Are there any classes/functions available to be used for easy JSON escaping? I'd rather not have to write my own.
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5JsonConvert.ToString() worked for me. – Martin Lottering Mar 30 '17 at 19:57
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@MartinLottering Thank you!!! I have been looking for a way to get json to a formatted string. None of the answers below worked, but this did. – GhostShaman Oct 24 '20 at 00:41
16 Answers
I use System.Web.HttpUtility.JavaScriptStringEncode
string quoted = HttpUtility.JavaScriptStringEncode(input);

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5I used this to avoid the missing `System.Web.Helpers.Json.Encode` in VS2015, but it needs the `(input, true)` parameter to include the actual quotes as well. – lapo Jun 22 '16 at 14:37
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2I notice that this will encode single quotes ' as `\u0027`. However single quotes are valid in a JSON string. – Stacey Jun 16 '21 at 08:01
For those using the very popular Json.Net project from Newtonsoft the task is trivial:
using Newtonsoft.Json;
....
var s = JsonConvert.ToString(@"a\b");
Console.WriteLine(s);
....
This code prints:
"a\\b"
That is, the resulting string value contains the quotes as well as the escaped backslash.

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2I cannot reproduce this method for deserializing an encoded and escaped unc path. My path `"WatchedPath": "\\\\myserver\\output"` becomes `"\"\\\\\\\\myserver\\\\output\""` which is pretty unacceptable. – slestak Dec 29 '14 at 14:36
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3The method above is not for deserializing - rater it is used when you want to create a JSON text manually and you have a C# string and need to gets its proper representation as a text. – Dror Harari Dec 30 '14 at 22:50
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@slestak, I think I am facing the same issue you were here. Did you find a solution? – GP24 Feb 11 '16 at 11:50
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No problem, thanks for replying. I did this if it helps you: yourAnnoyingDoubleEncodedString.Replace("\\\\", "\\").Replace("\\\"", "\""); – GP24 Feb 11 '16 at 15:24
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This worked for me, but adding the outer quotes was a problem, since this is within code manually handling json-style text. I did this, then removed the outer quotes. – goodeye Mar 09 '19 at 01:44
Building on the answer by Dejan, what you can do is import System.Web.Helpers
.NET Framework assembly, then use the following function:
static string EscapeForJson(string s) {
string quoted = System.Web.Helpers.Json.Encode(s);
return quoted.Substring(1, quoted.Length - 2);
}
The Substring
call is required, since Encode
automatically surrounds strings with double quotes.

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5This is part of ASP.NET Web Pages 2.0. It can be added using NuGet. It is not part of the framework. – Murven Dec 24 '16 at 17:37
Yep, just add the following function to your Utils class or something:
public static string cleanForJSON(string s)
{
if (s == null || s.Length == 0) {
return "";
}
char c = '\0';
int i;
int len = s.Length;
StringBuilder sb = new StringBuilder(len + 4);
String t;
for (i = 0; i < len; i += 1) {
c = s[i];
switch (c) {
case '\\':
case '"':
sb.Append('\\');
sb.Append(c);
break;
case '/':
sb.Append('\\');
sb.Append(c);
break;
case '\b':
sb.Append("\\b");
break;
case '\t':
sb.Append("\\t");
break;
case '\n':
sb.Append("\\n");
break;
case '\f':
sb.Append("\\f");
break;
case '\r':
sb.Append("\\r");
break;
default:
if (c < ' ') {
t = "000" + String.Format("X", c);
sb.Append("\\u" + t.Substring(t.Length - 4));
} else {
sb.Append(c);
}
break;
}
}
return sb.ToString();
}

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3
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I know this is an old answer and I'm happy to see this was given as I didn't want to rely on any external libraries, but I noticed that the default case for a control character will always return "\\u000X". I believe you need to cast the char first to an int. Consider replacing it with `string t = "000" + ((int)c).ToString("X");` – Jan Discart Dec 22 '18 at 19:18
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1The correct default case must be: `t = "000" + String.Format("{0:X}",(int) c);` – daniatic Apr 14 '20 at 13:03
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1What we actually want is " `"\\u" + ((int)c).ToString("X4")` (Although I think two Appends would be even better) – James Curran Nov 04 '20 at 04:53
I have used following code to escape the string value for json. You need to add your '"' to the output of the following code:
public static string EscapeStringValue(string value)
{
const char BACK_SLASH = '\\';
const char SLASH = '/';
const char DBL_QUOTE = '"';
var output = new StringBuilder(value.Length);
foreach (char c in value)
{
switch (c)
{
case SLASH:
output.AppendFormat("{0}{1}", BACK_SLASH, SLASH);
break;
case BACK_SLASH:
output.AppendFormat("{0}{0}", BACK_SLASH);
break;
case DBL_QUOTE:
output.AppendFormat("{0}{1}",BACK_SLASH,DBL_QUOTE);
break;
default:
output.Append(c);
break;
}
}
return output.ToString();
}

