Get String in YYYYMMDD format from JS date object?

Question

I'm trying to use JS to turn a date object into a string in YYYYMMDD format. Is there an easier way than concatenating Date.getYear(), Date.getMonth(), and Date.getDay()?

Answer 1

Altered piece of code I often use:

Date.prototype.yyyymmdd = function() {
  var mm = this.getMonth() + 1; // getMonth() is zero-based
  var dd = this.getDate();

  return [this.getFullYear(),
          (mm>9 ? '' : '0') + mm,
          (dd>9 ? '' : '0') + dd
         ].join('');
};

var date = new Date();
date.yyyymmdd();

Answer 2

I didn't like adding to the prototype. An alternative would be:

var rightNow = new Date();
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");

<!-- Next line is for code snippet output only -->
document.body.innerHTML += res;

Answer 3

You can use the toISOString function :

var today = new Date();
today.toISOString().substring(0, 10);

It will give you a "yyyy-mm-dd" format.

Answer 4

Moment.js could be your friend

var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');

Answer 5

new Date('Jun 5 2016').
  toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
  replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');

// => '2016-06-05'

Answer 6

If you don't need a pure JS solution, you can use jQuery UI to do the job like this :

$.datepicker.formatDate('yymmdd', new Date());

I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.

Visit http://api.jqueryui.com/datepicker/ for more examples

Answer 7

This is a single line of code that you can use to create a YYYY-MM-DD string of today's date.

var d = new Date().toISOString().slice(0,10);

Answer 8

I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.

function yyyymmdd(dateIn) {
  var yyyy = dateIn.getFullYear();
  var mm = dateIn.getMonth() + 1; // getMonth() is zero-based
  var dd = dateIn.getDate();
  return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd
}

var today = new Date();
console.log(yyyymmdd(today));

Fiddle: http://jsfiddle.net/gbdarren/Ew7Y4/

Answer 9

Local time:

var date = new Date();
date = date.toJSON().slice(0, 10);

UTC time:

var date = new Date().toISOString();
date = date.substring(0, 10);

date will print 2020-06-15 today as i write this.

toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ

The code takes the first 10 characters that we need for a YYYY-MM-DD format.

If you want format without '-' use:

var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;

In .join`` you can add space, dots or whatever you'd like.

Answer 10

In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.

Also, use concat() to ensure safe concatenation of variables

Date.prototype.yyyymmdd = function() {
  var yyyy = this.getFullYear();
  var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
  var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
  return "".concat(yyyy).concat(mm).concat(dd);
};

Date.prototype.yyyymmddhhmm = function() {
  var yyyymmdd = this.yyyymmdd();
  var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();
  var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();
  return "".concat(yyyymmdd).concat(hh).concat(min);
};

Date.prototype.yyyymmddhhmmss = function() {
  var yyyymmddhhmm = this.yyyymmddhhmm();
  var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();
  return "".concat(yyyymmddhhmm).concat(ss);
};

var d = new Date();
document.getElementById("a").innerHTML = d.yyyymmdd();
document.getElementById("b").innerHTML = d.yyyymmddhhmm();
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();

<div>
  yyyymmdd: <span id="a"></span>
</div>
<div>
  yyyymmddhhmm: <span id="b"></span>
</div>
<div>
  yyyymmddhhmmss: <span id="c"></span>
</div>

Answer 11

Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:

var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');

This in response to @weberste's comment on @Pierre Guilbert's answer.

Answer 12

// UTC/GMT 0
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509

// Client local time
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509

Answer 13

Another way is to use toLocaleDateString with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:

date.toLocaleDateString('se')

To remove the delimiters (-) is just a matter of replacing the non-digits:

console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );

This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.

Answer 14

var someDate = new Date();
var dateFormated = someDate.toISOString().substr(0,10);

console.log(dateFormated);

Answer 15

dateformat is a very used package.

How to use:

Download and install dateformat from NPM. Require it in your module:

const dateFormat = require('dateformat');

and then just format your stuff:

const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');

Answer 16

A little variation for the accepted answer:

function getDate_yyyymmdd() {

    const date = new Date();

    const yyyy = date.getFullYear();
    const mm = String(date.getMonth() + 1).padStart(2,'0');
    const dd = String(date.getDate()).padStart(2,'0');

    return `${yyyy}${mm}${dd}`
}

console.log(getDate_yyyymmdd())

Answer 17

Working from @o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.

