Serialize Java List to XML using Jackson XML mapper

Question

Hi I need to create an XML from JAVA using Jackson-dataformat XMLMapper. The XML should be like

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>Hong Kong</city>
      <state>Hong Kong</state>
    </addresses>
</Customer>

But I get it always like with an extra "< addresses> < /addresses>" tag.

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
<addresses>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>Hong Kong</city>
      <state>Hong Kong</state>
    </addresses>
<addresses>
</Customer>

I am using below code to create XML

JaxbAnnotationModule jaxbAnnotationModule = new JaxbAnnotationModule();
XmlMapper mapper = new XmlMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
mapper.registerModule(jaxbAnnotationModule);
mapper.registerModule(new GuavaModule());
String xml = mapper.writeValueAsString(customer);
System.out.println(xml);

Please can some one help me? How can I remove the extra tag please. I have tried to use @XmlElement but it does not help help. TIA!!

You are having list of address(Multiple) in customer class. so you need to have parent node addresses and its child node will be adress. — ManojP, Nov 26 '14 at 08:13
Thx Manoj, but I do not want any parental node. Can we somehow omit the parental node? — Sharmistha Sinha, Nov 26 '14 at 08:15
I got the answer - Just need to use @JacksonXmlElementWrapper(useWrapping = false) Thx for spending time to read it. — Sharmistha Sinha, Nov 26 '14 at 08:45

ManojP · Accepted Answer · 2022-10-18T06:42:14.253

Try the below code

@JacksonXmlRootElement(localName = "customer") 
class Customer {

    @JacksonXmlProperty(localName = "id")
    private int id;
    @JacksonXmlProperty(localName = "name")
    private String  name;

    @JacksonXmlProperty(localName = "addresses")
    @JacksonXmlElementWrapper(useWrapping = false)
    private Address[] address;

    // you can add it on getter method instead of declaration.  
    @JacksonXmlElementWrapper(useWrapping = false)
    public Address[] getAddress(){ 
        return address;
   }

   //getters, setters, toString             
}

class Address {

    @JacksonXmlProperty(localName = "city")
    private String city;

    @JacksonXmlProperty(localName = "state")
    private String state;
    // getter/setter 
}

score 6 · Answer 2 · answered Sep 09 '17 at 20:21

6

This setting changes default wrapping behavior, if you don't want to deal with annotation everywhere in your code.

XmlMapper mapper = new XmlMapper();
mapper.setDefaultUseWrapper(false);

answered Sep 09 '17 at 20:21

A Kunin

42,385
1
17
13

This doesn't work, atleast on version 2.15.2 of Jackson. – Sandeep Aug 19 '23 at 14:07

score 3 · Answer 3 · answered Oct 03 '16 at 00:15

3

Just to add to ManojP's answer, if adding the @JacksonXmlElementWrapper(useWrapping = false) on the declaration of your variable doesn't work (which was the case for me), adding it to the getter method will do the trick.

answered Oct 03 '16 at 00:15

alphathesis

199
2
12

Serialize Java List to XML using Jackson XML mapper

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