Check if a value is an object in JavaScript

Question

How do you check if a value is an object in JavaScript?

Answer 1

If typeof yourVariable === 'object', it's an object or null.

If you want null, arrays or functions to be excluded, just make it:

if (
    typeof yourVariable === 'object' &&
    !Array.isArray(yourVariable) &&
    yourVariable !== null
) {
    executeSomeCode();
}

Answer 2

UPDATE:

This answer is incomplete and gives misleading results. For example, null is also considered of type object in JavaScript, not to mention several other edge cases. Follow the recommendation below and move on to other "most upvoted (and correct!) answer":

typeof yourVariable === 'object' && yourVariable !== null

---

Original answer:

Try using typeof(var) and/or var instanceof something.

EDIT: This answer gives an idea of how to examine variable's properties, but it is not a bulletproof recipe (after all there's no recipe at all!) for checking whether it's an object, far from it. Since people tend to look for something to copy from here without doing any research, I'd highly recommend that they turn to the other, most upvoted (and correct!) answer.

Answer 3

Let's define "object" in Javascript. According to the MDN docs, every value is either an object or a primitive:

primitive, primitive value

A data that is not an object and does not have any methods. JavaScript has 7 primitive data types: string, number, bigint, boolean, undefined, symbol, and null.

What's a primitive?

• 3
• 'abc'
• true
• null
• undefined

What's an object (i.e. not a primitive)?

• Object.prototype
• everything descended from Object.prototype
  • Function.prototype
    • Object
    • Function
    • function C(){} -- user-defined functions
  • C.prototype -- the prototype property of a user-defined function: this is not Cs prototype
    • new C() -- "new"-ing a user-defined function
  • Math
  • Array.prototype
    • arrays
  • {"a": 1, "b": 2} -- objects created using literal notation
  • new Number(3) -- wrappers around primitives
  • ... many other things ...
• Object.create(null)
• everything descended from an Object.create(null)

How to check whether a value is an object

instanceof by itself won't work, because it misses two cases:

// oops:  isObject(Object.prototype) -> false
// oops:  isObject(Object.create(null)) -> false
function isObject(val) {
    return val instanceof Object; 
}

typeof x === 'object' won't work, because of false positives (null) and false negatives (functions):

// oops: isObject(Object) -> false
function isObject(val) {
    return (typeof val === 'object');
}

Object.prototype.toString.call won't work, because of false positives for all of the primitives:

> Object.prototype.toString.call(3)
"[object Number]"

> Object.prototype.toString.call(new Number(3))
"[object Number]"

So I use:

function isObject(val) {
    if (val === null) { return false;}
    return ( (typeof val === 'function') || (typeof val === 'object') );
}

---

@Daan's answer also seems to work:

function isObject(obj) {
  return obj === Object(obj);
}

because, according to the MDN docs:

The Object constructor creates an object wrapper for the given value. If the value is null or undefined, it will create and return an empty object, otherwise, it will return an object of a type that corresponds to the given value. If the value is an object already, it will return the value.

---

A third way that seems to work (not sure if it's 100%) is to use Object.getPrototypeOf which throws an exception if its argument isn't an object:

// these 5 examples throw exceptions
Object.getPrototypeOf(null)
Object.getPrototypeOf(undefined)
Object.getPrototypeOf(3)
Object.getPrototypeOf('abc')
Object.getPrototypeOf(true)

// these 5 examples don't throw exceptions
Object.getPrototypeOf(Object)
Object.getPrototypeOf(Object.prototype)
Object.getPrototypeOf(Object.create(null))
Object.getPrototypeOf([])
Object.getPrototypeOf({})

Answer 4

underscore.js provides the following method to find out if something is really an object:

_.isObject = function(obj) {
  return obj === Object(obj);
};

UPDATE

Because of a previous bug in V8 and minor micro speed optimization, the method looks as follows since underscore.js 1.7.0 (August 2014):

_.isObject = function(obj) {
  var type = typeof obj;
  return type === 'function' || type === 'object' && !!obj;
};

Answer 5

Object.prototype.toString.call(myVar) will return:

• "[object Object]" if myVar is an object
• "[object Array]" if myVar is an array
• etc.

For more information on this and why it is a good alternative to typeof, check out this article.

Answer 6

For simply checking against Object or Array without additional function call (speed). As also posted here.

isArray()

isArray = function(a) {
    return (!!a) && (a.constructor === Array);
};
console.log(isArray(        )); // false
console.log(isArray(    null)); // false
console.log(isArray(    true)); // false
console.log(isArray(       1)); // false
console.log(isArray(   'str')); // false
console.log(isArray(      {})); // false
console.log(isArray(new Date)); // false
console.log(isArray(      [])); // true

isLiteralObject() - Note: use for Object literals only, as it returns false for custom objects, like new Date or new YourCustomObject.

isLiteralObject = function(a) {
    return (!!a) && (a.constructor === Object);
};
console.log(isLiteralObject(        )); // false
console.log(isLiteralObject(    null)); // false
console.log(isLiteralObject(    true)); // false
console.log(isLiteralObject(       1)); // false
console.log(isLiteralObject(   'str')); // false
console.log(isLiteralObject(      [])); // false
console.log(isLiteralObject(new Date)); // false
console.log(isLiteralObject(      {})); // true

Answer 7

I'm fond of simply:

function isObject (item) {
  return (typeof item === "object" && !Array.isArray(item) && item !== null);
}

If the item is a JS object, and it's not a JS array, and it's not null…if all three prove true, return true. If any of the three conditions fails, the && test will short-circuit and false will be returned. The null test can be omitted if desired (depending on how you use null).

DOCS:

http://devdocs.io/javascript/operators/typeof

http://devdocs.io/javascript/global_objects/object

http://devdocs.io/javascript/global_objects/array/isarray

http://devdocs.io/javascript/global_objects/null

Answer 8

With function Array.isArray:

function isObject(o) {
  return o !== null && typeof o === 'object' && Array.isArray(o) === false;
}

Without function Array.isArray:

Just surprised how many upvotes for wrong answers
Only 1 answer passed my tests!!! Here I've created my simplified version:

function isObject(o) {
  return o instanceof Object && o.constructor === Object;
}

As for me, it's clear and simple, and just works! Here my tests:

console.log(isObject({}));             // Will return: true
console.log(isObject([]));             // Will return: false
console.log(isObject(null));           // Will return: false
console.log(isObject(/.*/));           // Will return: false
console.log(isObject(function () {})); // Will return: false

ONE MORE TIME: not all answers pass this tests !!!