Date.prototype.getFromFormat = function(format) {
    var yyyy = this.getFullYear().toString();
    format = format.replace(/yyyy/g, yyyy)
    var mm = (this.getMonth()+1).toString(); 
    format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
    var dd  = this.getDate().toString();
    format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
    var hh = this.getHours().toString();
    format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
    var ii = this.getMinutes().toString();
    format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
    var ss  = this.getSeconds().toString();
    format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
    return format;
};

d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);

I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.

NB: I've kept the predefined class definition but you might wanna put that in a function or a custom class as per best practices.

Answer 18

Shortest

.toJSON().slice(0,10).split`-`.join``;

let d = new Date();

let s = d.toJSON().slice(0,10).split`-`.join``;

console.log(s);

Answer 19

This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format() function for the Javascript's Date object, so it can be used with familiar literal formats.

If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.

Answer 20

Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :

function toYYYYMMDD(d) {
    var yyyy = d.getFullYear().toString();
    var mm = (d.getMonth() + 101).toString().slice(-2);
    var dd = (d.getDate() + 100).toString().slice(-2);
    return yyyy + mm + dd;
}

Answer 21

You can simply use This one line code to get date in year

var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();

Answer 22

How about Day.js?

It's only 2KB, and you can also dayjs().format('YYYY-MM-DD').

https://github.com/iamkun/dayjs

Answer 23

Use padStart:

Date.prototype.yyyymmdd = function() {
    return [
        this.getFullYear(),
        (this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
        this.getDate().toString().padStart(2, '0')
    ].join('-');
};

Answer 24

[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value

or

new Date().toJSON().slice(0,10).replace(/\/|-/g,'')

Answer 25

This code is fix to Pierre Guilbert's answer:

(it works even after 10000 years)

YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")

Answer 26

Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:

function getDateInYYYYMMDD() {
    let currentDate = new Date();

    // year
    let yyyy = '' + currentDate.getFullYear();

    // month
    let mm = ('0' + (currentDate.getMonth() + 1));  // prepend 0 // +1 is because Jan is 0
    mm = mm.substr(mm.length - 2);                  // take last 2 chars

    // day
    let dd = ('0' + currentDate.getDate());         // prepend 0
    dd = dd.substr(dd.length - 2);                  // take last 2 chars

    return yyyy + "" + mm + "" + dd;
}

var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);

Answer 27

It seems that mootools provides Date().format(): https://mootools.net/more/docs/1.6.0/Types/Date

I'm not sure if it worth including just for this particular task though.

Answer 28

I usually use the code below when I need to do this.

var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
    + ('0' + (date.getMonth() + 1)).slice(-2)
    + '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written

To explain, .slice(-2) gives us the last two characters of the string.

So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.

So if the MyDate.getMonth() returns 9, it will be:

("0" + "9") // Giving us "09"

so adding .slice(-2) on that gives us the last two characters which is:

("0" + "9").slice(-2)

"09"

But if date.getMonth() returns 10, it will be:

("0" + "10") // Giving us "010"

so adding .slice(-2) gives us the last two characters, or:

("0" + "10").slice(-2)

"10"

Answer 29

From ES6 onwards you can use template strings to make it a little shorter:

var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;

This solution does not zero pad. Look to the other good answers to see how to do that.

Answer 30

If you don't mind including an additional (but small) library, Sugar.js provides lots of nice functionality for working with dates in JavaScript. To format a date, use the format function:

new Date().format("{yyyy}{MM}{dd}")

Answer 31

If using AngularJs (up to 1.5) you can use the date filter:

var formattedDate = $filter('date')(myDate, 'yyyyMMdd')

Answer 32

yyyymmdd=x=>(f=x=>(x<10&&'0')+x,x.getFullYear()+f(x.getMonth()+1)+f(x.getDate()));
alert(yyyymmdd(new Date));

Answer 33

date-shortcode to the rescue!

const dateShortcode = require('date-shortcode')
dateShortcode.parse('{YYYYMMDD}', new Date())
//=> '20180304'