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9Do not use this code in production! This JSON escaping misses important special characters. See: http://stackoverflow.com/a/33799784 – vog Nov 19 '15 at 11:49
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2This code does not cover all the special cases. DO NOT use in production. – Envil Sep 08 '16 at 04:49
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3reinvent the wheel, and introduce some bug in special cases, is not a good answer – Xilmiki Oct 19 '16 at 09:47
The methods offered here are faulty.
Why venture that far when you could just use System.Web.HttpUtility.JavaScriptEncode ?
If you're on a lower framework, you can just copy paste it from mono
Courtesy of the mono-project @ https://github.com/mono/mono/blob/master/mcs/class/System.Web/System.Web/HttpUtility.cs
public static string JavaScriptStringEncode(string value, bool addDoubleQuotes)
{
if (string.IsNullOrEmpty(value))
return addDoubleQuotes ? "\"\"" : string.Empty;
int len = value.Length;
bool needEncode = false;
char c;
for (int i = 0; i < len; i++)
{
c = value[i];
if (c >= 0 && c <= 31 || c == 34 || c == 39 || c == 60 || c == 62 || c == 92)
{
needEncode = true;
break;
}
}
if (!needEncode)
return addDoubleQuotes ? "\"" + value + "\"" : value;
var sb = new System.Text.StringBuilder();
if (addDoubleQuotes)
sb.Append('"');
for (int i = 0; i < len; i++)
{
c = value[i];
if (c >= 0 && c <= 7 || c == 11 || c >= 14 && c <= 31 || c == 39 || c == 60 || c == 62)
sb.AppendFormat("\\u{0:x4}", (int)c);
else switch ((int)c)
{
case 8:
sb.Append("\\b");
break;
case 9:
sb.Append("\\t");
break;
case 10:
sb.Append("\\n");
break;
case 12:
sb.Append("\\f");
break;
case 13:
sb.Append("\\r");
break;
case 34:
sb.Append("\\\"");
break;
case 92:
sb.Append("\\\\");
break;
default:
sb.Append(c);
break;
}
}
if (addDoubleQuotes)
sb.Append('"');
return sb.ToString();
}
This can be compacted into
// https://github.com/mono/mono/blob/master/mcs/class/System.Json/System.Json/JsonValue.cs
public class SimpleJSON
{
private static bool NeedEscape(string src, int i)
{
char c = src[i];
return c < 32 || c == '"' || c == '\\'
// Broken lead surrogate
|| (c >= '\uD800' && c <= '\uDBFF' &&
(i == src.Length - 1 || src[i + 1] < '\uDC00' || src[i + 1] > '\uDFFF'))
// Broken tail surrogate
|| (c >= '\uDC00' && c <= '\uDFFF' &&
(i == 0 || src[i - 1] < '\uD800' || src[i - 1] > '\uDBFF'))
// To produce valid JavaScript
|| c == '\u2028' || c == '\u2029'
// Escape "</" for <script> tags
|| (c == '/' && i > 0 && src[i - 1] == '<');
}
public static string EscapeString(string src)
{
System.Text.StringBuilder sb = new System.Text.StringBuilder();
int start = 0;
for (int i = 0; i < src.Length; i++)
if (NeedEscape(src, i))
{
sb.Append(src, start, i - start);
switch (src[i])
{
case '\b': sb.Append("\\b"); break;
case '\f': sb.Append("\\f"); break;
case '\n': sb.Append("\\n"); break;
case '\r': sb.Append("\\r"); break;
case '\t': sb.Append("\\t"); break;
case '\"': sb.Append("\\\""); break;
case '\\': sb.Append("\\\\"); break;
case '/': sb.Append("\\/"); break;
default:
sb.Append("\\u");
sb.Append(((int)src[i]).ToString("x04"));
break;
}
start = i + 1;
}
sb.Append(src, start, src.Length - start);
return sb.ToString();
}
}

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This will also escape triangle brackets. Important for JS in HTML but not for JSON encoding per-se. – Luke Briner Mar 08 '22 at 09:34
In .Net Core 3+ and .Net 5+:
string escapedJsonString = JsonEncodedText.Encode(jsonString);

