openURL from App Extension

Question

On iOS 8 beta 2 it should be possible to use openUrl from app extension as written into the release notes:

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however when I try to use this API (on Xcode 6 beta 2) I get the following error:

enter image description here

Beta 2 really fixed this issue or not?

score 45 · Accepted Answer · edited May 23 '17 at 11:46

45

you may use this code:

[self.extensionContext openURL:url completionHandler:^(BOOL success) {
        NSLog(@"fun=%s after completion. success=%d", __func__, success);
    }];

the API document: openURL:completionHandler:

you could also refer to this question: openURL not work in Action Extension

edited May 23 '17 at 11:46

Community

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answered Jun 23 '14 at 02:53

Laurence Fan

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@MassimoPiazza Which type Extension do you use when you add openURL sentence? I try it in Action extension but failed. I only success in Today extension. What result do you have? – Laurence Fan Jun 24 '14 at 03:32
@MassimoPiazza Got it. I am working on Action extension and openURL can not work. Wait for Apple's response. – Laurence Fan Jun 24 '14 at 16:08
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I might add that this code worked inside an IBACtion for a button overlaid over the entire widget. Is there a way to do this without an invisible button? – Jackson Jul 30 '14 at 00:34
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Only Today Extensions support openUrl. See this thread: http://stackoverflow.com/questions/24297273/openurl-not-work-in-action-extension – n8tr Aug 07 '14 at 18:28

score 6 · Answer 2 · answered Jun 12 '17 at 12:22

6

Accepted solution only works in Today extensions, a working solution in Swift 3.1 (tested in iOS10) for other extension-types:

You need to create your own URL Scheme, then add this function to your ViewController and call it with openURL("myScheme://myIdentifier")

//  Function must be named exactly like this so a selector can be found by the compiler!
//  Anyway - it's another selector in another instance that would be "performed" instead.
func openURL(_ url: URL) -> Bool {
    var responder: UIResponder? = self
    while responder != nil {
        if let application = responder as? UIApplication {
            return application.perform(#selector(openURL(_:)), with: url) != nil
        }
        responder = responder?.next
    }
    return false
}

answered Jun 12 '17 at 12:22

coyer

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Do you have objective-C solution for this? – George May 02 '19 at 13:24
Sorry I can't deal with this. I found some ObjC to a similar problem which may help porting: https://stackoverflow.com/questions/24495362/launch-containing-app-from-ios8-custom-keyboard – coyer May 02 '19 at 13:39
This is very useful for MacCatalyst applications. Thanks. – Dzmitry Sotnikov Nov 17 '21 at 09:33

openURL from App Extension

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