How to emulate a do-while loop?

Question

I need to emulate a do-while loop in a Python program. Unfortunately, the following straightforward code does not work:

list_of_ints = [ 1, 2, 3 ]
iterator = list_of_ints.__iter__()
element = None

while True:
  if element:
    print element

  try:
    element = iterator.next()
  except StopIteration:
    break

print "done"

Instead of "1,2,3,done", it prints the following output:

[stdout:]1
[stdout:]2
[stdout:]3
None['Traceback (most recent call last):
', '  File "test_python.py", line 8, in <module>
    s = i.next()
', 'StopIteration
']

What can I do in order to catch the 'stop iteration' exception and break a while loop properly?

An example of why such a thing may be needed is shown below as pseudocode.

State machine:

s = ""
while True :
  if state is STATE_CODE :
    if "//" in s :
      tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
      state = STATE_COMMENT
    else :
      tokens.add( TOKEN_CODE, s )
  if state is STATE_COMMENT :
    if "//" in s :
      tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
    else
      state = STATE_CODE
      # Re-evaluate same line
      continue
  try :
    s = i.next()
  except StopIteration :
    break

Answer 1

I am not sure what you are trying to do. You can implement a do-while loop like this:

while True:
  stuff()
  if fail_condition:
    break

Or:

stuff()
while not fail_condition:
  stuff()

What are you doing trying to use a do while loop to print the stuff in the list? Why not just use:

for i in l:
  print i
print "done"

Update:

So do you have a list of lines? And you want to keep iterating through it? How about:

for s in l: 
  while True: 
    stuff() 
    # use a "break" instead of s = i.next()

Does that seem like something close to what you would want? With your code example, it would be:

for s in some_list:
  while True:
    if state is STATE_CODE:
      if "//" in s:
        tokens.add( TOKEN_COMMENT, s.split( "//" )[1] )
        state = STATE_COMMENT
      else :
        tokens.add( TOKEN_CODE, s )
    if state is STATE_COMMENT:
      if "//" in s:
        tokens.append( TOKEN_COMMENT, s.split( "//" )[1] )
        break # get next s
      else:
        state = STATE_CODE
        # re-evaluate same line
        # continues automatically

Answer 2

Here's a very simple way to emulate a do-while loop:

condition = True
while condition:
    # loop body here
    condition = test_loop_condition()
# end of loop

The key features of a do-while loop are that the loop body always executes at least once, and that the condition is evaluated at the bottom of the loop body. The control structure show here accomplishes both of these with no need for exceptions or break statements. It does introduce one extra Boolean variable.

Answer 3

My code below might be a useful implementation, highlighting the main difference between do-while vs while as I understand it.

So in this one case, you always go through the loop at least once.

first_pass = True
while first_pass or condition:
    first_pass = False
    do_stuff()

Answer 4

do {
  stuff()
} while (condition())

->

while True:
  stuff()
  if not condition():
    break

You can do a function:

def do_while(stuff, condition):
  while condition(stuff()):
    pass

But 1) It's ugly. 2) Condition should be a function with one parameter, supposed to be filled by stuff (it's the only reason not to use the classic while loop.)

Answer 5

Exception will break the loop, so you might as well handle it outside the loop.

try:
  while True:
    if s:
      print s
    s = i.next()
except StopIteration:   
  pass

I guess that the problem with your code is that behaviour of break inside except is not defined. Generally break goes only one level up, so e.g. break inside try goes directly to finally (if it exists) an out of the try, but not out of the loop.

Related PEP: http://www.python.org/dev/peps/pep-3136
Related question: Breaking out of nested loops

Answer 6

I believe that this do-while simulation on python has a syntax format closest to the do-while structure format present in C and Java.

do = True
while do:
    [...]
    do = <condition>

Answer 7

Here is a crazier solution of a different pattern -- using coroutines. The code is still very similar, but with one important difference; there are no exit conditions at all! The coroutine (chain of coroutines really) just stops when you stop feeding it with data.

def coroutine(func):
    """Coroutine decorator

    Coroutines must be started, advanced to their first "yield" point,
    and this decorator does this automatically.
    """
    def startcr(*ar, **kw):
        cr = func(*ar, **kw)
        cr.next()
        return cr
    return startcr

@coroutine
def collector(storage):
    """Act as "sink" and collect all sent in @storage"""
    while True:
        storage.append((yield))

@coroutine      
def state_machine(sink):
    """ .send() new parts to be tokenized by the state machine,
    tokens are passed on to @sink
    """ 
    s = ""
    state = STATE_CODE
    while True: 
        if state is STATE_CODE :
            if "//" in s :
                sink.send((TOKEN_COMMENT, s.split( "//" )[1] ))
                state = STATE_COMMENT
            else :
                sink.send(( TOKEN_CODE, s ))
        if state is STATE_COMMENT :
            if "//" in s :
                sink.send(( TOKEN_COMMENT, s.split( "//" )[1] ))
            else
                state = STATE_CODE
                # re-evaluate same line
                continue
        s = (yield)

tokens = []
sm = state_machine(collector(tokens))
for piece in i:
    sm.send(piece)

The code above collects all tokens as tuples in tokens and I assume there is no difference between .append() and .add() in the original code.