---

In case you need to verify that object is instance of particular class you have to check constructor with your particular class, like:

function isDate(o) {
  return o instanceof Object && o.constructor === Date;
}

simple test:

var d = new Date();
console.log(isObject(d)); // Will return: false
console.log(isDate(d));   // Will return: true

As result, you will have strict and robust code!

---

In case you won't create functions like isDate, isError, isRegExp, etc you may consider option to use this generalized functions:

function isObject(o) {
  return o instanceof Object && typeof o.constructor === 'function';
}

it won't work correctly for all test cases mentioned earlier, but it's good enough for all objects (plain or constructed).

---

isObject won't work in case of Object.create(null) because of internal implementation of Object.create which is explained here but you can use isObject in more sophisticated implementation:

function isObject(o, strict = true) {
  if (o === null || o === undefined) {
    return false;
  }
  const instanceOfObject = o instanceof Object;
  const typeOfObject = typeof o === 'object';
  const constructorUndefined = o.constructor === undefined;
  const constructorObject = o.constructor === Object;
  const typeOfConstructorObject = typeof o.constructor === 'function';
  let r;
  if (strict === true) {
    r = (instanceOfObject || typeOfObject) && (constructorUndefined || constructorObject);
  } else {
    r = (constructorUndefined || typeOfConstructorObject);
  }
  return r;
};

There is already created package on npm v1 based on this implementation! And it works for all earlier described test cases!

Answer 9

Oh My God! I think this could be more shorter than ever, let see this:

Short and Final code

function isObject(obj)
{
    return obj != null && obj.constructor.name === "Object"
}

console.log(isObject({})) // returns true
console.log(isObject([])) // returns false
console.log(isObject(null)) // returns false

Explained

Return Types

typeof JavaScript objects (including null) returns "object"

console.log(typeof null, typeof [], typeof {})

Checking on Their constructors

Checking on their constructor property returns function with their names.

console.log(({}).constructor) // returns a function with name "Object"
console.log(([]).constructor) // returns a function with name "Array"
console.log((null).constructor) //throws an error because null does not actually have a property

Introducing Function.name

Function.name returns a readonly name of a function or "anonymous" for closures.

console.log(({}).constructor.name) // returns "Object"
console.log(([]).constructor.name) // returns "Array"
console.log((null).constructor.name) //throws an error because null does not actually have a property

Note: As of 2018, Function.name might not work in IE

Answer 10

Try this

if (objectName instanceof Object) {
  alert('An object');
} else {
  alert('Not an object');
}

Answer 11

OK, let's give you this concept first before answering your question, in JavaScript Functions are Object, also null, Object, Arrays and even Date, so as you see there is not a simple way like typeof obj === 'object', so everything mentioned above will return true, but there are ways to check it with writing a function or using JavaScript frameworks, OK:

Now, imagine you have this object that's a real object (not null or function or array):

var obj = {obj1: 'obj1', obj2: 'obj2'};

Pure JavaScript:

//that's how it gets checked in angular framework
function isObject(obj) {
  return obj !== null && typeof obj === 'object';
}

or

//make sure the second object is capitalised 
function isObject(obj) {
   return Object.prototype.toString.call(obj) === '[object Object]';
}

or

function isObject(obj) {
    return obj.constructor.toString().indexOf("Object") > -1;
}

or

function isObject(obj) {
    return obj instanceof Object;
}

You can simply use one of these functions as above in your code by calling them and it will return true if it's an object:

isObject(obj);

If you are using a JavaScript framework, they usually have prepared these kind of functions for you, these are few of them:

jQuery:

 //It returns 'object' if real Object;
 jQuery.type(obj);

Angular:

angular.isObject(obj);

Underscore and Lodash:

//(NOTE: in Underscore and Lodash, functions, arrays return true as well but not null)
_.isObject(obj);

Answer 12

It depends on what you mean with "is an object". If you want everything that is not a primitive, i.e. things that you can set new properties on, this should do the trick:

function isAnyObject(value) {
    return value != null && (typeof value === 'object' || typeof value === 'function');
}

It excludes the primitives (plain numbers/NaN/Infinity, plain strings, symbols, true/false, undefined and null) but should return true for everything else (including Number, Boolean and String objects). Note that JS does not define what "host" objects, such as window or console, should return when used with typeof, so those are hard to cover with a check like this.

If you want to know whether something is a "plain" object, i.e. it was created as a literal {} or with Object.create(null), you might do this:

function isPlainObject(value) {
    if (Object.prototype.toString.call(value) !== '[object Object]') {
        return false;
    } else {
        var prototype = Object.getPrototypeOf(value);
        return prototype === null || prototype === Object.prototype;
    }
}

Edit 2018: Because Symbol.toStringTag now allows customizing the output of Object.prototype.toString.call(...), the isPlainObject function above might return false in some cases even when the object started its life as a literal. Arguably, by convention an object with a custom string tag isn't exactly a plain object any more, but this has further muddied the definition of what a plain object even is in Javascript.

Answer 13

My God, too much confusion in other answers.

Short Answer

typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array)

To test this simply run the following statements in chrome console.

Case 1.

var anyVar = {};
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array) // true

Case 2.

anyVar = [];
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array) // false

Case 3.

anyVar = null;
typeof anyVar == 'object' && anyVar instanceof Object && !(anyVar instanceof Array); // false

Explanation

Okay.Let's break it down

typeof anyVar == 'object' is returned true from three candidates - [], {} and null,

anyVar instanceof Object narrows down these candidates to two - [], {}

!(anyVar instanceof Array) narrows to only one - {}

Drum rolls please!

By this you may have already learnt how to check for Array in Javascript.

Answer 14

Here's an answer with optional chaining, and perhaps the smallest isObj function for this question.

const isObj = o => o?.constructor === Object;

// True for this
console.log(isObj({}));        // object!

// False for these
console.log(isObj(0));         // number
console.log(isObj([]));        // array
console.log(isObj('lol'));     // string
console.log(isObj(null));      // null
console.log(isObj(undefined)); // undefined
console.log(isObj(() => {}));  // function
console.log(isObj(Object));    // class

Answer 15

The most reasonable way to check the type of a value seems the typeof operator. The only problem is that it's horribly broken:

• It returns "object" for null, which belongs to Null type.
• It returns "function" for callable objects, which belong to Object type.
• It can return (almost) anything it wants for non-standard non-callable objects. For example, IE seemed to like "unknown". The only forbidden results are "function" and primitive types.

typeof is only reliable for non-null primitives. So a way to check if a value is an object would be ensuring that the string returned by typeof does not correspond to a primitive, and that the object is not null. However, the problem is that a future standard could introduce a new primitive type, and our code would consider it to be an object. New types don't appear frequently, but for example ECMAScript 6 introduced the Symbol type.