Answer 34

A lot of answers here use the toisostring function. This function converts the time to zulu time before outputting, which may cause issues.

function datestring(time) {
    return new Date(time.getTime() - time.getTimezoneOffset()*60000).toISOString().slice(0,10).replace(/-/g,"")
}

mydate = new Date("2018-05-03")
console.log(datestring(mydate))

The datestring function fixes the timezone issue, or even better you can avoid the whole issue by working in zulu time:

mydate = new Date("2018-05-03Z")
// mydate = new Date(Date.UTC(2018,5,3))
console.log(mydate.toISOString().slice(0,10).replace(/-/g,""))

Answer 35

const date = new Date()

console.log(date.toISOString().split('T')[0]) // 2022-12-27

Answer 36

Here is a more generic approach which allows both date and time components and is identically sortable as either number or string.

Based on the number order of Date ISO format, convert to a local timezone and remove non-digits. i.e.:

// monkey patch version
Date.prototype.IsoNum = function (n) {
    var tzoffset = this.getTimezoneOffset() * 60000; //offset in milliseconds
    var localISOTime = (new Date(this - tzoffset)).toISOString().slice(0,-1);
    return localISOTime.replace(/[-T:\.Z]/g, '').substring(0,n || 20); // YYYYMMDD
}

Usage

var d = new Date();
// Tue Jul 28 2015 15:02:53 GMT+0200 (W. Europe Daylight Time)
console.log(d.IsoNum(8));  // "20150728"
console.log(d.IsoNum(12)); // "201507281502"
console.log(d.IsoNum());   // "20150728150253272"

Answer 37

Native Javascript:

new Date().toLocaleString('zu-ZA').slice(0,10).replace(/-/g,'');

Answer 38

Sure, you can build a specific function for each variation of date string representations. If you consider international date formats you wind up with dozens of specific functions with rediculous names and hard to distinguish.

There is no reasonable function that matches all formats, but there is a reasonable function composition that does:

const pipe2 = f => g => x =>
  g(f(x));

const pipe3 = f => g => h => x =>
  h(g(f(x)));

const invoke = (method, ...args) => o =>
  o[method] (...args);

const padl = (c, n) => s =>
  c.repeat(n)
    .concat(s)
    .slice(-n);

const inc = n => n + 1;

// generic format date function

const formatDate = stor => (...args) => date =>
  args.map(f => f(date))
    .join(stor);

// MAIN

const toYYYYMMDD = formatDate("") (
  invoke("getFullYear"),
  pipe3(invoke("getMonth")) (inc) (padl("0", 2)),
  pipe2(invoke("getDate")) (padl("0", 2)));

console.log(toYYYYMMDD(new Date()));

Yes, this is a lot of code. But you can express literally every string date representation by simply changing the function arguments passed to the higher order function formatDate. Everything is explicit and declarative i.e., you can almost read what's happening.

Answer 39

One Liner (2022) w/ Correct Timezone Offset

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON().slice(0, 10).replaceAll("-", "");

// YearMonthDay

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON().slice(0, 10).replaceAll("-", "");

console.log("YearMonthDay");
console.log(dateDisplay);

// Year-Month-Day

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON().slice(0, 10);

console.log("Year-Month-Day");
console.log(dateDisplay);

// Year-Month-Day Hour:Minute:Second

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON().slice(0, 19).replace("T", " ");

console.log("Year-Month-Day Hour:Minute:Second");
console.log(dateDisplay);

// Year-Month-Day Hour-Minute-Second

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON().slice(0, 19).replace("T", " ").replaceAll(":", "-");

console.log("Year-Month-Day Hour-Minute-Second");
console.log(dateDisplay);

// ISO-8601 standard: YYYY-MM-DDTHH:mm:ss.sssZ

var dateDisplay = new Date(Date.now() - (new Date().getTimezoneOffset() * 1000 * 60)).toJSON();

console.log("ISO-8601 standard: YYYY-MM-DDTHH:mm:ss.sssZ");
console.log(dateDisplay);

Answer 40

I've written a simple function, which can convert a Date object to String with date number, month number (with zero padding) and year number in customizable order. You can use it with any separator you like or leave this parameter empty to have no separator in output. Please, have a look.

