Getting URL parameter in java and extract a specific text from that URL

Question

I have a URL and I need to get the value of v from this URL. Here is my URL: http://www.youtube.com/watch?v=_RCIP6OrQrE

How can I do that?

what is v ?? and please provide some more information and code if you can — Harmeet Singh, Jul 31 '12 at 05:15
what you are trying to do with youtube URL ? do you need to find the value `v` from a `url-string` using substring methods ? — sunil, Jul 31 '12 at 05:20
http://www.youtube.com/watch?v=_RCIP6OrQrE I need to get value of v= — codezoner, Jul 31 '12 at 05:22
@androidmaniac hey android, check out my answer btw.. I rewrote it. The function will support multiple sets of youtube urls. — classicjonesynz, Feb 14 '13 at 09:46
@androidmaniac I updated my answer, by the way.. the code represents a more universal way of retrieving a parameter from any youtube url. — classicjonesynz, Mar 24 '13 at 23:49

score 72 · Accepted Answer · edited May 13 '20 at 12:40

72

I think the one of the easiest ways out would be to parse the string returned by URL.getQuery() as

public static Map<String, String> getQueryMap(String query) {  
    String[] params = query.split("&");  
    Map<String, String> map = new HashMap<String, String>();

    for (String param : params) {  
        String name = param.split("=")[0];  
        String value = param.split("=")[1];  
        map.put(name, value);  
    }  
    return map;  
}

You can use the map returned by this function to retrieve the value keying in the parameter name.

edited May 13 '20 at 12:40

Willi Mentzel

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answered Jul 31 '12 at 05:31

verisimilitude

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This would not work for multivalued parameters. In the following example the EmployeeID parameter has three values: Northwest/Employee Sales Report&rs:Command=Render&EmployeeID=A&EmployeeID=B&EmployeeID=C You could make this work using a multi-valule map implementation instead of HashMap. I don't think the JRE has any, but multi-value map parameter implementations are easily found on the web. – DaBlick Apr 24 '13 at 20:37
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Also a ArrayIndexOutOfBoudndsException would be throw for urls like `example.com.com?param` or `example.com?param=` – Panthro Sep 04 '15 at 09:40
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I recommend the solution here: http://stackoverflow.com/questions/5902090/how-to-extract-parameters-from-a-given-url – Panthro Sep 04 '15 at 09:41
This will not work if the values contain "=" signs. I changed `String value = param.split("=")[1];` with `String value = param.split(name+"=")[1];` and now it seems to work. – Dr. Gadget Nov 21 '17 at 15:05

score 30 · Answer 2 · edited Sep 10 '17 at 03:41

30

If you're on Android, you can do this:

Uri uri = Uri.parse(url);
String v = uri.getQueryParameter("v");

edited Sep 10 '17 at 03:41

Noah Andrews

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answered Nov 08 '16 at 02:18

Deep P

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Could you explain what package contains this? – T J Jul 20 '17 at 14:30
@TJ It's in the Android SDK – Noah Andrews Sep 10 '17 at 01:57

score 9 · Answer 3 · answered Jul 11 '17 at 14:26

I have something like this:

import org.apache.http.NameValuePair;
import org.apache.http.client.utils.URIBuilder;

private String getParamValue(String link, String paramName) throws URISyntaxException {
        List<NameValuePair> queryParams = new URIBuilder(link).getQueryParams();
        return queryParams.stream()
                .filter(param -> param.getName().equalsIgnoreCase(paramName))
                .map(NameValuePair::getValue)
                .findFirst()
                .orElse("");
    }

classicjonesynz · Answer 4 · 2015-03-19T04:53:49.883

I wrote this last month for Joomla Module when implementing youtube videos (with the Gdata API). I've since converted it to java.

Import These Libraries

    import java.net.URL;
    import java.util.regex.*;

Copy/Paste this function

    public String getVideoId( String videoId ) throws Exception {
        String pattern = "^(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]";
        Pattern p = Pattern.compile(pattern);
        Matcher m = p.matcher(videoId);
        int youtu = videoId.indexOf("youtu");
        if(m.matches() && youtu != -1){
            int ytu = videoId.indexOf("http://youtu.be/");
            if(ytu != -1) { 
                String[] split = videoId.split(".be/");
                return split[1];
            }
            URL youtube = new URL(videoId);
            String[] split = youtube.getQuery().split("=");
            int query = split[1].indexOf("&");
            if(query != -1){
                String[] nSplit = split[1].split("&");
                return nSplit[0];
            } else return split[1];
        }
        return null; //throw something or return what you want
    }

URL's it will work with

http://www.youtube.com/watch?v=k0BWlvnBmIE (General URL)
http://youtu.be/k0BWlvnBmIE (Share URL)
http://www.youtube.com/watch?v=UWb5Qc-fBvk&list=FLzH5IF4Lwgv-DM3CupM3Zog&index=2 (Playlist URL)

@paranoid-android +1 rep yeah thanks I know, just forgot what the syntax was without Eclipse open. — classicjonesynz, Jul 31 '12 at 05:30
Please don't advocate parsing URLs by hand. Use a library for that. — Peter V. Mørch, Jan 07 '21 at 05:13

score 3 · Answer 5 · answered Apr 23 '15 at 07:04

Import these libraries

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;

Similar to the verisimilitude, but with the capabilities of handling multivalue parameters. Note: I've seen HTTP GET requests without a value, in this case the value will be null.