Therefore, instead of typeof, I only recommend approaches whose result varies depending on if the value is an object or not. The following intends to be a

Comprehensive but not exhaustive list of proper ways to test if a value belongs to the Object type.

• Object constructor

  The Object constructor coerces the passed argument to an object. If it's already an object, the same object is returned.

  Therefore, you can use it to coerce the value to an object, and strictly compare that object with the original value.

  The following function requires ECMAScript 3, which introduced ===:

  function isObject(value) { /* Requires ECMAScript 3 or later */
    return Object(value) === value;
  }
  

  I like this approach because it's simple and self-descriptive, and an analogous check will also work for booleans, numbers and strings. However, be aware it relies on the global Object not being shadowed nor altered.

• Constructors

  When you instantiate a constructor, it can return a value different than the just-created instance. But that value will be ignored unless it's an object.

  The following function requires ECMAScript 3, which allowed constructors to return non-objects. Before ECMAScript 3 that threw an error, but try statements didn't exist back then.

  function isObject(value) { /* Requires ECMAScript 3 or later */
    return new function() { return value; }() === value;
  }
  

  While a bit less simple than the previous example, this one does not rely on any global property, and thus might be the safest.

• this value

  Old ECMAScript specifications required the this value to be an object. ECMAScript 3 introduced Function.prototype.call, which allowed to call a function with an arbitrary this value, but coerced to an object.

  ECMAScript 5 introduced a strict mode which removed this behavior, but in sloppy mode we still can (but arguably shouldn't) rely on it.

  function isObject(value) { /* Requires ECMAScript 3 or later in sloppy mode */
    return function() { return this === value; }.call(value);
  }
  

• [[Prototype]]

  All ordinary objects have an internal slot called [[Prototype]], whose value determines from which other object it inherits from. The value can only be an object or null. Therefore, you can attempt to create an object which inherits from the desired value, and check if it worked.

  Both Object.create and Object.getPrototypeOf require ECMAScript 5.

  function isObject(value) { /* Requires ECMAScript 5 or later */
    try {
      Object.create(value);
      return value !== null;
    } catch(err) {
      return false;
    }
  }
  

  function isObject(value) { /* Requires ECMAScript 5 or later */
    function Constructor() {}
    Constructor.prototype = value;
    return Object.getPrototypeOf(new Constructor()) === value;
  }
  

• Some new ECMAScript 6 ways

  ECMAScript 6 introduces some new indirect ways to check is a value is an object. They use the previously seen approach to pass the value to some code which requires an object, wrapped inside a try statement to catch errors. Some hidden examples, not worth commenting

  function isObject(value) { /* Requires ECMAScript 6 or later */
    try {
      Object.setPrototypeOf({}, value);
      return value !== null;
    } catch(err) {
      return false;
    }
  }

  function isObject(value) { /* Requires ECMAScript 6 or later */
    try {
      new WeakSet([value]);
      return true;
    } catch(err) {
      return false;
    }
  }

---

Note: I intentionally skipped some approaches like Object.getPrototypeOf(value) (ES5) and Reflect methods (ES6) because they call essential internal methods which might do nasty things, e.g. if value is a proxy. For safety reasons my examples only reference value without accessing it directly.

Answer 16

Ready to use functions for checking

function isObject(o) {
  return null != o && 
    typeof o === 'object' && 
    Object.prototype.toString.call(o) === '[object Object]';
}

function isDerivedObject(o) {
  return !isObject(o) && 
    null != o && 
    (typeof o === 'object' || typeof o === 'function') &&
    /^\[object /.test(Object.prototype.toString.call(o));
}

// Loose equality operator (==) is intentionally used to check
// for undefined too

// Also note that, even null is an object, within isDerivedObject
// function we skip that and always return false for null

---

Explanation

• In Javascript, null, Object, Array, Date and functions are all objects. Although, null is bit contrived. So, it's better to check for the null first, to detect it's not null.

• Checking for typeof o === 'object' guarantees that o is an object. Without this check, Object.prototype.toString would be meaningless, since it would return object for everthing, even for undefined and null! For example: toString(undefined) returns [object Undefined]!

  After typeof o === 'object' check, toString.call(o) is a great method to check whether o is an object, a derived object like Array, Date or a function.

• In isDerivedObject function, it checks for the o is a function. Because, function also an object, that's why it's there. If it didn't do that, function will return as false. Example: isDerivedObject(function() {}) would return false, however now it returns true.

• One can always change the definition of what is an object. So, one can change these functions accordingly.

---

Tests

function isObject(o) {
  return null != o && 
    typeof o === 'object' && 
    Object.prototype.toString.call(o) === '[object Object]';
}

function isDerivedObject(o) {
  return !isObject(o) && 
    null != o && 
    (typeof o === 'object' || typeof o === 'function') &&
    /^\[object /.test(Object.prototype.toString.call(o));
}

// TESTS

// is null an object?

console.log(
  'is null an object?', isObject(null)
);

console.log(
  'is null a derived object?', isDerivedObject(null)
);

// is 1234 an object?

console.log(
  'is 1234 an object?', isObject(1234)
);

console.log(
  'is 1234 a derived object?', isDerivedObject(1234)
);

// is new Number(1234) an object?

console.log(
  'is new Number(1234) an object?', isObject(new Number(1234))
);

console.log(
  'is new Number(1234) a derived object?', isDerivedObject(1234)
);

// is function object an object?

console.log(
  'is (new (function (){})) an object?', 
  isObject((new (function (){})))
);

console.log(
  'is (new (function (){})) a derived object?', 
  isObject((new (function (){})))
);

// is {} an object?

console.log(
  'is {} an object?', isObject({})
);

console.log(
  'is {} a derived object?', isDerivedObject({})
);

// is Array an object?

console.log(
  'is Array an object?',
  isObject([])
)

console.log(
  'is Array a derived object?',
  isDerivedObject([])
)

// is Date an object?

console.log(
  'is Date an object?', isObject(new Date())
);

console.log(
  'is Date a derived object?', isDerivedObject(new Date())
);

// is function an object?

console.log(
  'is function an object?', isObject(function(){})
);

console.log(
  'is function a derived object?', isDerivedObject(function(){})
);

