Why are x and y strings instead of ints in the below code?
(Note: in Python 2.x use raw_input(). In Python 3.x use input(). raw_input() was renamed to input() in Python 3.x)
play = True
while play:
x = input("Enter a number: ")
y = input("Enter a number: ")
print(x + y)
print(x - y)
print(x * y)
print(x / y)
print(x % y)
if input("Play again? ") == "no":
play = False
Since Python 3, input returns a string which you have to explicitly convert to ints, with int, like this
x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
You can accept numbers of any base and convert them directly to base-10 with the int function, like this
>>> data = int(input("Enter a number: "), 8)
Enter a number: 777
>>> data
511
>>> data = int(input("Enter a number: "), 16)
Enter a number: FFFF
>>> data
65535
>>> data = int(input("Enter a number: "), 2)
Enter a number: 10101010101
>>> data
1365
The second parameter tells what is the base of the numbers entered and then internally it understands and converts it. If the entered data is wrong it will throw a ValueError.
>>> data = int(input("Enter a number: "), 2)
Enter a number: 1234
Traceback (most recent call last):
File "<input>", line 1, in <module>
ValueError: invalid literal for int() with base 2: '1234'
For values that can have a fractional component, the type would be float rather than int:
x = float(input("Enter a number:"))
Summary
input function evaluated the received data, converting it to an integer implicitly (read the next section to understand the implication), but Python 3's input function does not do that anymore.input is the raw_input function.Python 2.x
There were two functions to get user input, called input and raw_input. The difference between them is, raw_input doesn't evaluate the data and returns as it is, in string form. But, input will evaluate whatever you entered and the result of evaluation will be returned. For example,
>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)
The data 5 + 17 is evaluated and the result is 22. When it evaluates the expression 5 + 17, it detects that you are adding two numbers and so the result will also be of the same int type. So, the type conversion is done for free, and 22 is returned as the result of the input and stored in the data variable. You can think of input as the raw_input composed with an eval call.
>>> data = eval(raw_input("Enter a number: "))
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)
Note: You should be careful when you are using input in Python 2.x. I explained why one should be careful when using it, in this answer.
But, raw_input doesn't evaluate the input and returns as it is, as a string.
>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = raw_input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <type 'str'>)
Python 3.x
Python 3.x's input and Python 2.x's raw_input are similar and raw_input is not available in Python 3.x.
>>> import sys
>>> sys.version
'3.4.0 (default, Apr 11 2014, 13:05:11) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <class 'str'>)
In Python 3.x, raw_input was renamed to input and the Python 2.x input was removed.
This means that, just like raw_input, input in Python 3.x always returns a string object.
To fix the problem, you need to explicitly make those inputs into integers by putting them in int:
x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
For multiple integer in a single line, map might be better.
arr = map(int, raw_input().split())
If the number is already known, (like 2 integers), you can use
num1, num2 = map(int, raw_input().split())
input() (Python 3) and raw_input() (Python 2) always return strings. Convert the result to integer explicitly with int().
x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
Multiple questions require multiple integers to be entered on a single line. The best way is to enter the entire string of numbers line by line and split them into integers. Here is the Python 3 version:
a = []
p = input()
p = p.split()
for i in p:
a.append(int(i))
You can also use list comprehensions:
p = input().split("whatever the seperator is")
To convert all input from string to int we do the following:
x = [int(i) for i in p]
print(x, end=' ')
List elements should be printed in straight lines.
Convert to integers:
my_number = int(input("enter the number"))
Similarly for floating point numbers:
my_decimalnumber = float(input("enter the number"))
n=int(input())
for i in range(n):
n=input()
n=int(n)
arr1=list(map(int,input().split()))
the for loop shall run 'n' number of times . the second 'n' is the length of the array. the last statement maps the integers to a list and takes input in space separated form . you can also return the array at the end of for loop.
I encountered a problem of taking integer input while solving a problem on CodeChef, where two integers - separated by space - should be read from one line.
While int(input()) is sufficient for a single integer, I did not find a direct way to input two integers. I tried this:
num = input()
num1 = 0
num2 = 0
for i in range(len(num)):
if num[i] == ' ':
break
num1 = int(num[:i])
num2 = int(num[i+1:])
Now I use num1 and num2 as integers.
def dbz():
try:
r = raw_input("Enter number:")
if r.isdigit():
i = int(raw_input("Enter divident:"))
d = int(r)/i
print "O/p is -:",d
else:
print "Not a number"
except Exception ,e:
print "Program halted incorrect data entered",type(e)
dbz()
Or
num = input("Enter Number:")#"input" will accept only numbers
While in your example, int(input(...)) does the trick in any case, python-future's builtins.input is worth consideration since that makes sure your code works for both Python 2 and 3 and disables Python2's default behaviour of input trying to be "clever" about the input data type (builtins.input basically just behaves like raw_input).
