457

I want to convert an object like this:

{"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

into an array of key-value pairs like this:

[[1,5],[2,7],[3,0],[4,0]...].

How can I convert an Object to an Array of key-value pairs in JavaScript?

Soptareanu Alex
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22 Answers22

694

You can use Object.keys() and map() to do this

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map((key) => [key, obj[key]]);

console.log(result);
Nenad Vracar
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    @blvckasvp Are you using numbers as your keys? If not, when it tries to convert your key to a number it will fail and return `NaN` instead. If you want to use strings as your keys, change the return from `[Number(key), obj[key]]` to `[key, obj[key]]` or use the `Object.entries` as @Pila suggested in their answer – scottbot95 May 29 '19 at 20:49
  • for me, it's worked fine. I need to convert the below object let res ={"5":"ManuscriptRequestId","4":"PublishRequestId","9":"AuthorIdentificationId","1":"VisitRequestId","6":"InformationRequestId","3":"RareDocumnetsRequestId","2":"RarePhotoRequestId","7":"BookPurchaseRequestId","8":"StatmentRequestId"} const dataArray = Object.entries(res).map(([key, value]) => ({ key, value })); – Rohit Gaidhane Aug 02 '23 at 11:55
317

The best way is to do:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.entries(obj);

console.log(result);

Calling entries, as shown here, will return [key, value] pairs, as the caller requested.

Alternatively, you could call Object.values(obj), which would return only values.

SuperDJ
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Pila
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81

Object.entries() returns an array whose elements are arrays corresponding to the enumerable property [key, value] pairs found directly upon object. The ordering of the properties is the same as that given by looping over the property values of the object manually.

- https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/entries#Description

The Object.entries function returns almost the exact output you're asking for, except the keys are strings instead of numbers.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

console.log(Object.entries(obj));

If you need the keys to be numbers, you could map the result to a new array with a callback function that replaces the key in each pair with a number coerced from it.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
    const entries = Object.entries(input);
    return entries.map(entry => Object.assign(entry, { 0: +entry[0] }));
}

console.log(toNumericPairs(obj));

I use an arrow function and Object.assign for the map callback in the example above so that I can keep it in one instruction by leveraging the fact that Object.assign returns the object being assigned to, and a single instruction arrow function's return value is the result of the instruction.

This is equivalent to:

entry => {
    entry[0] = +entry[0];
    return entry;
}

As mentioned by @TravisClarke in the comments, the map function could be shortened to:

entry => [ +entry[0], entry[1] ]

However, that would create a new array for each key-value pair, instead of modifying the existing array in place, hence doubling the amount of key-value pair arrays created. While the original entries array is still accessible, it and its entries will not be garbage collected.

Now, even though using our in-place method still uses two arrays that hold the key-value pairs (the input and the output arrays), the total number of arrays only changes by one. The input and output arrays aren't actually filled with arrays, but rather references to arrays and those references take up a negligible amount of space in memory.

  • Modifying each key-value pair in-place results in a negligible amount of memory growth, but requires typing a few more characters.
  • Creating a new array for each key-value pair results in doubling the amount of memory required, but requires typing a few less characters.

You could go one step further and eliminate growth altogether by modifying the entries array in-place instead of mapping it to a new array:

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
  const entries = Object.entries(obj);
  entries.forEach(entry => entry[0] = +entry[0]);
  return entries;
}

console.log(toNumericPairs(obj));
33

To recap some of these answers now on 2018, where ES6 is the standard.

Starting with the object:

let const={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
  • Just blindly getting the values on an array, do not care of the keys:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.values(obj));
//[9,8,7,6,5,4,3,2,1,0,5]
  • Simple getting the pairs on an array:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj));
//[["1",9],["2",8],["3",7],["4",6],["5",5],["6",4],["7",3],["8",2],["9",1],["10",0],["12",5]]
  • Same as previous, but with numeric keys on each pair:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).map(([k,v])=>[+k,v]));
//[[1,9],[2,8],[3,7],[4,6],[5,5],[6,4],[7,3],[8,2],[9,1],[10,0],[12,5]]
  • Using the object property as key for a new array (could create sparse arrays):

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).reduce((ini,[k,v])=>(ini[k]=v,ini),[]));
//[undefined,9,8,7,6,5,4,3,2,1,0,undefined,5]

This last method, it could also reorganize the array order depending the value of keys. Sometimes this could be the desired behaviour (sometimes don't). But the advantage now is that the values are indexed on the correct array slot, essential and trivial to do searches on it.

