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Say I want to match the presence of the phrase Sortes\index[persons]{Sortes} in the phrase test Sortes\index[persons]{Sortes} text.

Using python re I could do this:

>>> search = re.escape('Sortes\index[persons]{Sortes}')
>>> match = 'test Sortes\index[persons]{Sortes} text'
>>> re.search(search, match)
<_sre.SRE_Match object; span=(5, 34), match='Sortes\\index[persons]{Sortes}'>

This works, but I want to avoid the search pattern Sortes to give a positive result on the phrase test Sortes\index[persons]{Sortes} text.

>>> re.search(re.escape('Sortes'), match)
<_sre.SRE_Match object; span=(5, 11), match='Sortes'>

So I use the \b pattern, like this:

search = r'\b' + re.escape('Sortes\index[persons]{Sortes}') + r'\b'
match = 'test Sortes\index[persons]{Sortes} text'
re.search(search, match)

Now, I don't get a match.

If the search pattern does not contain any of the characters []{}, it works. E.g.:

>>> re.search(r'\b' + re.escape('Sortes\index') + r'\b', 'test Sortes\index test')
<_sre.SRE_Match object; span=(5, 17), match='Sortes\\index'>

Also, if I remove the final r'\b', it also works:

re.search(r'\b' + re.escape('Sortes\index[persons]{Sortes}'), 'test Sortes\index[persons]{Sortes} test')
<_sre.SRE_Match object; span=(5, 34), match='Sortes\\index[persons]{Sortes}'>

Furthermore, the documentation says about \b

Note that formally, \b is defined as the boundary between a \w and a \W character (or vice versa), or between \w and the beginning/end of the string.

So I tried replacing the final \b with (\W|$):

>>> re.search(r'\b' + re.escape('Sortes\index[persons]{Sortes}') + '(\W|$)', 'test Sortes\index[persons]{Sortes} test')
<_sre.SRE_Match object; span=(5, 35), match='Sortes\\index[persons]{Sortes} '>

Lo and behold, it works! What is going on here? What am I missing?

Wiktor Stribiżew
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Stenskjaer
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    `}`, the last character of your pattern is a non-word-character, as is the space following it. Thus there is no word boundary and no match. If the last character is `s`, it is a word-character, thus there is a word boundary. – Sebastian Proske Jul 17 '17 at 13:36

2 Answers2

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See what a word boundary matches:

A word boundary can occur in one of three positions:

  • Before the first character in the string, if the first character is a word character.
  • After the last character in the string, if the last character is a word character.
  • Between two characters in the string, where one is a word character and the other is not a word character.

In your pattern }\b only matches if there is a word char after } (a letter, digit or _).

When you use (\W|$) you require a non-word or end of string explicitly.

A solution is adaptive word boundaries:

re.search(r'(?:(?!\w)|\b(?=\w)){}(?:(?<=\w)\b|(?<!\w))'.format(re.escape('Sortes\index[persons]{Sortes}')), 'test Sortes\index[persons]{Sortes} test')

Or equivalent:

re.search(r'(?!\B\w){}(?<!\w\B)'.format(re.escape('Sortes\index[persons]{Sortes}')), 'test Sortes\index[persons]{Sortes} test')

Here, adaptive dynamic word boundaries are used that mean the following:

  • (?:(?!\w)|\b(?=\w)) (equal to (?!\B\w)) - a left-hand boundary, making sure the current position is at the word boundary if the next char is a word char, or no context restriction is applied if the next char is not a word char (note that you will need to use (?:\B(?!\w)|\b(?=\w)) if you want to disallow a word char immediately on the left if the next char is not a word char)
  • (?:(?<=\w)\b|(?<!\w)) (equal to (?<!\w\B)) - a right-hand boundary, making sure the current position is at the word boundary if the previous char is a word char, or no context restriction is applied if the previous char is not a word char (note that you will need to use (?:(?<=\w)\b|\B(?<!\w)) if you want to disallow a word char immediately on the right if the preceding char is not a word char).

You might also consider using unambiguous word boundaries based on negative lookarounds in these cases:

re.search(r'(?<!\w){}(?!\w)'.format(re.escape('Sortes\index[persons]{Sortes}')), 'test Sortes\index[persons]{Sortes} test')

Here, (?<!\w) negative lookbehind will fail the match if there is a word char immediately to the left of the current location, and (?!\w) negative lookahead will fail the match if there is a word char immediately to the right of the current location.

Which to choose? Adaptive word boundaries are more lenient compared to unambiguous word boundaries as the latter presume there must be no word chars on both ends of a match, while the former allow matching leading and trailing non-word chars in any context.

Note: It is easy to customize these lookaround patterns further (say, to only fail the match if there are letters around the pattern, use [^\W\d_] instead of \w, or if you only allow matches around whitespaces, use whitespace boundaries (?<!\S) / (?!\S) lookaround boundaries).

Wiktor Stribiżew
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  • I like the suggestion about the negative look-arounds. This regex match is in a pretty hot part of my code, so I am worried about the performance of the match. Would that be a concern the with look-arounds? – Stenskjaer Jul 17 '17 at 13:51
  • @Stenskjaer `\b` is also a zero-width assertion, like any other lookaround. Since these lookaround patterns only contain single atoms, the overhead should not be too different from the one you already had with `\b`s. Well, you may set a quick performance test if you are worried, but this is the only correct regex way I can think of to solve the problem. – Wiktor Stribiżew Jul 17 '17 at 13:54
  • True! I just tested it myself. There is not (detectable) difference in performance. Thanks. – Stenskjaer Jul 17 '17 at 13:58
  • Adaptative word-boundaries can be written like that: `(?:(?!\w)|\b(?=\w))` => `(?!\B\w)` and `(?:(?<=\w)\b|(?<!\w))` => `(?<!\w\B)` – Casimir et Hippolyte Feb 08 '22 at 13:27
  • Also, I recorded a [*"Dynamic adaptive word boundaries"*](https://www.youtube.com/watch?v=ngbxagE2b68) YT video where I explain the constructs in detail. – Wiktor Stribiżew Nov 16 '22 at 08:58
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I think this is what you're running into:

\b lands on the boundary of \w and \W, but in the example that doesn't work. '{Sortes}\b' is the boundary between \W and \W because of the '}', which doesn't match [a-zA-Z0-9_], the ordinary set for \w.

Benjamin Hicks
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