open google maps through intent for specific location in android

Question

I'm designing one application in which I want to show specific location on Map. I'm passing String of address which is already placed on Google Map. Following is my Intent code..

String url = "http://maps.google.com/maps?daddr="+address;
Intent intent = new Intent(android.content.Intent.ACTION_VIEW,  Uri.parse(url));
startActivity(intent);

But it gives me Google Map for getting direction. I know why that so, because I used daddr in url but I don't know what to use for specific location..Please tell me what to use there..

hi I am developing a trip planner project, is completely free to use 'open google maps through intent for a specific location in android', or any pricing if reached quote?? do you know anything about this plz share — Bolt UIX, Jan 28 '21 at 10:43
Its completely free to open specific location via intent as you are opening it in external App and not in yours.. — Akshay, Jan 29 '21 at 11:40

Rat-a-tat-a-tat Ratatouille · Accepted Answer · 2014-03-28T05:38:14.797

154

I have not tested this but you could try :

First method:

String uri = String.format(Locale.ENGLISH, "geo:%f,%f", latitude, longitude);
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(uri));
context.startActivity(intent);

EDIT: This might not work with Google maps 7,0

hence you could change the uri to :

Second option:

String geoUri = "http://maps.google.com/maps?q=loc:" + lat + "," + lng + " (" + mTitle + ")";

where mTitle is the name of the location.

Third option:

geo:0,0?q=my+street+address

Fourth option:

String map = "http://maps.google.co.in/maps?q=" + yourAddress;

Hope that works and helps :D..

edited Mar 28 '14 at 05:38

answered Mar 28 '14 at 05:02

Rat-a-tat-a-tat Ratatouille

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and what about lat and lng ? I don't want to pass them, I'm just passing address – Akshay Mar 28 '14 at 05:09
oh alright, il have to google that part :).. like i said iv not tried this either :).. il get back – Rat-a-tat-a-tat Ratatouille Mar 28 '14 at 05:13
Please try, and if you get something the tell me – Akshay Mar 28 '14 at 05:16
but i think i did read it somewhere that it would ignore the lat and long and simply take the location denoted by `mTitle` – Rat-a-tat-a-tat Ratatouille Mar 28 '14 at 05:17
and you could catch ur ears the other way round, get lat and long from the address and then pass those to the string uri – Rat-a-tat-a-tat Ratatouille Mar 28 '14 at 05:20
@Aksh hi, try `geo:0,0?q=my+street+address` – Rat-a-tat-a-tat Ratatouille Mar 28 '14 at 05:31
Thanks, your fourth solution worked so easily, just have to add `q` ..:) – Akshay Mar 28 '14 at 05:44
Second one is mine. I used it without adding title and it works. – oguzhan Dec 14 '16 at 19:09
Any idea how to pass the adress to the search bar of Google Maps? – Daniel Reyhanian Jan 11 '20 at 20:19

Darshak · Answer 2 · 2014-03-28T05:21:19.477

Get Lat-Lng Using this web-service

http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false

Then Pass it to this code

    String strUri = "http://maps.google.com/maps?q=loc:" + lat + "," + lng + " (" + "Label which you want" + ")";
    Intent intent = new Intent(android.content.Intent.ACTION_VIEW, Uri.parse(strUri));

    intent.setClassName("com.google.android.apps.maps", "com.google.android.maps.MapsActivity");

    startActivity(intent);

I hope it will help you

Thank you.

score 36 · Answer 3 · answered Sep 12 '16 at 06:46

36

The latest version of map provides better solution. If you wish show an address on map use below code.

Uri mapUri = Uri.parse("geo:0,0?q=" + Uri.encode(address));
Intent mapIntent = new Intent(Intent.ACTION_VIEW, mapUri);
mapIntent.setPackage("com.google.android.apps.maps");
startActivity(mapIntent);

If you want to display using latitude and longitude values, use below method.

Uri mapUri = Uri.parse("geo:0,0?q=lat,lng(label)");
Intent mapIntent = new Intent(Intent.ACTION_VIEW, mapUri);
mapIntent.setPackage("com.google.android.apps.maps");
startActivity(mapIntent);

Lat and lng being the latitude and longitude you wish to display, the label here is optional.

answered Sep 12 '16 at 06:46

Ishaan

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+1, this is the only option that doesn't explicitly mention Google Maps. The `?q=lat,lon` parameter has better results too, as it displays a pin on the opened map (the first lat,lon only pans the map to the location). The `setPackage` call is optional. – Benoit Duffez May 18 '17 at 19:32
1

FYI, Google Maps is not displaying the value for "label" when the 2nd option you've shown is used. I have verified that `regionData.name` is a String in the following code snippet `Uri.parse("geo:0,0?q=loc:${regionData.location.latitude},${regionData.location.longitude} (${regionData.name})")` – Bill Mote Apr 08 '19 at 15:19

score 8 · Answer 4 · edited Dec 26 '19 at 12:45

This will work like a charm. Make sure to check for existence for Google Maps, so this can work universally across all non Google devices also. It will open in a browser in such cases.