  • Map instead of Array

Finally (not part of the original question, but for completeness), if you need to easy search using the key or the value, but you don't want sparse arrays, no duplicates and no reordering without the need to convert to numeric keys (even can access very complex keys), then array (or object) is not what you need. I will recommend Map instead:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map

let r=new Map(Object.entries(obj));
r.get("4"); //6
r.has(8); //true
CarlosH.
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    The fourth bullet point and onward is completely irrelevant to the question, and the rest of your answer is just summarizing the top three answers here. This answer does not bring anything to the discussion that was not already here or is not completely irrelevant. –  Jan 06 '19 at 17:27
  • Yes, as the first line state, this is a summary of answers, then update them to use modern ES6 techniques instead of full blow functions. The fourth answer is useful when you are moving JSON arrays from a language that supports associative arrays (e.g. PHP). – CarlosH. Jan 07 '19 at 22:30
  • All of the methods provided here have already been provided in their plain form in two of the top three answers, they are not in functions so I dont know what you're on about there. As far as the 4th, as I said it is completely irrelevant to the question asked. It might be relevant to a different question, but not this one. Regardless, JSON is JSON whether it is created using PHP, JavaScript, or Haskell. –  Jan 07 '19 at 22:47
30

In Ecmascript 6,

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

var res = Object.entries(obj);

console.log(res);

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
var res = Object.entries(obj);
console.log(res);
Shubham Dixit
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23

Yet another solution if Object.entries won't work for you.

const obj = {
      '1': 29,
      '2': 42
    };
const arr = Array.from(Object.keys(obj), k=>[`${k}`, obj[k]]);
console.log(arr);
bigh_29
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    This worked for me. I experienced an issue where importing JSON added indexes that made it impossible to use Angulars ngFor loop. This removed the indexes while preserving the structure. – RAC Sep 28 '18 at 18:37
  • @RAC +1 for using "indexes" instead of "indices". Begone, archaic (ie. arbitrary and meaninglessly deviant) English traditions! – Venryx Jan 08 '19 at 03:35
10

Use Object.keys and Array#map methods.

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
// get all object property names
var res = Object.keys(obj)
  // iterate over them and generate the array
  .map(function(k) {
    // generate the array element 
    return [+k, obj[k]];
  });

console.log(res);
Pranav C Balan
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10

Use Object.entries to get each element of Object in key & value format, then map through them like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

var res = Object.entries(obj).map(([k, v]) => ([Number(k), v]));

console.log(res);

But, if you are certain that the keys will be in progressive order you can use Object.values and Array#map to do something like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}; 

                        // idx is the index, you can use any logic to increment it (starts from 0)
let result = Object.values(obj).map((e, idx) => ([++idx, e]));

console.log(result);
BlackBeard
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9

You can use Object.values([]), you might need this polyfill if you don't already:

const objectToValuesPolyfill = (object) => {
  return Object.keys(object).map(key => object[key]);
};
Object.values = Object.values || objectToValuesPolyfill;

https://stackoverflow.com/a/54822153/846348

Then you can just do:

var object = {1: 'hello', 2: 'world'};
var array = Object.values(object);

Just remember that arrays in js can only use numerical keys so if you used something else in the object then those will become `0,1,2...x``

It can be useful to remove duplicates for example if you have a unique key.

var obj = {};
object[uniqueKey] = '...';
OZZIE
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8

With lodash, in addition to the answer provided above, you can also have the key in the output array.

Without the object keys in the output array

for:

const array = _.values(obj);

If obj is the following:

{ “art”: { id: 1,  title: “aaaa” }, “fiction”: { id: 22,  title: “7777”} }

Then array will be:

[ { id: 1, title: “aaaa” }, { id: 22, title: “7777” } ]

With the object keys in the output array

If you write instead ('genre' is a string that you choose):

const array= _.map(obj, (val, id) => {
    return { ...val, genre: key };
  });

You will get:

[ 
  { id: 1, title: “aaaa” , genre: “art”}, 
  { id: 22, title: “7777”, genre: “fiction” }
]
Yossi
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7