Answer 8

The way I've done this is as follows...

condition = True
while condition:
     do_stuff()
     condition = (<something that evaluates to True or False>)

This seems to me to be the simplistic solution, I'm surprised I haven't seen it here already. This can obviously also be inverted to

while not condition:

etc.

Answer 9

Python 3.8 has the answer.

It's called assignment expressions. from the documentation:

# Loop over fixed length blocks
while (block := f.read(256)) != '':
    process(block)

Answer 10

for a do - while loop containing try statements

loop = True
while loop:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       loop = False  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        loop = False
   finally:
        more_generic_stuff()

alternatively, when there's no need for the 'finally' clause

while True:
    generic_stuff()
    try:
        questionable_stuff()
#       to break from successful completion
#       break  
    except:
        optional_stuff()
#       to break from unsuccessful completion - 
#       the case referenced in the OP's question
        break

Answer 11

While loop:

while condition:
  print("hello")
  

Do while loop:

while True:
  print("hello")
  if not condition:
    break

Also you can use any true boolean value as condition:

while 1:
  print("hello")
  if not condition:
    break

Another variant:

check = 1
while check:
    print("hello")
    check = condition

Answer 12

Quick hack:

def dowhile(func = None, condition = None):
    if not func or not condition:
        return
    else:
        func()
        while condition():
            func()

Use like so:

>>> x = 10
>>> def f():
...     global x
...     x = x - 1
>>> def c():
        global x
        return x > 0
>>> dowhile(f, c)
>>> print x
0

Answer 13

while condition is True: 
  stuff()
else:
  stuff()

Answer 14

Why don't you just do

for s in l :
    print s
print "done"

?

Answer 15

You wondered:

What can I do in order to catch the 'stop iteration' exception and break a while loop properly?

You could do it as shown below and which also makes use of the assignment expressions feature (aka “the walrus operator”) that was introduced in Python 3.8:

list_of_ints = [1, 2, 3]
iterator = iter(list_of_ints)

try:
    while (element := next(iterator)):
        print(element)
except StopIteration:
    print("done")

Another possibility (that would work from Python 2.6 to 3.x) would be to provide a default argument to the built-in next() function to avoid the StopIteration exception:

SENTINEL = object()  # Unique object.
list_of_ints = [1, 2, 3]
iterator = iter(list_of_ints)

while True:
    element = next(iterator, SENTINEL)
    if element is SENTINEL:
        break
    print(element)

print("done")

Answer 16

You can clean things up a bit with the walrus operator in Python 3.8:

list_of_ints = [ 1, 2, None, 3 ]
iterator = iter(list_of_ints)

_sentinel = object()
while True:
    if (i := next(iterator, _sentinel)) is _sentinel:
        break

    print(i)

This has no duplicated logic outside the while. It also handles values in the list that evaluate to False.

Answer 17

If you're in a scenario where you are looping while a resource is unavaliable or something similar that throws an exception, you could use something like

import time

while True:
    try:
       f = open('some/path', 'r')
    except IOError:
       print('File could not be read. Retrying in 5 seconds')   
       time.sleep(5)
    else:
       break

Answer 18

For me a typical while loop will be something like this:

xBool = True
# A counter to force a condition (eg. yCount = some integer value)

while xBool:
    # set up the condition (eg. if yCount > 0):
        (Do something)
        yCount = yCount - 1
    else:
        # (condition is not met, set xBool False)
        xBool = False

I could include a for..loop within the while loop as well, if situation so warrants, for looping through another set of condition.

Answer 19

while True:
    try:
        # stuff
        stuff_1()
        if some_cond:
            continue
        if other_cond:
            break
        stuff_2()
    finally:
        # condition
        if not condition:
            break

• [x] condition checked only after running stuff
• [x] stuff is not a function call
• [x] condition is not a function call
• [x] stuff can contain flow control
• [ ] Avoid checking condition if stuff called break (can be done with another boolean)

Answer 20

See if this helps :

Set a flag inside the exception handler and check it before working on the s.

flagBreak = false;
while True :

    if flagBreak : break

    if s :
        print s
    try :
        s = i.next()
    except StopIteration :
        flagBreak = true

print "done"

Answer 21

The built-in iter function does specifically that:

for x in iter(YOUR_FN, TERM_VAL):
    ...

E.g. (tested in Py2 and 3):

class Easy:
  X = 0
  @classmethod
  def com(cls):
    cls.X += 1
    return cls.X

for x in iter(Easy.com, 10):
  print(">>>", x)

If you want to give a condition to terminate instead of a value, you always can set an equality, and require that equality to be True.