Also, remember, don't have www in the URL. Else this will not work.

        Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse("http://maps.google.com/maps?q=loc:" + latitude + "," + longitude));
        i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); // Only if initiating from a Broadcast Receiver
        String mapsPackageName = "com.google.android.apps.maps";
        if (isPackageExisted(context, mapsPackageName)) {
            i.setClassName(mapsPackageName, "com.google.android.maps.MapsActivity");
            i.setPackage(mapsPackageName);
        }
        context.startActivity(i);

private static boolean isPackageExisted(Context context, String targetPackage){
    PackageManager pm=context.getPackageManager();
    try {
        PackageInfo info=pm.getPackageInfo(targetPackage,PackageManager.GET_META_DATA);
    } catch (PackageManager.NameNotFoundException e) {
        return false;
    }
    return true;
}

score 5 · Answer 5 · edited Dec 03 '22 at 20:02

As of 2020 you can also consider using Google Maps URLs, the API designed by Google in order to create universal cross-platform links. You can open Google maps on web, Android or iOS using the same URL string in form:

https://www.google.com/maps/search/?api=1&parameters

In case when you need show certain location you can use an URL like

https://www.google.com/maps/search/?api=1&query=36.26577,-92.54324

The code snippet is

String url = "https://www.google.com/maps/search/?api=1&query="+address;
Intent intent = new Intent(android.content.Intent.ACTION_VIEW,Uri.parse(url));
startActivity(intent);

score 3 · Answer 6 · edited Oct 14 '22 at 19:48

3

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse("geo:0,0?q=" + address));
startActivity(intent);

edited Oct 14 '22 at 19:48

halfer

19,824
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answered Feb 26 '21 at 17:15

Kavishka Kolamunna

31
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score 2 · Answer 7 · answered Sep 21 '16 at 14:21

Uri gmmIntentUri = Uri.parse("geo:37.7749,-122.4194");
Intent mapIntent = new Intent(Intent.ACTION_VIEW, gmmIntentUri);
mapIntent.setPackage("com.google.android.apps.maps");
if (mapIntent.resolveActivity(getPackageManager()) != null) {
    startActivity(mapIntent);
}

Refer this documentation

score 2 · Answer 8 · answered Sep 27 '17 at 12:30

  try {
                    Intent intent = new Intent(android.content.Intent.ACTION_VIEW,
                            Uri.parse("http://maps.google.com/maps?saddr=" + src_lat+ "," + src_lng + "&daddr=" + des_lat + "," + des_lng));
                    startActivity(intent);
                }catch (ActivityNotFoundException  ane){

                    Toast.makeText(activity, "Please Install Google Maps ", Toast.LENGTH_LONG).show();
                }catch (Exception ex){
                    ex.getMessage();
                }
            }
        });

score 1 · Answer 9 · answered Jun 14 '17 at 13:35

This helper method using uriBuilder for cleaner code and handle condition if there is no activity on device that can open map

public static boolean openMap(Context context, String address) {
    Uri.Builder uriBuilder = new Uri.Builder()
            .scheme("geo")
            .path("0,0")
            .appendQueryParameter("q", address);
    Intent intent = new Intent(Intent.ACTION_VIEW, uriBuilder.build());
    if (intent.resolveActivity(context.getPackageManager()) != null) {
        context.startActivity(intent);
        return true;
    }
    return false;
}

score 1 · Answer 10 · answered Mar 04 '20 at 12:58

To show location and disply show directions button inside google Maps use this code snippet:

String geoUri = "http://maps.google.com/maps?q=loc:" + latitude + "," + longitude + " (" + locationName + ")";
Intent mapIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(geoUri));
if (mapIntent.resolveActivity(context.getPackageManager()) != null) {
    context.startActivity(mapIntent);

score 1 · Answer 11 · edited Oct 14 '22 at 19:48

I find this solution in Google documentation so, it will work fine.

