unable to get $_SESSION variable

Question

this error
In Log-in.php I have

  $email=$_POST['email']; 
  $pass=$_POST['pass'];
  $_SESSION['type'] = 'user';
  $_SESSION['email'] = $email; 
  $_SESSION['pass']=$pass; 
  header('location:./connect.php');

I am getting error like undefined index email for other user log-in, at other side I can log-in as admin here..

I have a log-in form that see rather what kind of log-in is this and pass that type in session in this connect.php its check what kind of type it is and then proceed it was working well but unfortunately getting error can't modify anymore.

log-in form is one form for user, admin and agents, where I am able to log-in as admin but I am not able to login as other it shows error

if(empty($_SESSION))
{
   session_regenerate_id();
   session_start();
}
@mysql_connect('localhost','root','') or die("ERROR in SERVER");
@mysql_select_db('module') or die("ERROR IN DATABASE");

    $_SESSION['start'] = time(); // taking now logged in time

    if(!isset($_SESSION['expire'])){
        $_SESSION['expire'] = $_SESSION['start'] + (60* 60) ; // ending a session in 30 seconds
    }
    $now = time(); // checking the time now when home page starts

    if($now > $_SESSION['expire'])
    {
        session_destroy();

    }

if(!empty($_SESSION['type']))
{
$email = $_SESSION['email'];
$pass = $_SESSION['pass'];
$type = $_SESSION['type'];


// admin login //
if($type == 'admin'){




$admin = mysql_query("SELECT * FROM `admin` WHERE `email` ='$email' ");
$res = mysql_fetch_array($admin);
if($email == "" || $pass == "" || $email != $res['email'] || $pass != $res['pass'])
{
    header('location:./login/login.php');
}

}


// user login //
if($type == 'user')
{
     $email = $_SESSION['email'];
     $pass = $_SESSION['pass'];
     $type = $_SESSION['type'];
    $user = mysql_query("SELECT `id` FROM `users` WHERE `email`='$email' AND `status`='1'");
    $useres = mysql_fetch_array($user);
   // $trail = $useres['date'];
  //  $time = explode("/",$trail);


    if($email != $useres['email'] || $pass != $useres['pass'])

    {
        echo mysql_error();
//        header('location:./login/login.php');
    }

    else if($pass = $useres['pass']){
//        echo '<script> location.replace("./user.php"); </script>';
    }
}


// agent login //
if($type == 'agent')
{

    $email = $_SESSION['email'];
     $pass = $_SESSION['pass'];
     $type = $_SESSION['type'];
    $agent = mysql_query("SELECT `id` FROM `sale_agents` WHERE `email`='$email'");
    $agentres = mysql_fetch_array($agent);
    if($email != $agentres['email'] || $pass != $agentres['pass'])
    {
        header('location:./login/login.php');

    }
    else if($pass = $agentres['pass']){
   //     echo '<script> location.replace("./agent.php"); </script>';
    }
}
}
else{
    header('location:./login/login.php');
}

In one way I am getting error in other way page is also displaying email what to do now? enter image description here

you show where set a variable to the value of `$_SESSION['email']`, but where do you set `$_SESSION['email']`? — Sean, Dec 20 '14 at 06:20
just for information for you. `mysql_* function is deprecated`. Read this [article](http://php.net/manual/en/function.mysql-connect.php). The answer is your question is just like the error said that you have not defined index for email in session — Hendry Tanaka, Dec 20 '14 at 06:22
@Sean i am using `$_SESSION['email']` for `$email` and using it to validating log-in in `SQL` — Talha Habib, Dec 20 '14 at 06:24
well your error `undefined index email` means that you have not set it prior to trying to use it in `$email = $_SESSION['email'];`. So where in your code do you do `$_SESSION['email'] = SOME VALUE;`? — Sean, Dec 20 '14 at 06:25
`$email=$_POST['email'];` `$pass=$_POST['pass'];` `$_SESSION['type'] = 'user';` `$_SESSION['email'] = $email;` `$_SESSION['pass']=$pass;` `header('location:./connect.php');` well that is like this @Sean — Talha Habib, Dec 20 '14 at 06:34

score 10 · Accepted Answer · edited Jun 20 '20 at 09:12

10

Sessions Step By Step

Defining session before everything, No output should be before that, NO OUTPUT
```
<?php
session_start();
?>
```

Set your session in a page and then you have access in that, for example this is page 1.php

<?php
   //This is page 1 and then we will use session that defined from this page:
    session_start();
    $_SESSION['email]='email@example.com';
?>

Using and Getting session in 2.php

 <?php
   //In this page I am going to use session:
  session_start();
  if($_SESSION['email']){
  echo 'Your Email Is Here!  :) ';
  }
 ?>

NOTE: Comments don't have output.

