
In this factory you'll catch the response status if it's 500 do what you want. Then reject the response.
Now you have to put the factory in the responseInterceptors
of $httProvider
in your config module like that :
app.config(function ($routeProvider, $httpProvider) {
$routeProvider
.when('/', {
templateUrl: 'views/home.html',
controller: 'HomeCtrl'
})
.otherwise({
templateUrl: 'views/404.html'
});
$httpProvider.responseInterceptors.push('SecurityHttpInterceptor');
})

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Sorry I should have said I knew how to make an interceptor, i was wondering if there was a way to actually "stop" the $http.pendingRequests queue the first time a status 500 was encountered. – Ben Kilah Oct 04 '13 at 01:01
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I'm also looking for a solution to stopping all subsequent requests upon detecting a certain status code (403 in my case). I already have an interceptor set up, but don't know how to continue from there. Please share if you have a solution to this, thanks. – Mark Jun 12 '14 at 06:38
You could create a service and interceptor to deal with this,
.factory('ServerErrorService', function() {
var _hasError = false
return {
get hasError() {
return _hasError;
},
set hasError(value) {
_hasError = value;
// you could broadcast an event on $rootScope to notify another service that it has to deal with the error
},
clear: clear
}
function clear() {
_hasError = false;
}
})
.factory('ServerErrorInterceptor', function ($q, ServerErrorService) {
var interceptor = {
request: function(config) {
if(ServerErrorService.hasError) {
var q = $q.defer();
q.reject('prevented request');
return q.promise;
}
return config;
},
responseError: function(response) {
if(response.status === 500) {
ServerErrorService.hasError = true;
}
return $q.reject(response);
}
}
return interceptor;
})
If you wanted to allow requests to be made again then you just need to call ServerErrorService.clear()
OR
You could use a modified version of this answer. Although i'm not sure how - if you wanted to - you'd cancel this action and allow subsequent requests.
https://stackoverflow.com/a/25475121/1798234
.factory('ServerErrorInterceptor', function ($q) {
var canceller = $q.defer();
var interceptor = {
request: function(config) {
config.timeout = canceller.promise;
return config;
},
responseError: function(response) {
if(response.status === 500) {
canceller.resolve('server error');
}
return $q.reject(response);
}
}
return interceptor;
})
One thing to remember for both of these solutions, if you have any other interceptors after this that have a responseError
method defined or any handlers set up with .catch
to process the $http promise, they will receive a response object with {data:null, status:0}