how to get an uri of an image resource in android

Question

I need to open an intent to view an image as follows:

Intent intent = new Intent(Intent.ACTION_VIEW);
Uri uri = Uri.parse("@drawable/sample_1.jpg");
intent.setData(uri);
startActivity(intent);

The problem is that Uri uri = Uri.parse("@drawable/sample_1.jpg"); is incorrect.

score 152 · Answer 1 · answered Feb 04 '11 at 09:12

152

The format is:

"android.resource://[package]/[res id]"

[package] is your package name

[res id] is value of the resource ID, e.g. R.drawable.sample_1

to stitch it together, use

Uri path = Uri.parse("android.resource://your.package.name/" + R.drawable.sample_1);

answered Feb 04 '11 at 09:12

Axarydax

16,353
21
92
151

3

Uri path = Uri.parse("android.resource://net.londatiga.android.twitpic/" + R.drawable.icon); String mpath = path.toString(); I get No such file or directory error when i am doing this – hemanth kumar Sep 04 '12 at 12:45
4

when i try to send image as email attachment it is sending the file but without .jpg extension. So the image isn't valid in the receipients pc. – ruben May 30 '13 at 05:56
@hemanthkumar See this answer as a reference : http://stackoverflow.com/a/8476930/62921 He explain that there is no drawable folder except on your machine. That's why it uses IDs and that your path.toString() doesn't work. – ForceMagic Jul 16 '13 at 15:21
This does not work for me. I get ActivityNotFoundException. (android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW dat=android.resource://com.mypackage.myapp/2130837582 }. LG E400 Android 2.3.6. – Lucio Crusca Feb 25 '14 at 19:29
@LucioCrusca - maybe you should specify the intent type - is it jpeg or png image? – Axarydax Feb 26 '14 at 11:19
Just a reminder that the constant in the framework is: `ContentResolver.SCHEME_ANDROID_RESOURCE` – Simon Nov 22 '14 at 02:49
Thank you! Worked for me. Before I tried this (which did not work): `Uri uri = Uri.parse(String.valueOf(R.id.drawable_name));` – Azurespot Apr 27 '15 at 07:00
So is the resource type required or not? It's not working for me when I don't include the resource typ: http://stackoverflow.com/questions/19566840/get-uri-from-drawable-image – fobbymaster Nov 21 '15 at 01:01

Uli · Answer 2 · 2022-05-31T02:34:35.220

Here is a clean solution which fully leverages the android.net.Uri class via its Builder pattern, avoiding repeated composition and decomposition of the URI string, without relying on hard-coded strings or ad hoc ideas about URI syntax.

Resources resources = context.getResources();
Uri uri = new Uri.Builder()
    .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
    .authority(resources.getResourcePackageName(resourceId))
    .appendPath(resources.getResourceTypeName(resourceId))
    .appendPath(resources.getResourceEntryName(resourceId))
    .build();

Minimally more elegant with Kotlin:

fun Context.resourceUri(resourceId: Int): Uri = with(resources) {
    Uri.Builder()
        .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
        .authority(getResourcePackageName(resourceId))
        .appendPath(getResourceTypeName(resourceId))
        .appendPath(getResourceEntryName(resourceId))
        .build()
}

In Jetpack Compose:

@Composable
fun rememberResourceUri(resourceId: Int): Uri {
    val context = LocalContext.current

    return remember(resourceId) {
        with(context.resources) {
            Uri.Builder()
                .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
                .authority(getResourcePackageName(resourceId))
                .appendPath(getResourceTypeName(resourceId))
                .appendPath(getResourceEntryName(resourceId))
                .build()
        }
    }
}

this solved my problem. My uri shape was like "android.resource://com.craiovadata.guessthecountry/drawable/sky" — Dan Alboteanu, Oct 02 '18 at 11:24

score 59 · Answer 3 · edited Aug 09 '16 at 10:32

59

public static Uri resourceToUri(Context context, int resID) {
        return Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + "://" +
                context.getResources().getResourcePackageName(resID) + '/' +
                context.getResources().getResourceTypeName(resID) + '/' +
                context.getResources().getResourceEntryName(resID) );
    }

edited Aug 09 '16 at 10:32

Nick Cardoso

20,807
14
73
124

answered Jan 05 '15 at 21:29

xnagyg

4,784
2
32
24

score 11 · Answer 4 · answered Jun 06 '14 at 08:50

11

For those having error, you may be entering the wrong package name. Just use this method.