Answer 17

Little late... for "plain objects" (i mean, like {'x': 5, 'y': 7}) i have this little snippet:

function isPlainObject(o) {
   return (o === null || Array.isArray(o) || typeof o == 'function' || o.constructor === Date ) ?
           false
          :(typeof o == 'object');
}

It generates the next output:

console.debug(isPlainObject(isPlainObject)); //function, false
console.debug(isPlainObject({'x': 6, 'y': 16})); //literal object, true
console.debug(isPlainObject(5)); //number, false
console.debug(isPlainObject(undefined)); //undefined, false
console.debug(isPlainObject(null)); //null, false
console.debug(isPlainObject('a')); //string, false
console.debug(isPlainObject([])); //array?, false
console.debug(isPlainObject(true)); //bool, false
console.debug(isPlainObject(false)); //bool, false

It always works for me. If will return "true" only if the type of "o" is "object", but no null, or array, or function. :)

Answer 18

If you would like to check if the prototype for an object solely comes from Object. Filters out String, Number, Array, Arguments, etc.

function isObject (n) {
  return Object.prototype.toString.call(n) === '[object Object]';
}

Or as a single-expression arrow function (ES6+)

const isObject = n => Object.prototype.toString.call(n) === '[object Object]'

Answer 19

var a = [1]
typeof a //"object"
a instanceof Object //true
a instanceof Array //true

var b ={a: 1}
b instanceof Object //true
b instanceof Array //false

var c = null
c instanceof Object //false
c instanceof Array //false

I was asked to provide more details. Most clean and understandable way of checking if our variable is an object is typeof myVar. It returns a string with a type (e.g. "object", "undefined").

Unfortunately either Array and null also have a type object. To take only real objects there is a need to check inheritance chain using instanceof operator. It will eliminate null, but Array has Object in inheritance chain.

So the solution is:

if (myVar instanceof Object && !(myVar instanceof Array)) {
  // code for objects
}

Answer 20

lodash has isPlainObject, which might be what many who come to this page are looking for. It returns false when give a function or array.

Answer 21

The Ramda functional library has a wonderful function for detecting JavaScript types.

Paraphrasing the full function:

function type(val) {
  return val === null      ? 'Null'      :
         val === undefined ? 'Undefined' :
         Object.prototype.toString.call(val).slice(8, -1);
}

I had to laugh when I realized how simple and beautiful the solution was.

Example usage from Ramda documentation:

R.type({}); //=> "Object"
R.type(1); //=> "Number"
R.type(false); //=> "Boolean"
R.type('s'); //=> "String"
R.type(null); //=> "Null"
R.type([]); //=> "Array"
R.type(/[A-z]/); //=> "RegExp"
R.type(() => {}); //=> "Function"
R.type(undefined); //=> "Undefined"

Answer 22

Performance

Today 2020.09.26 I perform tests on MacOs HighSierra 10.13.6 on Chrome v85, Safari v13.1.2 and Firefox v80 for chosen solutions.

Results

• solutions C and H are fast/fastest on all browsers for all cases
• solutions D and G are slow/slowest on all browsers for all cases

Details

I perform 3 tests cases for solutions A B C D E F G H I J K L M N O P Q R S T U V

• for small object - you can run it HERE
• for big object - you can run it HERE
• for no object - you can run it HERE

Below snippet presents differences between solutions. Solutions A-G give proper answers for chosen cases described by Matt Fenwick

// https://stackoverflow.com/a/14706877/860099
function A(x) {
  return x === Object(x);
};

// https://stackoverflow.com/a/42250981/860099
function B(x) {
    return _.isObject(x);
}

// https://stackoverflow.com/a/34864175/860099
function C(x) {
    return x != null && (typeof x === 'object' || typeof x === 'function');
}

// https://stackoverflow.com/a/39187058/860099
function D(x) { 
  return new function() { return x; }() === x;
}

// https://stackoverflow.com/a/39187058/860099
function E(x) { 
  return function() { return this === x; }.call(x);
}

// https://stackoverflow.com/a/39187058/860099
function F(x) { /* Requires ECMAScript 5 or later */
  try {
    Object.create(x);
    return x !== null;
  } catch(err) {
    return false;
  }
}

// https://stackoverflow.com/a/39187058/860099
function G(x) { /* Requires ECMAScript 5 or later */
  function Constructor() {}
  Constructor.prototype = x;
  return Object.getPrototypeOf(new Constructor()) === x;
}

// https://stackoverflow.com/a/8511332/860099
function H(x) {
  return typeof x === 'object' && x !== null
}

// https://stackoverflow.com/a/25715455/860099
function I(x) {
  return (typeof x === "object" && !Array.isArray(x) && x !== null);
};

// https://stackoverflow.com/a/22482737/860099
function J(x) {
  return x instanceof Object; 
}

// https://stackoverflow.com/a/50712057/860099
function K(x)
{
    let t= JSON.stringify(x);
    return t ? t[0] === '{' : false;
}

// https://stackoverflow.com/a/13356338/860099
function L(x) {
  return Object.prototype.toString.call(x) === "[object Object]";
};



// https://stackoverflow.com/a/46663081/860099
function M(o, strict = true) {
  if (o === null || o === undefined) {
    return false;
  }
  const instanceOfObject = o instanceof Object;
  const typeOfObject = typeof o === 'object';
  const constructorUndefined = o.constructor === undefined;
  const constructorObject = o.constructor === Object;
  const typeOfConstructorObject = typeof o.constructor === 'function';
  let r;
  if (strict === true) {
    r = (instanceOfObject || typeOfObject) && (constructorUndefined || constructorObject);
  } else {
    r = (constructorUndefined || typeOfConstructorObject);
  }
  return r;
}

// https://stackoverflow.com/a/42250981/860099
function N(x) {
    return $.type(x) === 'object';
}

// https://stackoverflow.com/a/34864175/860099
function O(x) {
    if (Object.prototype.toString.call(x) !== '[object Object]') {
        return false;
    } else {
        var prototype = Object.getPrototypeOf(x);
        return prototype === null || prototype === Object.prototype;
    }
}

// https://stackoverflow.com/a/57863169/860099
function P(x) {
  while (     Object.prototype.toString.call(x) === '[object Object]')
  if    ((x = Object.getPrototypeOf(x))         === null)
  return true
  return false
}

