Extracting just the last part of a string

Question

I'm trying to get the username from a JSON property I get returned from Sharepoint's restful API.

The property/string I receive: "i:0#.w|xyz\tzzjjaa"

What I want: "xyz\tzzjjaa"

I tried: "i:0#.w|xyz\tzzjjaa".replace("\\","\\\\"), which returns: "i:0#.w|corproot tzzjjaa"

Why is this the case? (is the backslash kind of escaping the "t" in the string?) How can I fix it to just get "xyz\tzzjjaa"?

Thanks alot. :)

`\t` is a tab, so the initial string is not properly escaped. — epascarello, Aug 22 '16 at 13:06
So what to do then? This is a username I get from the server... can't change it... — sandrooco, Aug 22 '16 at 13:08
What shilly said...why not just do `string.split("|")[1]` if the format of the string you get is consistent — tewathia, Aug 22 '16 at 13:09
If the \ is supposed to be an \ than you need to double it up when the string is created. My guess sharepoint is not doing that so.... not sure what to do in your case. — epascarello, Aug 22 '16 at 13:11

score 2 · Answer 1 · edited May 23 '17 at 11:55

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var str = String.raw`i:0#.w|xyz\tzzjjaa`;
console.log(str.split("|")[1]);

Assuming you want to keep the backslash see a really good answer by T.J. Crowder on using the String.raw function, then split the string on the pipe and take the second part of the resulting array.

Demo: https://jsfiddle.net/snjfveo6/

If you don't want the backslash you can remove the String.raw part and skip to splitting the string.

edited May 23 '17 at 11:55

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answered Aug 22 '16 at 13:13

Jonathan Newton

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And the support for that is very limited in browsers and looks like you typed it wrong. – epascarello Aug 22 '16 at 13:14
Looks good, tested it in chrome. See docs: https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/raw - it is only support in Chrome and Firefox – Sebastian G. Marinescu Aug 22 '16 at 13:17
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Yeah I should note that this is a 2015 standard @epascarello well pointed out! – Jonathan Newton Aug 22 '16 at 13:17
It's not working with an `x` instead of `t`: var str = String.raw`i:0#.w|xyz\xzzjjaa`; – Sebastian G. Marinescu Aug 22 '16 at 13:31
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Thanks :) In case there will never be an 'x', your solution is really nice. It's just a real pity we can't even deactivate escaping in a **Raw-String**. – Sebastian G. Marinescu Aug 22 '16 at 13:45
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@SebastianG.Marinescu Yeah it's frustrating [also a known bug](https://bugs.chromium.org/p/v8/issues/detail?id=5016) – Jonathan Newton Aug 22 '16 at 13:54

Sathvik Chinnu · Answer 2 · 2016-08-22T13:25:02.053

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var str = "i:0#.w|xyz\tzzjjaa".replace("i:0#.w|", "");
alert(JSON.stringify(str));

Demo

edited Aug 22 '16 at 13:25

answered Aug 22 '16 at 13:18

Sathvik Chinnu

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added demo @Sandrooco – Sathvik Chinnu Aug 22 '16 at 13:25
This works in this case. If however the user-name/-suffix starts with an `x`, it will not work - try: `str = "i:0#.w|xyz\xzzjjaa".replace("i:0#.w|", "");` – Sebastian G. Marinescu Aug 22 '16 at 13:30
he haven't mentioned that in the question @SebastianG.Marinescu – Sathvik Chinnu Aug 22 '16 at 13:32
Why should the OP try this? A ***good answer*** will always have an explanation of what was done and why it was done in such a manner, not only for the OP but for future visitors to SO. – Jay Blanchard Sep 26 '16 at 18:36

score -1 · Answer 3 · answered Aug 22 '16 at 13:10

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are you sure it should be "tzzjjaa"? \t in a quoted string literal (or in the JSON string) is not \ followed by t, it represents a TAB (ASCII Code# 09) character instead!

answered Aug 22 '16 at 13:10

some1

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@Sandrooco if it is a \ followed by t, then it should be coded as `"i:0#.w|xyz\\tzzjjaa"`, or with the `String.raw` as suggested above. instead of splitting the string, you may still use the replace function in the following manner: `.replace(/^.+\|/,"")` – some1 Aug 23 '16 at 01:58

score -1 · Answer 4 · edited May 23 '17 at 10:28

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\t in a JS-string is escaped to a Tab-character.

Your best solution as I see it, is to escape it on the server-side.

In your case you will have to write a little server-script, that calls your used API and converts/escapes everything to be ready for your JS. And your JS calls this little server-script.

If your username is sure to never start with an x after the backslash, then:

Either go with JNewtons's answer and use the String.raw-method, or for wider support use the Stringify-method by Sathvik Cheela.

But if there is a chance that it might start with an x after the backslash, you have currently no way to solve this in the Frontend in JavaScript – only in a backend.

edited May 23 '17 at 10:28

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answered Aug 22 '16 at 13:21

Sebastian G. Marinescu

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Why can't people read the question and comments? I told that I can't change the server stuff because it's SP. – sandrooco Aug 22 '16 at 13:22
I am not talking about the already existing API – but you could write a little PHP-snippet as broker. Of course I am assuming that you are allowed to work on the server. – Sebastian G. Marinescu Aug 22 '16 at 13:24
If you are the Admin on the SP-Site, then you have to change it: Escape the response correctly. If not, _they_ have to change it. Your response from the API should be correctly JSON-encoded. – Sebastian G. Marinescu Aug 22 '16 at 13:38
As said I can't change it. Never mind, found a good solution. – sandrooco Aug 22 '16 at 13:47
@Sandrooco: I'm curious, what is your solution? – Sebastian G. Marinescu Aug 22 '16 at 13:48
`JSON.stringify(result.Author.Name).split("|")[1].slice(0, -1).replace("\\\\", "\\");`- a bit dirty but the safest. Working all the way down to IE8. – sandrooco Aug 22 '16 at 13:50
And your Author-Name can never contain a `\x` in it? – Sebastian G. Marinescu Aug 22 '16 at 13:54

Extracting just the last part of a string

4 Answers4