public static Uri resIdToUri(Context context, int resId) {
    return Uri.parse(Consts.ANDROID_RESOURCE + context.getPackageName()
                     + Consts.FORESLASH + resId);
}

Where

public static final String ANDROID_RESOURCE = "android.resource://";
public static final String FORESLASH = "/";

answered Jun 06 '14 at 08:50

sandalone

41,141
63
222
338

17

did you really made a constant for a foreslash?? – Sartheris Stormhammer Sep 07 '15 at 18:41
@SartherisStormhammer Yes :), although I usually use system constant for foreslash ;) – sandalone Sep 07 '15 at 18:44

score 5 · Answer 5 · answered Mar 07 '19 at 00:09

5

Based on the answers above I want to share a kotlin example on how to get a valid Uri for any resource in your project. I think it's the best solution because you don't have to type any strings in your code and risk typing it wrongly.

    val resourceId = R.raw.scannerbeep // r.mipmap.yourmipmap; R.drawable.yourdrawable
    val uriBeepSound = Uri.Builder()
        .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
        .authority(resources.getResourcePackageName(resourceId))
        .appendPath(resources.getResourceTypeName(resourceId))
        .appendPath(resources.getResourceEntryName(resourceId))
        .build()

answered Mar 07 '19 at 00:09

Sergio

2,346
2
24
28

This is literally the same thing as Uli's answer .. – max pleaner Feb 04 '23 at 22:59
@maxpleaner it literally isn't the same answer, and his answer was edited because it was only in Java, as you know Kotlin for Android is a thing since 2019, original answer 2016. Thank you for your comment. Have a nice day. – Sergio Feb 05 '23 at 23:48
My mistake. Sorry about that. – max pleaner Feb 06 '23 at 02:51

score 3 · Answer 6 · edited Sep 01 '17 at 09:41

3

You want the URI of the image resource, and R.drawable.goomb is an image resource. The Builder function creates the URI that you are asking for:

String resourceScheme = "res";
Uri uri = new Uri.Builder()
  .scheme(resourceScheme)
  .path(String.valueOf(intResourceId))
  .build();

edited Sep 01 '17 at 09:41

Cody Gray - on strike

239,200
50
490
574

answered Mar 08 '16 at 16:17

roide

127
1
4

So you're passing something like "18" to path. That seems incorrect – Nick Cardoso Aug 09 '16 at 10:29
@NickCardoso R.drawable.goomba is the the drawable that I have in my resource folder. If its value is 18, does that make the assignment incorrect ? – roide Aug 09 '16 at 21:15
Of course it does. https://developer.android.com/reference/android/net/Uri.Builder.html#path(java.lang.String) The ID in the R file needs to be used to resolve a real path. – Nick Cardoso Aug 10 '16 at 06:59
@NickCardoso thanks but it does not and it works perfectly. The Scheme takes care of that path as the documentation you pointed out suggests. – roide Aug 10 '16 at 09:50

score 1 · Answer 7 · answered Oct 09 '21 at 09:51

Based on @xnagyg answer above I've made a convenience extension which hopefully will be useful for others also,

fun Resources.getRawUri(@RawRes rawRes: Int) = "%s://%s/%s/%s".format(
    ContentResolver.SCHEME_ANDROID_RESOURCE, this.getResourcePackageName(rawRes),
    this.getResourceTypeName(rawRes), this.getResourceEntryName(rawRes)
)

which can be used like context.resources.getRawUri(R.raw.rawid)

score 0 · Answer 8 · answered Apr 28 '23 at 14:44

0

public static String getURIForResource (int resourceId) {
        
        return Uri.parse("android.resource://"+BuildConfig.APPLICATION_ID+"/" +resourceId).toString();
    }

answered Apr 28 '23 at 14:44

Khalid Lakhani

179
2
10

Remember that Stack Overflow isn't just intended to solve the immediate problem, but also to help future readers find solutions to similar problems, which requires understanding the underlying code. This is especially important for members of our community who are beginners, and not familiar with the syntax. Given that, **can you [edit] your answer to include an explanation of what you're doing** and why you believe it is the best approach? – Jeremy Caney Apr 30 '23 at 00:34

how to get an uri of an image resource in android

8 Answers8

Linked

Related