// https://stackoverflow.com/a/43289971/860099
function Q(x){
  try{
    switch(x.constructor){
      case Number:
      case Function:
      case Boolean:
      case Symbol:
      case Date:
      case String:
      case RegExp:
        return x.constructor === Object;
      case Error:
      case EvalError:
      case RangeError:
      case ReferenceError:
      case SyntaxError:
      case TypeError:
      case URIError:
        return (Object === Error ? Error : x.constructor) === Object;
      case Array:
      case Int8Array:
      case Uint8Array:
      case Uint8ClampedArray:
      case Int16Array:
      case Uint16Array:
      case Int32Array:
      case Uint32Array:
      case Float32Array:
      case Float64Array:
        return (Object === Array ? Array : x.constructor) === Object;
      case Object:
      default:
        return (Object === Object ? Object : x.constructor) === Object;
    }
  } catch(ex){
    return x == Object;   
  }
}

// https://stackoverflow.com/a/52478680/860099
function R(x) {
    return typeof x == 'object' && x instanceof Object && !(x instanceof Array);
}

// https://stackoverflow.com/a/51458052/860099
function S(x)
{
    return x != null && x.constructor?.name === "Object"
}

// https://stackoverflow.com/a/42250981/860099
function T(x) {
    return x?.constructor?.toString().indexOf("Object") > -1;
}

// https://stackoverflow.com/a/43223661/860099
function U(x)
{
    return x?.constructor === Object;
}

// https://stackoverflow.com/a/46663081/860099
function V(x) {
  return x instanceof Object && x.constructor === Object;
}




// -------------
// TEST
// -------------

console.log('column: 1 2 3 4 5 6 - 7 8 9 10 11');

[A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V]
.map(f=> console.log(`${f.name}:      ${1*f(new Date())} ${1*f(/./)} ${1*f({})} ${1*f(Object.prototype)} ${1*f(Object.create(null))} ${1*f(()=>{})} - ${1*f("abc")} ${1*f(3)} ${1*f(true)}  ${1*f(null)}  ${1*f(undefined)}`))

console.log(`
Columns legend (test cases):
 1: new Date()
 2: /./ (RegExp)
 3: {}
 4: Object.prototype
 5: Object.create(null)
 6: ()=>{} (function)
 7: "abc" (string)
 8: 3 (number)
 9: true (boolean)
10: null
11: undefined

Rows:
1 = is object
0 = is NOT object

Theoretically columns 1-6 should have have 1, columns 7-11 shoud have 0
`);

<script
  src="https://code.jquery.com/jquery-3.5.1.min.js"
  integrity="sha256-9/aliU8dGd2tb6OSsuzixeV4y/faTqgFtohetphbbj0="
  crossorigin="anonymous"></script>
  
<script 
  src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" 
  integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" 
  crossorigin="anonymous"></script>
  
This shippet only presents functions used in performance tests - it not perform tests itself!

And here are example results for chrome

Answer 23

Since there seems a lot of confusion about how to handle this problem correctly, I'll leave my 2 cents (this answer is spec compliant and produces correct results under all circumstances):

Testing for primitives: undefined null boolean string number

function isPrimitive(o){return typeof o!=='object'||null}

An object is not a primitive:

function isObject(o){return !isPrimitive(o)}

Or alternatively:

function isObject(o){return o instanceof Object}
function isPrimitive(o){return !isObject(o)}

Testing for any Array:

const isArray=(function(){
    const arrayTypes=Object.create(null);
    arrayTypes['Array']=true;
    arrayTypes['Int8Array']=true;
    arrayTypes['Uint8Array']=true;
    arrayTypes['Uint8ClampedArray']=true;
    arrayTypes['Int16Array']=true;
    arrayTypes['Uint16Array']=true;
    arrayTypes['Int32Array']=true;
    arrayTypes['Uint32Array']=true;
    arrayTypes['BigInt64Array']=true;
    arrayTypes['BigUint64Array']=true;
    arrayTypes['Float32Array']=true;
    arrayTypes['Float64Array']=true;
    return function(o){
        if (!o) return false;
        return !isPrimitive(o)&&!!arrayTypes[o.constructor.name];
    }
}());

Testing for object excluding: Date RegExp Boolean Number String Function any Array

const isObjectStrict=(function(){
    const nativeTypes=Object.create(null);
    nativeTypes['Date']=true;
    nativeTypes['RegExp']=true;
    nativeTypes['Boolean']=true;
    nativeTypes['Number']=true;
    nativeTypes['String']=true;
    nativeTypes['Function']=true;
    return function(o){
        if (!o) return false;
        return !isPrimitive(o)&&!isArray(o)&&!nativeTypes[o.constructor.name];
    }
}());

Answer 24

After reading and trying out a lot of implementations, I've noticed that very few people try to check for values like JSON, Math, document or objects with prototype chains longer than 1 step.

Instead of checking the typeof of our variable and then hacking away edge-cases, I thought it'd be better if the check is kept as simple as possible to avoid having to refactor when there's new primitives or native objects added that register as typeof of 'object'.

After all, the typeof operator will tell you if something is an object to JavaScript, but JavaScript's definition of an object is too broad for most real-world scenarios (e.g. typeof null === 'object'). Below is a function that determines whether variable v is an object by essentially repeating two checks:

1. A loop is started that continues as long as the stringified version of v is '[object Object]'.
   I wanted the result of the function to be exactly like the logs below, so this is the only "objectness"-criteria I ended up with. If it fails, the function returns false right away.
2. v is replaced with the next prototype in the chain with v = Object.getPrototypeOf(v), but also directly evaluated after. When the new value of v is null, it means that every prototype including the root prototype (which could very well have been the only prototype inside the chain) have passed the check in the while loop and we can return true. Otherwise, a new iteration starts.

function isObj (v) {
  while (     Object.prototype.toString.call(v) === '[object Object]')
  if    ((v = Object.getPrototypeOf(v))         === null)
  return true
  return false
}

console.log('FALSE:')
console.log('[]                   -> ', isObj([]))
console.log('null                 -> ', isObj(null))
console.log('document             -> ', isObj(document))
console.log('JSON                 -> ', isObj(JSON))
console.log('function             -> ', isObj(function () {}))
console.log('new Date()           -> ', isObj(new Date()))
console.log('RegExp               -> ', isObj(/./))

console.log('TRUE:')
console.log('{}                   -> ', isObj({}))
console.log('new Object()         -> ', isObj(new Object()))
console.log('new Object(null)     -> ', isObj(new Object(null)))
console.log('new Object({})       -> ', isObj(new Object({foo: 'bar'})))
console.log('Object.prototype     -> ', isObj(Object.prototype))
console.log('Object.create(null)  -> ', isObj(Object.create(null)))
console.log('Object.create({})    -> ', isObj(Object.create({foo: 'bar'})))
console.log('deep inheritance     -> ', isObj(Object.create(Object.create({foo: 'bar'}))))

