I have the following condition to test
<xsl:if test=" $Occupation='5'
or $Occupation='7'
or $Occupation='N'
or $Occupation='M'
or $Occupation='J'
or $Occupation='V'
or $Occupation='W'">
<xsl:value-of select="'Accounts'"/>
</xsl:if>
Is there a way to check like this?
<xsl:if test="$occupation contains('5','7','N','W','J','M')">
Assuming everything in your list is a single character:
<xsl:if test="string-length($occupation) = 1 and contains('57NWJM', $occupation)">
<xsl:value-of select="'Accounts'"/>
</xsl:if>
If the entries are longer than one character, you can use a separation character. This character must of course not appear in any of the values in your list. With a space as separation character, things might look like:
<xsl:if test="not(contains($occupation, ' ')) and contains(' foo bar baz ', concat(' ', $occupation, ' '))">
<xsl:value-of select="'Accounts'"/>
</xsl:if>
Make sure you don't forget those padding spaces before foo and after baz.
You could use:
<xsl:if test="contains('57NMJ', $Occupation)">
but this would also return true when $Occupation = "7N", for example.
To protect against that, you can use:
<xsl:if test="contains('|5|7|N|M|J|', concat('|', $Occupation, '|'))">
The other way round might work...
<xsl:if test="contains('57NWJM',$Occupation)">
You can do this much more cleanly in XSLT 2.0:
$occupation = ('5','7','N','M','J','V','W')
For single-character value cases such as yours, this XPath 1.0 expression,
translate($occupation,'7NMJVW','555555')='5'
will return true when $occupation is 5, 7, N, M, J, V, or W as requested.
For single- or multi-character value cases, see Thomas W's answer or michael.hor257k's answer, which employ a technique often used to test @class attribute values safely:
contains(concat(" ", normalize-space(@class), " "), " target ")]