Maybe answer to your question:

I think you are not setting session, and because of that PHP doesn't know that session variable.

Your login should be like this

  <?php
  session_start();
  $email=$_POST['email']; 
  $pass=$_POST['pass'];
  $_SESSION['type'] = 'user';
  $_SESSION['email'] = $email; 
  $_SESSION['pass']=$pass; 
  header('location:./connect.php');
  ?>

edited Jun 20 '20 at 09:12

Community

1
1

answered Dec 20 '14 at 06:31

Mohammad Kermani

5,188
7
37
61

@user4238306 OK, Please let mo to check it again – Mohammad Kermani Dec 20 '14 at 06:51
@user4238306 I tested in My own computer, But I did't found any error (I just found an DB error) – Mohammad Kermani Dec 20 '14 at 06:55
check images i attached with question, Thank you. – Talha Habib Dec 20 '14 at 07:08
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/67369/discussion-between-multi-thinker-and-kermani). – Talha Habib Dec 20 '14 at 07:26

score 0 · Answer 2 · answered Dec 20 '14 at 08:39

Set this code in login.php :

session_start();
$email = $_POST['email'];
$pass = $_POST['pass'];
$_SESSION['type'] = 'user';
$_SESSION['email'] = $email;
$_SESSION['pass'] = $pass;
header('location:./connect.php');

And this one in connect.php :

session_start();
@mysql_connect('localhost', 'root', '') or die("ERROR in SERVER");
@mysql_select_db('module') or die("ERROR IN DATABASE");
$_SESSION['start'] = time(); // taking now logged in time
if (!isset($_SESSION['expire'])) {
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60);
}
$now = time(); // checking the time now when home page starts
if ($now > $_SESSION['expire']) {
    session_destroy();
    header('location:./login/login.php');
}
if (isset($_SESSION['email']) && !empty($_SESSION['email']) &&
        isset($_SESSION['pass']) && !empty($_SESSION['pass']) &&
        isset($_SESSION['type']) && !empty($_SESSION['type'])) {

    $email = $_SESSION['email'];
    $pass = $_SESSION['pass'];
    $type = $_SESSION['type'];

    // admin login //
    if ($type == 'admin') {
        $admin = mysql_query("SELECT * FROM `admin` WHERE `email`='$email'");
        $res = mysql_fetch_array($admin);
        if ($email == "" || $pass == "" || $email != $res['email'] || $pass != $res['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }

    // user login //
    if ($type == 'user') {
        $user = mysql_query("SELECT `id` FROM `users` WHERE `email`='$email' AND `status`='1'");
        $useres = mysql_fetch_array($user);
        // $trail = $useres['date'];
        //  $time = explode("/",$trail);
        if ($email != $useres['email'] || $pass != $useres['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }

    // agent login //
    if ($type == 'agent') {
        $agent = mysql_query("SELECT `id` FROM `sale_agents` WHERE `email`='$email'");
        $agentres = mysql_fetch_array($agent);
        if ($email != $agentres['email'] || $pass != $agentres['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }
} else {
    header('location:./login/login.php');
}

I hope this will help you.

score 0 · Answer 3 · answered Dec 22 '18 at 07:01

session_start();

$_SESSION["user"] = $result['full_name'];
$_SESSION["user_id"] = $result['user_id'];
$_SESSION["website_type"] = $result['user_id'];

// this is my code ... // i cant access in another page ..

// second page enter code here session_start(); // print_r($_SESSION);

    echo $_SESSION['user'];
    echo $_SESSION['user_id'];
    echo $_SESSION['website_type'];

unable to get $_SESSION variable

3 Answers3

Sessions Step By Step

Maybe answer to your question:

Linked