public static List<NameValuePair> getQueryMap(String query)  
{  
    List<NameValuePair> queryMap = new ArrayList<NameValuePair>();
    String[] params = query.split(Pattern.quote("&"));  
    for (String param : params)
    {
        String[] chunks = param.split(Pattern.quote("="));
        String name = chunks[0], value = null;  
        if(chunks.length > 1) {
            value = chunks[1];
        }
        queryMap.add(new BasicNameValuePair(name, value));
    }
    return queryMap;
}

Example:

GET /bottom.gif?e235c08=1509896923&%49%6E%...

score 3 · Answer 6 · answered Jul 21 '20 at 15:29

Using pure Java 8

Assumming you want to extract param "v" from url:

             String paramV = Stream.of(url.split("?")[1].split("&"))
                        .map(kv -> kv.split("="))
                        .filter(kv -> "v".equalsIgnoreCase(kv[0]))
                        .map(kv -> kv[1])
                        .findFirst()
                        .orElse("");

score 2 · Answer 7 · answered Mar 16 '19 at 07:07

I believe we have a better approach to answer this question.

1: Define a function that returns Map values.

Here we go.

public Map<String, String> getUrlValues(String url) throws UnsupportedEncodingException {
    int i = url.indexOf("?");
    Map<String, String> paramsMap = new HashMap<>();
    if (i > -1) {
        String searchURL = url.substring(url.indexOf("?") + 1);
        String params[] = searchURL.split("&");

        for (String param : params) {
            String temp[] = param.split("=");
            paramsMap.put(temp[0], java.net.URLDecoder.decode(temp[1], "UTF-8"));
        }
    }

    return paramsMap;
}

2: Call your function surrounding with a try catch block

Here we go

try {
     Map<String, String> values = getUrlValues("https://example.com/index.php?form_id=9&page=1&view_id=78");
     String formId = values.get("form_id");
     String page = values.get("page");
     String viewId = values.get("view_id");
     Log.d("FormID", formId);
     Log.d("Page", page);
     Log.d("ViewID", viewId);
} catch (UnsupportedEncodingException e) {
     Log.e("Error", e.getMessage());
}

score 2 · Answer 8 · answered Mar 29 '19 at 16:36

If you are using Jersey (which I was, my server component needs to make outbound HTTP requests) it contains the following public method:

var multiValueMap = UriComponent.decodeQuery(uri, true);

It is part of org.glassfish.jersey.uri.UriComponent, and the javadoc is here. Whilst you may not want all of Jersey, it is part of the Jersey common package which isn't too bad on dependencies...

score 2 · Answer 9 · answered Oct 27 '19 at 09:09

I solved the problem like this

public static String getUrlParameterValue(String url, String paramName) {
String value = "";
List<NameValuePair> result = null;

try {
    result = URLEncodedUtils.parse(new URI(url), UTF_8);
    value = result.stream().filter(pair -> pair.getName().equals(paramName)).findFirst().get().getValue();
    System.out.println("-------------->  \n" + paramName + " : " + value + "\n");
} catch (URISyntaxException e) {
    e.printStackTrace();
} 
return value;

}

score 1 · Answer 10 · answered Jul 31 '12 at 05:27

1

Assuming the URL syntax will always be http://www.youtube.com/watch?v= ...

String v = "http://www.youtube.com/watch?v=_RCIP6OrQrE".substring(31);

or disregarding the prefix syntax:

String url = "http://www.youtube.com/watch?v=_RCIP6OrQrE";
String v = url.substring(url.indexOf("v=") + 2);

answered Jul 31 '12 at 05:27

rtheunissen

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What do you mean, @smonff? – rtheunissen Oct 13 '15 at 19:45
I mean that I appreciated the simplicity of your answer :-D – smonff Oct 13 '15 at 19:47

Harmeet Singh · Answer 11 · 2012-07-31T05:40:28.457

this will work for all sort of youtube url :
if url could be

youtube.com/?v=_RCIP6OrQrE
youtube.com/v/_RCIP6OrQrE
youtube.com/watch?v=_RCIP6OrQrE
youtube.com/watch?v=_RCIP6OrQrE&feature=whatever&this=that

Pattern p = Pattern.compile("http.*\\?v=([a-zA-Z0-9_\\-]+)(?:&.)*");
String url = "http://www.youtube.com/watch?v=_RCIP6OrQrE";
Matcher m = p.matcher(url.trim()); //trim to remove leading and trailing space if any

if (m.matches()) {
    url = m.group(1);        
}
System.out.println(url);

this will extract video id from your url

further reference

score 0 · Answer 12 · edited Oct 31 '18 at 15:18

My solution mayble not good

        String url = "https://www.youtube.com/watch?param=test&v=XcHJMiSy_1c&lis=test";
        int start = url.indexOf("v=")+2;
        // int start = url.indexOf("list=")+5; **5 is length of ("list=")**
        int end = url.indexOf("&", start);

        end = (end == -1 ? url.length() : end); 

        System.out.println(url.substring(start, end));
        // result: XcHJMiSy_1c

work fine with:

https://www.youtube.com/watch?param=test&v=XcHJMiSy_1c&lis=test
https://www.youtube.com/watch?v=XcHJMiSy_1c

score 0 · Answer 13 · edited Feb 14 '20 at 05:39

0

public static String getQueryMap(String query) {        
    String[] params = query.split("&");     
    for (String param : params) {           
       String name = param.split("=")[0];
       if ("YourParam".equals(name)) {
           return param.split("=")[1]; 
       }
    }
    return null;
}

edited Feb 14 '20 at 05:39

Hank

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answered Feb 14 '20 at 04:49

Shubham Goswami

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Getting URL parameter in java and extract a specific text from that URL

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