I need to create a subscription to an Observable that is immediately disposed of when it is first called.
Is there something like:
observable.subscribeOnce(func);
My use case, I am creating a subscription in an express route handler and the subscription is being called multiple times per request.
Not 100% certain about what you need, but if you only want to observe the first value, then use either first() or take(1):
observable.first().subscribe(func);
note: .take(1) and .first() both unsubscribe automatically when their condition is met
From comment by Coderer.
import { first } from 'rxjs/operators'
observable
.pipe(first())
.subscribe(func);
RxJS has some of the best documentation I've ever come across. Following the bellow link will take you to an exceedingly helpful table mapping use cases to operators. For instance, under the "I want to take the first value" use case are three operators: first, firstOrDefault, and sample.
Note, if an observable sequence completes with no notifications, then the first operator notifies subscribers with an error while the firstOrDefault operator provides a default value to subscribers.
UPDATE(DEC/2021):
As toPromise() function has been deprecated in RxJS 7, new functions have been announced to be used instead of it. firstValueFrom and lastValueFrom.
firsValueFrom function resolves the first emitted value and directly unsubscribe from the resource. It rejects with an EmptyError when the Observable completes without emitting any value.
On the other hand, lastValueFrom function is, to a certain degree, same to toPromise() as it resolves the last value emitted when the observable completes. However, if the observable doesn't emit any value, it will reject with an EmptyError. Unlike toPromise() which resolve undefined when no value emits.
For more information, please check the docs.
Old Answer:
If you want to call an Observable only one time, it means you are not going to wait for a stream from it. So using toPromise() instead of subscribe() would be enough in your case as toPromise() doesn't need unsubscription.
To supplement @Brandon's answer, using first() or the like is also essential for updating a BehaviorSubject based on its Observable. For example (untested):
var subject = new BehaviorSubject({1:'apple',2:'banana'});
var observable = subject.asObservable();
observable
.pipe(
first(), // <-- Ensures no stack overflow
flatMap(function(obj) {
obj[3] = 'pear';
return of(obj);
})
)
.subscribe(function(obj) {
subject.next(obj);
});
Expanding on M Fuat NUROĞLU's amazing answer on converting the observable to a promise, here's the very convenient version of it.
const value = await observable.toPromise();
console.log(value)
The beauty of this is that we can use that value like a normal variable without introducing another nested block!
This is especially handy when you need to get multiple values from multiple observables. Neat and clean.
const content = await contentObservable.toPromise();
const isAuthenticated = await isAuthenticatedObservable.toPromise();
if(isAuthenticated){
service.foo(content)
}
Of course, you will have to make your containing function async if you are to go with this route. You can also just .then the promise if you don't want the containing function to be async
I'm not sure if there are tradeoffs with this approach, feel free to let me know in the comments so we are aware.
P.S. If you liked this answer, don't forget to upvote M Fuat NUROĞLU's Answer as well :)
I had similar question.
Below was called even later on from different state changers. As I did not want to.
function foo() {
// this was called many times which was not needed
observable.subscribe(func);
changeObservableState("new value");
}
I decided to try unsubscribe() after subscribe as below.
function foo() {
// this was called ONE TIME
observable.subscribe(func).unsubscribe();
changeObservableState("new value");
}
subscribe(func).unsubscribe(); is like subscribeOnce(func).
I hope that helped you too.
observable.pipe(take(1)).subscribe() use take 1 it subscribe for one time then exit
