How to select 1d array from 2d array?

Question

I have 2d array and want to select only first element of it, which is 1d array.
How do I do that?

Answer 1

To get the first slice of an array:

SELECT my_arr[1:1];

The resulting array has the same array dimensions as the input.
Details in my previous answer here:

• Unnest array by one level

To flatten the result:

SELECT ARRAY(SELECT unnest(my_arr[1:1]));

Or cleaner:

SELECT ARRAY(SELECT * FROM unnest(my_arr)[1:1]));

Examples

SELECT (ARRAY[[1,2,3], [4,5,6], [7,8,9]])[1:1];

Result:

{{1,2,3}}  -- 2D array

Or:

SELECT ARRAY(
   SELECT unnest((ARRAY[[1,2,3], [4,5,6], [7,8,9]])[1:1])
   );

Result:

{1,2,3}  -- 1D array

Emulate unnest() in Postgres 8.3

The Wiki page you are linking to was a bit misleading. I updated it with code for 2-dimensional arrays.

unnest() for 1-dimensional array:

CREATE OR REPLACE FUNCTION unnest_1d(anyarray)
  RETURNS SETOF anyelement
  LANGUAGE sql IMMUTABLE AS
$func$
SELECT $1[i]
FROM   generate_series(array_lower($1,1), array_upper($1,1)) i
$func$;

unnest() for 2-dimensional array:

CREATE OR REPLACE FUNCTION unnest_2d(anyarray)
  RETURNS SETOF anyelement
  LANGUAGE sql IMMUTABLE AS
$func$
SELECT $1[d1][d2]
FROM   generate_series(array_lower($1,1), array_upper($1,1)) d1
    ,  generate_series(array_lower($1,2), array_upper($1,2)) d2
$func$;

The aggregate function array_agg() is not installed by default in Postgres 8.3:

CREATE AGGREGATE array_agg(anyelement) (
 SFUNC = array_append,
 STYPE = anyarray,
 INITCOND = '{}'
);

Unnest 2d array to 1d arrays:

CREATE OR REPLACE FUNCTION unnest_2d_1d(anyarray)
  RETURNS SETOF anyarray
  LANGUAGE sql IMMUTABLE AS
$func$
SELECT array_agg($1[d1][d2])
FROM   generate_series(array_lower($1,1), array_upper($1,1)) d1
    ,  generate_series(array_lower($1,2), array_upper($1,2)) d2
GROUP  BY d1
ORDER  BY d1
$func$;

fiddle
_{Old sqlfiddle}