If you are using lodash, it could be as simple as this:

var arr = _.values(obj);
Adam Boostani
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5
var obj = { "1": 5, "2": 7, "3": 0, "4": 0, "5": 0, "6": 0, "7": 0, "8": 0, "9": 0, "10": 0, "11": 0, "12": 0 }
let objectKeys = Object.keys(obj);

let answer = objectKeys.map(value => {
    return [value + ':' + obj[value]]
});
Muhammad Shaeel
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4
const persons = { 
    john: { age: 23, year:2010},
    jack: { age: 22, year:2011},
    jenny: { age: 21, year:2012}
}
const resultArray = Object.keys(persons).map(index => {
    let person = persons[index];
    return person;
});

//use this for not indexed object to change array
KATHEESKUMAR
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3

This is my solution, i have the same issue and its seems like this solution work for me.

yourObj = [].concat(yourObj);
Qui-Gon Jinn
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3

or you can use Object.assign():

const obj = { 0: 1, 1: 2, 2: 3};
const arr = Object.assign([], obj);
console.log(arr)
// arr is [1, 2, 3]
Khaled Ayed
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2

Here is a "new" way with es6 using the spread operator in conjunction with Object.entries.

const data = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const dataSpread = Object.entries(data);

// data spread value is now:
[
  [ '1', 5 ],  [ '2', 7 ],
  [ '3', 0 ],  [ '4', 0 ],
  [ '5', 0 ],  [ '6', 0 ],
  [ '7', 0 ],  [ '8', 0 ],
  [ '9', 0 ],  [ '10', 0 ],
  [ '11', 0 ], [ '12', 0 ]
]
brff19
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  • Using the spread operator here is redundant. There is no need to use it because `Object.entries()` already returns a 2d array in the expected format. – Niket Pathak Mar 21 '23 at 09:29
  • Yep, you are right. The outer array isn't needed either, so I've updated the code to get rid of that as well! – brff19 Jun 05 '23 at 18:04
2

you can use 3 methods convert object into array (reference for anyone not only for this question (3rd on is the most suitable,answer for this question) Object.keys() ,Object.values(),andObject.entries()

examples for 3 methods

use Object.keys()

const text= {
    quote: 'hello world',
    author: 'unknown'
};
const propertyNames = Object.keys(text);

console.log(propertyNames);
result
[ 'quote', 'author' ]

use Object.values()

const propertyValues = Object.values(text);

console.log(propertyValues);

result

[ 'Hello world', 'unknown' ]

use Object.entires()

const propertyValues = Object.entires(text);

console.log(propertyValues);

result

[ [ 'quote', 'Hello world' ], [ 'author', 'unknown' ] ]
  • While this is informative, the question is more specific and can be answered just by the third part. Please consider editing your answer to just answer the question. – Sebastian Nov 17 '22 at 09:54
  • yeah, I did mentioned above before answering question anyway I bold it out ( I put 3 answers for reference for those who need to learn about this methods maybe you are pro but I mentioned it for beginners) – Dulanjana Abeyrathna Nov 21 '22 at 16:41
0

Use for in

var obj = { "10":5, "2":7, "3":0, "4":0, "5":0, "6":0, "7":0,
            "8":0, "9":0, "10":0, "11":0, "12":0 };

var objectToArray = function(obj) {
    var _arr = [];

    for (var key in obj) {
        _arr.push([key, obj[key]]);
    }
    return _arr;
}

console.log(objectToArray(obj));
wkyniston
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0

Recursive convert object to array

function is_object(mixed_var) {
    if (mixed_var instanceof Array) {
        return false;
    } else {
        return (mixed_var !== null) && (typeof( mixed_var ) == 'object');
    }
}


function objectToArray(obj) {
    var array = [], tempObject;
    for (var key in obj) {

        tempObject = obj[key];

        if (is_object(obj[key])) {
            tempObject = objectToArray(obj[key]);
        }
        array[key] = tempObject;
    }
    return array;
}
Marina Lebedeva
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0

We can change Number to String type for Key like below:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map(function(key) {
  return [String(key), obj[key]];
});
    
console.log(result);
Douwe de Haan
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Nagnath Mungade
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-1

you can use _.castArray(obj).

example: _.castArray({ 'a': 1 }); // => [{ 'a': 1 }]

Chopper Lee
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-1

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5}

result = Object.entries(obj).map((key,value) => [parseInt(key,10), value])

console.log(result);
Ryan M
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yu zhao
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