I think the reason that the browser clean the input value it is because a string with two dots it is not a number.
Some corrections about your code:
You need to change your expression regular if you want to accept number with decimal part. Now, you are only express that you want to accept digits [0-9] and no more chars.
To accomplish want you want, you need to change /[^\d]/g
to /[^\d.]/g
.
document.getElementById("integer").addEventListener('input', restrictToInteger);
function restrictToInteger()
{
this.value = this.value.replace(/[^\d.]/g, '');
}
<input type="number" id="integer" />
HOWEVER: If you define your input as number type, the regular expression is not needed. So, you just need to define the input like this and should your to your case:
<input type="number" id="integer" />
[THE SOLUTION]
To fully meet your needs, I came with a solution that catch the keydown event of the input and check if there is any '.' on the input. If yes, I prevent the char to go to the input.
document.getElementById("integer").addEventListener('keydown', restrictToInteger);
var lastCodeWasDot = false;
function restrictToInteger(e)
{
var inputValue = document.getElementById("integer").value;
var isDot = false;
var isDot = (e.keyCode && e.keyCode == 110) || (e.charCode && e.charCode == 190);
console.log(e.keyCode);
if(isDot && (inputValue.indexOf(".") > -1 || inputValue == "" || lastCodeWasDot)) {
e.preventDefault();
}
lastCodeWasDot = isDot;
}
<input type="number" id="integer" />
Explaning the solution:
The line of code var isDot = (e.keyCode && e.keyCode == 110) || (e.charCode && e.keyCode == 190) || false;
is needed because cross browser compatibility.
I don't now why but if you try to get the value from an input number type in the firefox, and if the value finishes with a dot, the value that you will get will be without the last dot of the input. To fix that, I needed to add the variable lastCodeWasDot
to fix this issue.
NOTE: The number input can accept floating point numbers, including negative symbols and the e or E character (check out this post)