Update: there's a new way of doing things
As of the day on which this was written, the feature of rust which enables the following (count
) to be done, in still unstable
and is available in nightly
builds.
You can check out the github issues and test cases for further understanding of what's given below
To enable this feature, you need to add the line #![feature(macro_metavar_expr)]
to the top of the crate's root module (usually main.rs
or lib.rs
), and also set your repo to use nightly builds, which is easily done by creating a file rust-toolchain.toml
in the root directory (alongside Cargo.toml
) and add the folllowing lines to it:
[toolchain]
channel = "nightly"
Now, instead of providing a solution to you specific problem, I'd like to share a generic solution I created to better illustrate most situations.
I highly recommend studying the code AND the comments, by pasting the following two code blocks in a file (main.rs
).
The macro_rules
#[derive(Eq, PartialEq, Debug, Copy, Clone)]
struct SumLen {
sum: i32,
len: u32
}
/// currently one `i32` type is available
///
/// # Examples
///
/// The output of the following:
/// ```ignore
/// sumnarr!(i32 => 5 ; 6, 7, 8)
/// ```
/// will be `[(5, 1), (21, 3)]`
macro_rules! sumnarr {
( $type:ty => $( $( $x: expr ),* );* ) => {
{
// `${count(x,0)}` will give you "length" (number of iterations)
// in `$( )*` loop that you are IMMEDIATELY OUTSIDE OF (e.g.: the `$( )*` loop below)
// `${count(x,1)}` will give you TOTAL number of iterations that the `$( )*` loop
// INSIDE of the IMMEDIATE `$( )*` loop will make. i.e. it is similar to converting
// [ [i1,i2], [i1,i2,i3] ] TO [ i1,i2,i3,i4,i5 ] i.e. flatten the nested iteration.
// In case of `[ [i1,i2], [i1,i2,i3] ]`, `${count(x,0)}` is 2 and `${count(x,1)}` is 5
let mut arr: [SumLen; ${count(x,0)}] = [SumLen{ sum:0, len:0}; ${count(x,0)}];
$(
// `${index()}` refers to the iteration number within the `$( )*` loop
arr[${index()}] = {
let mut sum = 0;
//let mut len = 0;
// THe following will give us length is the loop it is IMMEDIATELY OUTSIDE OF
// (the one just below)
let len = ${count(x,0)};
$(
sum += $x;
// If you were NOT using `$x` somewhere else inside `$( )*`,
// then you should use `${ignore(x)};` to inform the compiler
//You could use the below method, where `${length()}` will give you
//"length" or "number of iterations" in current loop that you are in
// OR
// you could go with my method of `${count(x,0)}` which is explained above
//len = ${length()};
)*
SumLen {
sum,
len
}
};
)*
arr
}
};
}
The #[test]
(unit test)
#[test]
fn sumnarr_macro() {
let (a, b, c, d, e) = (4, 5, 6, 9, 10);
let sum_lens = [
SumLen {
sum: a + e,
len: 2
},
SumLen {
sum: b + c + d,
len: 3
}
];
assert_eq!(sum_lens, sumnarr!(i32 => a,e;b,c,d));
}
I hope this helps