function dateToString(date, $1, $2, $3, separator='') {
  const dateObj = {
    date: String(date.getDate()).padStart(2, '0'),
    month: String(date.getMonth() + 1).padStart(2, '0'),
    year: date.getFullYear()
  };

  return dateObj[$1] + separator + dateObj[$2] + separator + dateObj[$3];
}

const date = new Date();

const dateString1 = dateToString(date, 'year', 'month', 'date');
console.log(dateString1);

// Manipulate arguments order to get output you want
const dateString2 = dateToString(date, 'date', 'month', 'year', '-');
console.log(dateString2);

Answer 41

Here is a little improvement to the answer from https://stackoverflow.com/users/318563/o-o

Date.prototype.ddmmyyyy = function(delimiter) {
    var yyyy = this.getFullYear().toString();
    var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
    var dd  = this.getDate().toString();
    return (dd[1]?dd:"0"+dd[0]) + delimiter + (mm[1]?mm:"0"+mm[0]) + delimiter +yyyy  ; // padding
};

Hope to be helpfull for anyone!

:)

Answer 42

Try this:

function showdate(){

var a = new Date();
var b = a.getFullYear();
var c = a.getMonth();
(++c < 10)? c = "0" + c : c;
var d = a.getDate();
(d < 10)? d = "0" + d : d;
var final = b + "-" + c + "-" + d; 

return final;


} 

document.getElementById("todays_date").innerHTML = showdate();

Answer 43

this post helped me to write this helper, so I share it in case some one is looking for this solution, it supports all variations of yyyy, mm, dd

Date.prototype.formattedDate = function (pattern) {
    formattedDate = pattern.replace('yyyy', this.getFullYear().toString());
    var mm = (this.getMonth() + 1).toString(); // getMonth() is zero-based
    mm = mm.length > 1 ? mm : '0' + mm;
    formattedDate = formattedDate.replace('mm', mm);
    var dd = this.getDate().toString();
    dd = dd.length > 1 ? dd : '0' + dd;
    formattedDate = formattedDate.replace('dd', dd);
    return formattedDate;
};

d = new Date();
pattern = 'yyyymmdd';  // 20150813
d.formattedDate(pattern);

pattern = 'yyyy-mm-dd';
d.formattedDate(pattern); // 2015-08-13

Answer 44

Date.js has a lot of helpful date parsing methods.

require("datejs")

(new Date()).toString("yyyyMMdd")

Answer 45

I try to write a simple library for manipulating JavaScript date object. You can try this.

var dateString = timeSolver.getString(date, "YYYYMMDD")

Libarary here: https://github.com/sean1093/timeSolver

Answer 46

Nice, and easy:

    var date = new Date();
    var yyyy = date.getFullYear();
    var mm = date.getMonth() + 1; // getMonth() is zero-based
    if (mm < 10) mm='0'+mm;
    var dd = date.getDate();
    if (dd < 10) dd='0'+dd;
    /*date.yyyymmdd();*/

    console.log('test - '+yyyy+'-'+mm+'-'+dd);

Answer 47

The @o-o solution doesn't work in my case. My solution is the following:

Date.prototype.yyyymmdd = function() {
  var mm = this.getMonth() + 1; // getMonth() is zero-based
  var dd = this.getDate();
  var ret = [this.getFullYear(), (mm<10)?'0':'', mm, (dd<10)?'0':'', dd].join('');

  return ret; // padding
};

Answer 48

To get the local date, in a YYYYMMDD format, im using:

var todayDate = (new Date()).toLocaleString('en-GB').slice(0,10).split("\/").reverse().join("");