Answer 25

When everything else fails, I use this:

var isObject = function(item) {
   return item.constructor.name === "Object";
}; 

Answer 26

This will work. It is a function that returns true, false, or possibly null.

const isObject = obj => obj && obj.constructor && obj.constructor === Object;

console.log(isObject({})); // true
console.log(isObject([])); // false
console.log(isObject(new Function)); // false
console.log(isObject(new Number(123))); // false
console.log(isObject(null)); // null

Answer 27

For the purpose of my code I found out this decision which corresponds with some of the answers above:

ES6 variant:

const checkType = o => Object.prototype
                    .toString
                    .call(o)
                    .replace(/\[|object\s|\]/g, '')
                    .toLowerCase();

ES5 variant:

function checkType(o){
   return Object.prototype
                    .toString
                    .call(o)
                    .replace(/\[|object\s|\]/g, '')
                    .toLowerCase();
}

You can use it very simply:

checkType([]) === 'array'; // true
checkType({}) === 'object'; // true
checkType(1) === 'number'; // true
checkType('') === 'string'; // true
checkType({}.p) === 'undefined'; // true
checkType(null) === 'null'; // true

and so on..

Answer 28

const isObject = function(obj) {
  const type = typeof obj;
  return type === 'function' || type === 'object' && !!obj;
};

!!obj is shorthand for checking if obj is truthy (to filter out null)

Answer 29

if(typeof value === 'object' && value.constructor === Object)
{
    console.log("This is an object");
}

Answer 30

It is an old question but thought to leave this here. Most people are checking if the variable is {} meaning a key-value paired and not what is the underline construct that JavaScript is using for a given thing, cuz to be honest mostly everything in JavaScript is an object. So taking that out of the way. If you do...

let x = function() {}
typeof x === 'function' //true
x === Object(x) // true
x = []
x === Object(x) // true

// also
x = null
typeof null // 'object'

Most of the time what we want is to know if we have a resource object from an API or our database call returned from the ORM. We can then test if is not an Array, is not null, is not typeof 'function', and is an Object

// To account also for new Date() as @toddmo pointed out

x instanceof Object && x.constructor === Object

x = 'test' // false
x = 3 // false
x = 45.6 // false
x = undefiend // false
x = 'undefiend' // false
x = null // false
x = function(){} // false
x = [1, 2] // false
x = new Date() // false
x = {} // true

Answer 31

function isObjectLike(value) {
  return value != null && typeof value == 'object' && !Array.isArray(value);
}

Based from lodash

Answer 32

If explicitly want to check if the given value is {}.

function isObject (value) {
 return value && typeof value === 'object' && value.constructor === Object;
}

Answer 33

i found a "new" way to do just this kind of type checking from this SO question: Why does instanceof return false for some literals?

from that, i created a function for type checking as follows:

function isVarTypeOf(_var, _type){
    try {
        return _var.constructor === _type;
    } catch(ex) {
        return false;         //fallback for null or undefined
    }
}

then you can just do:

console.log(isVarTypeOf('asdf', String));   // returns true
console.log(isVarTypeOf(new String('asdf'), String));   // returns true
console.log(isVarTypeOf(123, String));   // returns false
console.log(isVarTypeOf(123, Number));   // returns true
console.log(isVarTypeOf(new Date(), String));   // returns false
console.log(isVarTypeOf(new Date(), Number));   // returns false
console.log(isVarTypeOf(new Date(), Date));   // returns true
console.log(isVarTypeOf([], Object));   // returns false
console.log(isVarTypeOf([], Array));   // returns true
console.log(isVarTypeOf({}, Object));   // returns true
console.log(isVarTypeOf({}, Array));   // returns false
console.log(isVarTypeOf(null, Object));   // returns false
console.log(isVarTypeOf(undefined, Object));   // returns false
console.log(isVarTypeOf(false, Boolean));   // returns true

this is tested on Chrome 56, Firefox 52, Microsoft Edge 38, Internet Explorer 11, Opera 43

edit:
if you also want to check if a variable is null or undefined, you can use this instead:

function isVarTypeOf(_var, _type){
    try {
        return _var.constructor === _type;
    } catch(ex) {
        return _var == _type;   //null and undefined are considered the same
        // or you can use === if you want to differentiate them
    }
}

var a = undefined, b = null;
console.log(isVarTypeOf(a, undefined)) // returns true
console.log(isVarTypeOf(b, undefined)) // returns true
console.log(isVarTypeOf(a, null)) // returns true

update from inanc's comment: challenge accepted :D

if you want to loose compare objects you can try this way:

function isVarTypeOf(_var, _type, looseCompare){
    if (!looseCompare){
        try {
            return _var.constructor === _type;
        } catch(ex){
            return _var == _type;
        }
    } else {
        try{
            switch(_var.constructor){
                case Number:
                case Function:
                case Boolean:
                case Symbol:
                case Date:
                case String:
                case RegExp:
                    // add all standard objects you want to differentiate here
                    return _var.constructor === _type;
                case Error:
                case EvalError:
                case RangeError:
                case ReferenceError:
                case SyntaxError:
                case TypeError:
                case URIError:
                    // all errors are considered the same when compared to generic Error
                    return (_type === Error ? Error : _var.constructor) === _type;
                case Array:
                case Int8Array:
                case Uint8Array:
                case Uint8ClampedArray:
                case Int16Array:
                case Uint16Array:
                case Int32Array:
                case Uint32Array:
                case Float32Array:
                case Float64Array:
                    // all types of array are considered the same when compared to generic Array
                    return (_type === Array ? Array : _var.constructor) === _type;
                case Object:
                default:
                    // the remaining are considered as custom class/object, so treat it as object when compared to generic Object
                    return (_type === Object ? Object : _var.constructor) === _type;
            }
        } catch(ex){
            return _var == _type;   //null and undefined are considered the same
            // or you can use === if you want to differentiate them
        }
    }
}

that way, you can do just like inanc's comment:

isVarTypeOf(new (function Foo(){}), Object); // returns false
isVarTypeOf(new (function Foo(){}), Object, true); // returns true

or

Foo = function(){};
Bar = function(){};
isVarTypeOf(new Foo(), Object);   // returns false
isVarTypeOf(new Foo(), Object, true);   // returns true
isVarTypeOf(new Bar(), Foo, true);   // returns false
isVarTypeOf(new Bar(), Bar, true);   // returns true
isVarTypeOf(new Bar(), Bar);    // returns true

Answer 34

What I like to use is this

function isObject (obj) {
  return typeof(obj) == "object" 
        && !Array.isArray(obj) 
        && obj != null 
        && obj != ""
        && !(obj instanceof String)  }

I think in most of the cases a Date must pass the check as an Object, so I do not filter dates out

Answer 35

you can just use JSON.stringify to test your Object, like this:

var test = {}
if(JSON.stringify(test)[0] === '{') {
  console.log('this is a Object')
}

Answer 36

Consider - typeof bar === "object" to determine if bar is an object

Although typeof bar === "object" is a reliable way of checking if bar is an object, the surprising gotcha in JavaScript is that null is also considered an object!