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3You need to mention that this does not do trivial escaping by default and the result might be much more escaped than you want. For example, quotes, triangle brackets and many letters will be converted to unicode characters and will only be usable if you unescape at the other end. – Luke Briner Mar 08 '22 at 09:43
I ran speed tests on some of these answers for a long string and a short string. Clive Paterson's code won by a good bit, presumably because the others are taking into account serialization options. Here are my results:
Apple Banana
System.Web.HttpUtility.JavaScriptStringEncode: 140ms
System.Web.Helpers.Json.Encode: 326ms
Newtonsoft.Json.JsonConvert.ToString: 230ms
Clive Paterson: 108ms
\\some\long\path\with\lots\of\things\to\escape\some\long\path\t\with\lots\of\n\things\to\escape\some\long\path\with\lots\of\"things\to\escape\some\long\path\with\lots"\of\things\to\escape
System.Web.HttpUtility.JavaScriptStringEncode: 2849ms
System.Web.Helpers.Json.Encode: 3300ms
Newtonsoft.Json.JsonConvert.ToString: 2827ms
Clive Paterson: 1173ms
And here is the test code:
public static void Main(string[] args)
{
var testStr1 = "Apple Banana";
var testStr2 = @"\\some\long\path\with\lots\of\things\to\escape\some\long\path\t\with\lots\of\n\things\to\escape\some\long\path\with\lots\of\""things\to\escape\some\long\path\with\lots""\of\things\to\escape";
foreach (var testStr in new[] { testStr1, testStr2 })
{
var results = new Dictionary<string,List<long>>();
for (var n = 0; n < 10; n++)
{
var count = 1000 * 1000;
var sw = Stopwatch.StartNew();
for (var i = 0; i < count; i++)
{
var s = System.Web.HttpUtility.JavaScriptStringEncode(testStr);
}
var t = sw.ElapsedMilliseconds;
results.GetOrCreate("System.Web.HttpUtility.JavaScriptStringEncode").Add(t);
sw = Stopwatch.StartNew();
for (var i = 0; i < count; i++)
{
var s = System.Web.Helpers.Json.Encode(testStr);
}
t = sw.ElapsedMilliseconds;
results.GetOrCreate("System.Web.Helpers.Json.Encode").Add(t);
sw = Stopwatch.StartNew();
for (var i = 0; i < count; i++)
{
var s = Newtonsoft.Json.JsonConvert.ToString(testStr);
}
t = sw.ElapsedMilliseconds;
results.GetOrCreate("Newtonsoft.Json.JsonConvert.ToString").Add(t);
sw = Stopwatch.StartNew();
for (var i = 0; i < count; i++)
{
var s = cleanForJSON(testStr);
}
t = sw.ElapsedMilliseconds;
results.GetOrCreate("Clive Paterson").Add(t);
}
Console.WriteLine(testStr);
foreach (var result in results)
{
Console.WriteLine(result.Key + ": " + Math.Round(result.Value.Skip(1).Average()) + "ms");
}
Console.WriteLine();
}
Console.ReadLine();
}

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I would also recommend using the JSON.NET library mentioned, but if you have to escape unicode characters (e.g. \uXXXX format) in the resulting JSON string, you may have to do it yourself. Take a look at Converting Unicode strings to escaped ascii string for an example.

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I nice one-liner, used JsonConvert as others have but added substring to remove the added quotes and backslash.
var escapedJsonString = JsonConvert.ToString(JsonString).Substring(1, JsonString.Length - 2);

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I think you mean var escapedJsonString = JsonConvert.ToString(JsonString).Substring(1, JsonString.Length); - otherwise you chop 2 characters off the end of your string. Remember, the \" are additional characters to the length of the original. – Bertie Jul 01 '21 at 13:37
What about System.Web.Helpers.Json.Encode(...) (see http://msdn.microsoft.com/en-us/library/system.web.helpers.json.encode(v=vs.111).aspx)?

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String.Format("X", c);
That just outputs: X
Try this instead:
string t = ((int)c).ToString("X");
sb.Append("\\u" + t.PadLeft(4, '0'));

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I chose to use System.Web.Script.Serialization.JavaScriptSerializer
.
I have a small static helper class defined as follows:
internal static partial class Serialization
{
static JavaScriptSerializer serializer;
static Serialization()
{
serializer = new JavaScriptSerializer();
serializer.MaxJsonLength = Int32.MaxValue;
}
public static string ToJSON<T>(T obj)
{
return serializer.Serialize(obj);
}
public static T FromJSON<T>(string data)
{
if (Common.IsEmpty(data))
return default(T);
else
return serializer.Deserialize<T>(data);
}
}
To serialize anything I just call Serialization.ToJSON(itemToSerialize)
To deserialize I just call Serialization.FromJSON<T>(jsonValueOfTypeT)

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.NET 6 - System.Text.Json
var encodedText = JsonEncodedText.Encode(inputText);

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The C# method bellow is a more advanced optimization version using Span for small string inputs, to avoid heap allocation and StringBuilder for larger inputs to avoids excessive stack usage.
public static string JsonEscape(string text) {
if (text.Length == 0) {
return string.Empty;
}
if (text.Length < 1204) {
int count = 0;
foreach (char c in text) {
switch (c) {
case '\\':
case '\"':
case '\b':
case '\f':
case '\n':
case '\r':
case '\t':
count += 2;
break;
default:
count++;
break;
}
}
Span<char> result = stackalloc char[count];
count = 0;
foreach (char c in text) {
switch (c) {
case '\\':
case '\"':
case '\b':
case '\f':
case '\n':
case '\r':
case '\t':
result[count++] = '\\';
result[count++] = c;
break;
default:
result[count++] = c;
break;
}
}
return result.ToString();
}
StringBuilder sb = new StringBuilder();
foreach (char c in text) {
switch (c) {
case '\\': sb.Append("\\\\"); break;
case '\"': sb.Append("\\\""); break;
case '\b': sb.Append("\\\b"); break;
case '\f': sb.Append("\\\f"); break;
case '\n': sb.Append("\\\n"); break;
case '\r': sb.Append("\\\r"); break;
case '\t': sb.Append("\\\t"); break;
default: sb.Append(c); break;
}
}
return sb.ToString();
}

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