The callback function in Array.map
has three parameters:
From the same Mozilla page that you linked to:
callback is invoked with three arguments: the value of the element, the index of the element, and the Array object being traversed."
So if you call a function parseInt
which actually expects two arguments, the second argument will be the index of the element.
In this case, you ended up calling parseInt
with radix 0, 1 and 2 in turn. The first is the same as not supplying the parameter, so it defaulted based on the input (base 10, in this case). Base 1 is an impossible number base, and 3 is not a valid number in base 2:
parseInt('1', 0); // OK - gives 1
parseInt('2', 1); // FAIL - 1 isn't a legal radix
parseInt('3', 2); // FAIL - 3 isn't legal in base 2
So in this case, you need the wrapper function:
['1','2','3'].map(function(num) { return parseInt(num, 10); });
or with ES2015+ syntax:
['1','2','3'].map(num => parseInt(num, 10));
(In both cases, it's best to explicitly supply a radix to parseInt
as shown, because otherwise it guesses the radix based on the input. In some older browsers, a leading 0 caused it to guess octal, which tended to be problematic. It will still guess hex if the string starts with 0x
.)