How do I pass parameters to a jar file at the time of execution?

Question

How do I pass parameters to a JAR file at the time of execution?

Answer 1

To pass arguments to the jar:

java -jar myjar.jar one two

You can access them in the main() method of "Main-Class" (mentioned in the manifest.mf file of a JAR).

String one = args[0];  
String two = args[1];  

Answer 2

The JAVA Documentation says:

java [ options ] -jar file.jar [ argument ... ]

and

... Non-option arguments after the class name or JAR file name are passed to the main function...

Maybe you have to put the arguments in single quotes.

Answer 3

You can do it with something like this, so if no arguments are specified it will continue anyway:

public static void main(String[] args) {
    try {
        String one = args[0];
        String two = args[1];
    }
    catch (ArrayIndexOutOfBoundsException e){
        System.out.println("ArrayIndexOutOfBoundsException caught");
    }
    finally {

    }
}

And then launch the application:

java -jar myapp.jar arg1 arg2

Answer 4

java [ options ] -jar file.jar [ argument ... ]

if you need to pass the log4j properties file use the below option

-Dlog4j.configurationFile=directory/file.xml


java -Dlog4j.configurationFile=directory/file.xml -jar <JAR FILE> [arguments ...]

Answer 5

Incase arguments have spaces in it, you can pass like shown below.

java -jar myjar.jar 'first argument' 'second argument'