Answer 49

You can create yourself function as below

function toString(o, regex) {
    try {
        if (!o) return '';
        if (typeof o.getMonth === 'function' && !!regex) {
            let splitChar = regex.indexOf('/') > -1 ? '/' : regex.indexOf('-') > -1 ? '-' : regex.indexOf('.') > -1 ? '.' : '';
            let dateSeparate = regex.split(splitChar);
            let result = '';
            for (let item of dateSeparate) {
                let val = '';
                switch (item) {
                    case 'd':
                        val = o.getDate();
                        break;
                    case 'dd':
                        val = this.date2Char(o.getDate());
                        break;
                    case 'M':
                        val = o.getMonth() + 1;
                        break;
                    case 'MM':
                        val = this.date2Char(o.getMonth() + 1);
                        break;
                    case 'yyyy':
                        val = o.getFullYear();
                        break;
                    case 'yy':
                        val = this.date2Char(o.getFullYear());
                        break;
                    default:
                        break;
                }
                result += val + splitChar;
            }
            return result.substring(0, result.length - 1);
        } else {
            return o.toString();
        }
    } catch(ex) { return ''; }
}

function concatDateToString(args) {
    if (!args.length) return '';
    let result = '';
    for (let i = 1; i < args.length; i++) {
        result += args[i] + args[0];
    }
    return result.substring(0, result.length - 1);
}

function date2Char(d){
    return this.rightString('0' + d);
}

function rightString(o) {
    return o.substr(o.length - 2);
}

Used:

var a = new Date();
console.log('dd/MM/yyyy: ' + toString(a, 'dd/MM/yyyy'));
console.log('MM/dd/yyyy: ' + toString(a, 'MM/dd/yyyy'));
console.log('dd/MM/yy: ' + toString(a, 'dd/MM/yy'));
console.log('MM/dd/yy: ' + toString(a, 'MM/dd/yy'));

Answer 50

I hope this function will be useful

function formatDate(dDate,sMode){       
        var today = dDate;
        var dd = today.getDate();
        var mm = today.getMonth()+1; //January is 0!
        var yyyy = today.getFullYear();
        if(dd<10) {
            dd = '0'+dd
        } 
        if(mm<10) {
            mm = '0'+mm
        } 
        if (sMode+""==""){
            sMode = "dd/mm/yyyy";
        }
        if (sMode == "yyyy-mm-dd"){
            return  yyyy + "-" + mm + "-" + dd + "";
        }
        if (sMode == "dd/mm/yyyy"){
            return  dd + "/" + mm + "/" + yyyy;
        }

    }

Answer 51

Here's a compact little function that's easy to read and avoids local variables, which can be time-sinks in JavaScript. I don't use prototypes to alter standard modules, because it pollutes the namespace and can lead to code that doesn't do what you think it should.

The main function has a stupid name, but it gets the idea across.

function dateToYYYYMMDDhhmmss(date) {
    function pad(num) {
        num = num + '';
        return num.length < 2 ? '0' + num : num;
    }
    return date.getFullYear() + '/' +
        pad(date.getMonth() + 1) + '/' +
        pad(date.getDate()) + ' ' +
        pad(date.getHours()) + ':' +
        pad(date.getMinutes()) + ':' +
        pad(date.getSeconds());
}

Answer 52

var dateDisplay = new Date( 2016-11-09 05:27:00 UTC );
dateDisplay = dateDisplay.toString()
var arr = (dateDisplay.split(' '))
var date_String =  arr[0]+','+arr[1]+' '+arr[2]+' '+arr[3]+','+arr[4]

this will show string like Wed,Nov 09 2016,10:57:00

Answer 53

<pre>Date.prototype.getFromFormat = function(format) {
    var yyyy = this.getFullYear().toString();
    format = format.replace(/yyyy/g, yyyy)
    var mm = (this.getMonth()+1).toString(); 
    format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
    var dd  = this.getDate().toString();
    format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
    var hh = this.getHours().toString();
    format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
    var ii = this.getMinutes().toString();
    format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
    var ss  = this.getSeconds().toString();
    format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
    var ampm = (hh >= 12) ? "PM" : "AM";
    format = format.replace(/ampm/g, (ampm[1]?ampm:"0"+ampm[0]));
    return format;
};
var time_var = $('#899_TIME');
var myVar = setInterval(myTimer, 1000);
function myTimer() {
    var d = new Date(); 
    var date = d.getFromFormat('dd-mm-yyyy hh:ii:ss:ampm');
    time_var.text(date);

} </pre>

use the code and get the output like **26-07-2017 12:29:34:PM**

check the below link for your reference

https://parthiban037.wordpress.com/2017/07/26/date-and-time-format-in-oracle-apex-using-javascript/