Therefore, the following code will, to the surprise of most developers, log true (not false) to the console:

var bar = null; console.log(typeof bar === "object"); // logs true! As long as one is aware of this, the problem can easily be avoided by also checking if bar is null:

console.log((bar !== null) && (typeof bar === "object")); // logs false To be entirely thorough in our answer, there are two other things worth noting:

First, the above solution will return false if bar is a function. In most cases, this is the desired behavior, but in situations where you want to also return true for functions, you could amend the above solution to be:

console.log((bar !== null) && ((typeof bar === "object") || (typeof bar === "function"))); Second, the above solution will return true if bar is an array (e.g., if var bar = [];). In most cases, this is the desired behavior, since arrays are indeed objects, but in situations where you want to also false for arrays, you could amend the above solution to be:

console.log((bar !== null) && (typeof bar === "object") && (toString.call(bar) !== "[object Array]")); However, there’s one other alternative that returns false for nulls, arrays, and functions, but true for objects:

console.log((bar !== null) && (bar.constructor === Object)); Or, if you’re using jQuery:

console.log((bar !== null) && (typeof bar === "object") && (! $.isArray(bar)));

ES5 makes the array case quite simple, including its own null check:

console.log(Array.isArray(bar));

Answer 37

We can check this with only a single line, here obj can be any value (including null)

obj?.__proto__ === Object.prototype

or

obj?.constructor.name === 'Object';

Answer 38

Different approach via adverse selection:

I reviewed all answers here and am still missing a different approach. According to MDN docs, objects in JavaScript are non-primitive values. Primitive values:

1. Boolean type
2. Null type
3. Undefined type
4. Number type
5. BigInt type
6. String type
7. Symbol type

Based on this fact, the following approach is practising an adverse selection:

// Check if value is primitive value according to MDN docs:
    function isPrimitiveValue(value) {
        return (
                typeof value === "symbol" ||
                typeof value === "string" ||
                typeof value === "number" ||
                typeof value === "boolean" ||
                typeof value === "undefined" ||
                value === null ||
                typeof value === "bigint"
              );
            };

// Check if input is not primitive value, therefore object: 
    function isObject(input) {
            if (isPrimitiveValue(input)) {
              return false;
            }
            return true;
          };
    
console.log(isObject(10)); // false
console.log(isObject([{foo: "bar"}])); // true
console.log(isObject({ a: 1, b: 2, c: 3 })); // true
console.log(isObject(Object.getPrototypeOf("foo"))); // true
console.log(isObject(Symbol("foo"))); // false
console.log(isObject(BigInt(9007199254740991))); // false
console.log(isObject(null)); // false
console.log(isObject(undefined)); // false
console.log(isObject(false)); // false
console.log(isObject({})); // true

Answer 39

If you are already using AngularJS then it has a built in method which will check if its an object (without accepting null).

angular.isObject(...)

Answer 40

Works for all data types. It displays only objects

if (data && typeof data === 'object' && !Array.isArray(data)) {

Answer 41

The simplest way to determine if a variable is an Object or not:

first: Evaluate the type of Object

second: Getting an Array property from an Object must returns undefined (For example length is an Array property which does not work on Object)

so:

if (_object instanceof Object && _object.length === undefined) {
// here you can be sure that you have a curly bracket object :)
}

Answer 42

This is tricky because an array is an object type, a function is an object type and the actual object {} is also object type

Problem

const arr = []
const fun = function(){}
const actualObj = {}

arr instanceof Object // true
fun instanceof Object // true
actualObj instanceof Object // true

So the goal is actualObj must return true and everything else must return false

actualObj instanceof Object && !(actualObj instanceof Array) && !(typeof actualObj === 'function') // true

Answer 43

Its depends on use-case, if we do not want to allow array and functions to be an Object, we can use the underscore.js builtin functions.

    function xyz (obj) { 
       if (_.isObject(obj) && !_.isFunction(obj) && !_.isArray(obj)) {
         // now its sure that obj is an object 
       } 
    }

Answer 44

Mostly typeof obj[index] === 'object'is used, but it will return also function and #document which are an objects. It depends up to you if it need to be included in the result.

Basically you can do a test code that filtering out if a particular elements is an object by checking the output in your console. Here you can run a code just for a sample:

function cekObject(obj, index) {  
  if (!obj.tagName) {

    //test case #1      
    if (typeof obj === 'object') {
      console.log('obj['+ index +'] is listed as an object');
    } 
    
  }
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.2.3/jquery.min.js"></script>
<script>
  function updateFilters() {
    var object = $('.j-image');
    $('.juicer-feed').empty();
    
    for(var index in object) {
      cekObject(object[index], index);
    }; 
  }
</script>

<ul class="juicer-feed" data-feed-id="chetabahana" data-after="updateFilters()"></ul>
<script src="https://assets.juicer.io/embed.js"></script>

Answer 45

Simple working solution:

function isObject(value) {
    return !(value instanceof Date) && !Array.isArray(value) && !Object.is(value, null) && !Object.is(value, undefined) && !(value instanceof Function)
}

Answer 46

I think the reason there are so many answers is that lots of things are object in javascript whether you like it or not.

You can iterate over "keys" of an array just like any other object...

var key, 
    arr = ['one', 'two', 'three'];
for (key in arr)
    console.log(`${key}=${arr[key]}`);

console.log(arr[1]);
console.log(arr['1']);

// 0=one
// 1=two
// 2=three
// two
// two

Array is special (like many objects) in that it has some properties/methods that a generic Object does not have (e.g. length, forEach, etc).

So really this question should be: How do I filter to specific types of objects?

After all, I could easily implement my own array or regex or symbol, it would also be an object but probably pass through all the various "is it a real object?" tests....because it IS a real object.

So you want to filter to certain types of javascript objects...

The best way is to just do feature testing. Do you care if it has a length property for instance? Example: A NodeList in the browser looks like an array and can be iterated like an array, but is not an array.

