find a option in string split by space in bash

Question

I have a string like this, name it Options:

"printer-is-accepting-jobs=true printer-is-shared=false printer-location=Library printer-make-and-model='HP LaserJet 600 M601 M602 M603' printer-state=3"

they are "options=values" format, separated by spaces. but the "printer-make-and-model" has value with spaces.

tried command:

for word in $Options; do echo $word; done

all the HP LaserJet 600 M601 M602 M603 are splited.

How to deal with this in bash command?

perhaps one of the answers here will solve your problem http://stackoverflow.com/questions/9084257/bash-array-with-spaces-in-elements — clancer, Feb 28 '14 at 04:21
@h3nr1x. I would like to split the string to arrays, option=value for each line. — TonyL2ca, Feb 28 '14 at 04:58

anubhava · Accepted Answer · 2014-02-28T04:48:38.090

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Using grep -oP:

grep -oP "printer-make-and-model='\K[^']*" <<< "$s"
HP LaserJet 600 M601 M602 M603

OR using sed:

sed "s/^.*printer-make-and-model='\([^']*\).*/\1/" <<< "$s"
HP LaserJet 600 M601 M602 M603

edited Feb 28 '14 at 04:48

answered Feb 28 '14 at 04:35

anubhava

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Thank you! sorry, forget to mention, I'm on Mac. it doesn't have the -P options, what is the -P for? – TonyL2ca Feb 28 '14 at 04:40
I am also on OSX and `grep -P` is available (-P for PCRE) – anubhava Feb 28 '14 at 04:46
1

:) @jaypal you can take any regex/code from my answer. There is no copyright as I learnt most of it from SO and other forums. – anubhava Feb 28 '14 at 05:32

score 1 · Answer 2 · edited May 23 '17 at 12:03

1

Anubhava's regex is good, so if you don't have grep -P option then you can try:

ack command:

$ ack -ho "printer-make-and-model='\K[^']*" <<< "$options"
HP LaserJet 600 M601 M602 M603

or Perl:

$ perl -nle "print $+{f} if /printer-make-and-model='(?'f'\K[^']*)/" <<< "$options"
HP LaserJet 600 M601 M602 M603

edited May 23 '17 at 12:03

Community

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answered Feb 28 '14 at 05:15

jaypal singh

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Timmah · Answer 3 · 2014-02-28T07:19:45.033

1

You can do this with multiple awk statements:

while read record; do
    while read key value; do
        echo "K=($key) V=($value)"
    done< <(awk -F"=" '{printf("%s %s\n", $1, $2)}' <<< $record)
done< <(awk -F"printer-" '{for(i=2;i<NF;i++){printf("printer-%s\n", $i)}}' <<< $string)

This will split to output into key value pairs.

edited Feb 28 '14 at 07:19

answered Feb 28 '14 at 07:14

Timmah

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@"Tim Verhoeven", amazing! yours' give me the whole list! Thank you! – TonyL2ca Feb 28 '14 at 23:12

score 0 · Answer 4 · answered Feb 28 '14 at 07:12

0

Since you need to parse options, you can use getopt. However, this requires to use the evil eval command. So be careful about your input.

$ string="printer-is-accepting-jobs=true printer-is-shared=false printer-location=Library printer-make-and-model='HP LaserJet 600 M601 M602 M603' printer-state=3"
$ eval a=("$string")
$ eval b=($(getopt --long printer-make-and-model: -- ${a[@]/#/--} 2>/dev/null))
$ echo "${b[1]}"
HP LaserJet 600 M601 M602 M603

answered Feb 28 '14 at 07:12

anishsane

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on my Mac, **echo "${b[1]}"** gets **"printer-make-and-model:"** – TonyL2ca Feb 28 '14 at 23:10
Frankly, I haven't tried it on mac, but I think, `getopt` on `mac` gives different output than on my system. try `for x in "${b[@]}; do echo $x; done` to see if the order of parameters has changed in the getopt output... – anishsane Mar 03 '14 at 05:22

find a option in string split by space in bash

4 Answers4