Double latitude = 37.7749,longitude = -122.4192;
            String label = "Your location desired Aryan";
            Uri gmmIntentUri =
                    Uri.parse("geo:0,0?q="+latitude+","+longitude+"("+label+")");
            Intent mapIntent = new Intent(Intent.ACTION_VIEW, gmmIntentUri);
            mapIntent.setPackage("com.google.android.apps.maps");
            context.startActivity(mapIntent);

If you have any doubt just comment it. I am not checking maps package because on every Android device we have maps. If you want you check it easily.

score 0 · Answer 12 · answered Jan 24 '20 at 07:14

For the ones, who are looking for opening the "Maps" app for a particular location(by passing lat and long) and do not want that lat/long co-ordinates to be shown in Maps search bar after redirection(Opening Maps app). Instead wish to show some label or place name, you can refer to the code below,

private void openMapView(String latitude , String longitude , String locationName){
    Uri gmmIntentUri = Uri.parse("geo:"+latitude+","+longitude+"?q="+locationName);
    Intent mapIntent = new Intent(Intent.ACTION_VIEW, gmmIntentUri);
    mapIntent.setPackage("com.google.android.apps.maps");
    if (mapIntent.resolveActivity(context.getPackageManager()) != null) {
        context.startActivity(mapIntent);
    }
}

Note : "locationName" in the method above, represents the name you wish to display inside the Maps search bar.

score 0 · Answer 13 · answered Dec 06 '22 at 11:20

I thought I would chip in with the Kotlin code.

I created a helper function that takes latitude, longitude and context params to fire off the intent.

fun openGoogleMap(latitude: Double, longitude: Double, context: Context) { ... }

Inside the openGoogleMap() helper function create an intent passing in the action, data to act upon (lat/long) and package name for the Google Map application.

 fun openGoogleMap(latitude: Double, longitude: Double, context: Context) {
    
        // you need action, data and package name
    
        val uri = Uri.parse("geo:$latitude,$longitude?z=15")
        //create an intent
        val mapIntent = Intent()
    
        //add action & data
        mapIntent.action = Intent.ACTION_VIEW
        mapIntent.data = uri
    
        //package name for google maps app
        mapIntent.setPackage("com.google.android.apps.maps")
        try {
            context.startActivity(mapIntent)
        } catch (e: ActivityNotFoundException) {
    
            //if map app isn't resolved/installed catch error
            e.printStackTrace()
        }

}

The docs say that

To verify that an app is available to receive the intent, call resolveActivity() on your Intent object. If the result is non-null, there is at least one app that can handle the intent and it's safe to call startActivity().

But I found that using resolveActivity() has issues when used with this code especially when you are outside the Activity's code.

mapIntent.resolveActivity(packageManager)?.let {
  ...
}

To get around this I used try-catch block to catch ActivityNotFoundException with startActivity().

mapIntent.setPackage("com.google.android.apps.maps")
        try {
            context.startActivity(mapIntent)
        } catch (e: ActivityNotFoundException) {

            //if map app isn't resolved/installed catch error
            e.printStackTrace()
        }

I tested the util function and it does work and is launching the GoogleMaps with Kotlin code.

score 0 · Answer 14 · answered Feb 08 '23 at 14:23

If you have the name and address of the location available then you can launch the exact spot along with its images, details and navigation option using the following code :

    fun loadLocation(ctx: Context, name: String, address: String) {
        try {
            val geoUri = "http://maps.google.com/maps?q=$name,$address"
            val intent = Intent(Intent.ACTION_VIEW, Uri.parse(geoUri))
            ctx.startActivity(intent)
        }
        catch (ex: Exception) {
            ex.printStackTrace()
        }
    }

score -2 · Answer 15 · edited Aug 31 '22 at 09:54

https://www.google.com/maps/dir//37.4219983,-122.084

String location = "https://www.google.com/maps/dir//" + latitude + "," + longitude;
try {
    SmsManager sms = SmsManager.getDefault(); // using android SmsManager
    sms.sendTextMessage(number, null, message + location, null, null); // adding number and text
    Toast.makeText(getApplicationContext(), "Message Sent", Toast.LENGTH_SHORT).show();
} catch (Exception e) {
    Toast.makeText(this, "Sms not send, please check phone number/network", Toast.LENGTH_SHORT).show();
    e.printStackTrace();
}

open google maps through intent for specific location in android

15 Answers15

Get Lat-Lng Using this web-service

Then Pass it to this code

I hope it will help you

Linked