Anyway, if you just want to filter out specific types of objects, only you can define what you want to filter. Do you want to filter out RegExp? Date? Array? Browser DOM objects? Only you can decide what your filter chain looks like. You can use a fall-through switch to build your filter compactly.

function typeOfIs(val, type) {
    return typeof val == type;
}

function constructorIs(val, constructor) {
    return val && constructor && val.constructor === constructor;
}

function isObject(val) {
    // catch the easy non-object values
    if (!typeOfIs(val, 'object')) 
        return false;

    // catch the cases you don't want to consider to be 
    // "real" objects for your use-case
    switch (true) {
        case val === null:
        case Array.isArray(val):
        case typeOfIs(val, 'function'):
        case constructorIs(val, RegExp):
            return false;
        default:
            return true;
    }
}
function test(val) {
    console.log(Object.prototype.toString.call(val)+': '+isObject(val));
}
test(undefined);
test(null);
test(function () {});
test(Symbol('foo'));
test(1);
test(true);
test(false);
test('hello world');
test([]);
test(/.*/g);
test(new Date()); // true (because we didn't filter for it)
test({});  // true

feature testing

A better thing though would probably be to ask WHY you want to filter and maybe just test if the properties/functions you need/expect are present on a given variable...if they are present, work with the variable and don't worry about whether it is some type of object or another. If they aren't present, then just throw an API error that you were passed some value that was not of the right type (ie missing the expected properties/functions).

e.g.

if (typeof someVariable.hasOwnProperty == 'function')
    // ...

Answer 47

I am penning this answer because it is an entirely different approach to any of the other 50+ answers here due to the specific definition of "object".

This is for a library intended for public use, and this "object" will be provided by a user as an argument to class methods. The code also uses that externally created object to store additional properties, as a convenience. Requiring that the object be extensible doesn't strike me as a hardship on the user, and it allows me to use this simple, clean method for validating the user object, without typeof, instanceof or string comparisons of any kind. The object can be Array, Promise, any extensible type because it doesn't matter, so long as the object has the properties I require to be set and I can assign a value to additional properties.

Here's my isObject function:

function isObject(o) {
    try {
        o._ = 1;
        return (o._ === 1); // return false if you want to rely on strict mode throwing
    } catch(e) {
        return false;
    }     
}

You can set any property name and any value except undefined. If you don't like the lingering test property you can do this:

function isObject(o) {
    try {
        o._ = 1;
        const val = (o._ === 1); // ditto re: strict mode
        delete o._;
        return val;
    } catch(e) {
        return false;
    }     
}

Answer 48

use typeof(my_obj) will tells which type of variable it is.

for Array: Array.isArray(inp) or [] isinstanceof Array

if it is object will show 'object'

simple JS function,

function isObj(v) {
    return typeof(v) == "object"
}

Eg:

function isObj(v) {
    return typeof(v) == "object"
}

var samp_obj = {
   "a" : 1,
   "b" : 2,
   "c" : 3
}

var num = 10;
var txt = "Hello World!"
var_collection = [samp_obj, num, txt]
for (var i in var_collection) {
  if(isObj(var_collection[i])) {
     console.log("yes it is object")
  }
  else {
     console.log("No it is "+ typeof(var_collection[i]))
  }
}

Answer 49

Remember guys that typeof new Date() is "object".

So if you're looking for { key: value } objects, a date object is invalid.

Finally then: o => o && typeof o === 'object' && !(o instanceof Date) is a better answer to your question in my opinion.

Answer 50

isObject() checks whether passed argument is a object or not, using optional chaining and latest standards:

const isObject = (value) => { 
    return value?.constructor === Object;
}

Answer 51

Objects in JavaScript include arrays, functions, regular expressions, and more. Anything that is not a primitive in JavaScript is an object.

My solution tests the use of the in operator which is only supported by objects. Trying to use in with a primitive will throw an error.

From MDN:

in operator

The in operator returns true if the specified property is in the specified object or its prototype chain.

Exceptions

TypeError

Thrown if object is not an object (i.e. a primitive).

This function is concise, works without fail, and unlike the other answers here handles edge cases like document.all successfully. Tested and works in old browsers (ES3 and up).

function isObject(obj) {
    try {
        // Test obj with in operator
        return 0 in obj || true;
    }
    catch (e) {
        // obj is an object unless e is a TypeError
        return e.constructor!=TypeError;
    }
}

If you don't want the overhead of a function and a try/catch this conditional statement also works:

if (typeof obj in{"function":1,object:1,undefined:1} && obj!==null && obj!==void 0) {
    // obj is an object. Remember that functions and document.all are objects too.
}

Answer 52

A little NodeJS console experiment based on the reading of Matt Fenwick's third option to his complete answer above. Just a little tweak to get true or false.

The following return false for the object test.

> if(Object.getPrototypeOf('v') === Object.prototype){console.log(true);}else{console.log(false);}
false
undefined
> if(Object.getPrototypeOf(1) === Object.prototype){console.log(true);}else{console.log(false);}
false
undefined
> if(Object.getPrototypeOf(false) === Object.prototype){console.log(true);}else{console.log(false);}
false
undefined
> if(Object.getPrototypeOf(['apple']) === Object.prototype){console.log(true);}else{console.log(false);}
false
undefined

The object will return true.

> if(Object.getPrototypeOf({'this':10}) === Object.prototype){console.log(true);}else{console.log(false);}
true
undefined

Answer 53

var isArray=function(value){
    if(Array.isArray){
        return Array.isArray(value);
    }else{
        return Object.prototype.toString.call(value)==='[object Array]';
    }
}
var isObject=function(value){
    return value !== null&&!isArray(value) && typeof value === 'object';
}

var _val=new Date;
console.log(isObject(_val));//true
console.log(Object.prototype.toString.call(_val)==='[object Object]');//false

Answer 54

You can do this easily with toString() method of Object.prototype

if(Object.prototype.toString.call(variable) == "[object Object]"){
   doSomething();
}

or

if(Object.prototype.toString.call(variable).slice(8,-1).toLowerCase() == "object"){
   doSomething();
}

Answer 55

I have a code snippet that works. I find it confusing when the whole piece of code is not given, so I just created it myself:

    <!DOCTYPE html>
    <html>
    <body>
    <button onclick="myFunc()">Try it</button>

    <script>
    var abc = new Number();
    // var abc = 4;
    //this is a code variation which will give a diff alert

    function myFunc()
    {
    if(abc && typeof abc === "object")
    alert('abc is an object and does not return null value');
    else
    alert('abc is not an object');
    }
    </script>

    </body>
    </html>