Reading video data and writing to another file java

Question

I am reading a video file data in bytes and sending to another file but the received video file is not playing properly and is chattered.

Can anyone explain me why this is happening and a solution is appreciated.

My code is as follows

import java.io.*;

public class convert {

  public static void main(String[] args) {

    //create file object
    File file = new File("B:/music/Billa.mp4");

    try
    {
      //create FileInputStream object
      FileInputStream fin = new FileInputStream(file);


       byte fileContent[] = new byte[(int)file.length()];
       fin.read(fileContent);

       //create string from byte array
       String strFileContent = new String(fileContent);

       System.out.println("File content : ");
       System.out.println(strFileContent);

       File dest=new File("B://music//a.mp4");
       BufferedWriter bw=new BufferedWriter(new FileWriter(dest));
       bw.write(strFileContent+"\n");
       bw.flush();

    }
    catch(FileNotFoundException e)
    {
      System.out.println("File not found" + e);
    }
    catch(IOException ioe)
    {
      System.out.println("Exception while reading the file " + ioe);
    }
  }
}

1) What does this have to do with streamed video? The source of video is a file! 2) **You cannot treat video data as if it is strings or text! It is not.** — Andrew Thompson, Apr 19 '13 at 01:36
`new byte[(int)file.length()]` may truncate bytes from the file, as `int` is smaller then `long`. You need to copy the file in chuncks — MadProgrammer, Apr 19 '13 at 01:42
Thanks for your reply.I want to encrypt the data so m reading file into strings. — Krish, Apr 19 '13 at 01:50

Jakub Orsula · Answer 1 · 2020-12-24T20:48:22.407

This question might be dead but someone might find this useful.

You can't handle video as string. This is the correct way to read and write (copy) any file using Java 7 or higher.

Please note that size of buffer is processor-dependent and usually should be a power of 2. See this answer for more details.

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;

public class FileCopy {
public static void main(String args[]) {
    
    final int BUFFERSIZE = 4 * 1024;
    String sourceFilePath = "D:\\MyFolder\\MyVideo.avi";
    String outputFilePath = "D:\\OtherFolder\\MyVideo.avi";

    try(
            FileInputStream fin = new FileInputStream(new File(sourceFilePath));
            FileOutputStream fout = new FileOutputStream(new File(outputFilePath));
            ){
        
        byte[] buffer = new byte[BUFFERSIZE];
        
        while(fin.available() != 0) {
            bytesRead = fin.read(buffer);
            fout.write(buffer, 0, bytesRead);
        }
        
    }
    catch(Exception e) {
        System.out.println("Something went wrong! Reason: " + e.getMessage());
    }

    }
}

Suchin Madusha · Answer 2 · 2021-01-24T17:11:28.380

2

Hope this also helpful for you - This can read and write a file into another file (You can use any file type to do that)

import java.io.FileInputStream;
import java.io.FileOutputStream;

public class Copy {
    public static void main(String[] args) throws Exception {
        FileInputStream input = new FileInputStream("input.mp4");      //input file
        byte[] data = input.readAllBytes();
        FileOutputStream output = new FileOutputStream("output.mp4");  //output file
        output.write(data);
        output.close();
    }
}

edited Jan 24 '21 at 17:11

answered Jan 22 '21 at 08:43

Suchin Madusha

132
9

1

Hi Suchin and welcome to StackOverflow. Since the question is very old and appears to have already been thoroughly answered, you should explain how your solution improves on the previous ones. As a general rule, please avoid pasting code without explanation. – MathMax Jan 22 '21 at 09:25

score 0 · Answer 3 · answered Mar 17 '15 at 08:37

import java.awt.image.BufferedImage;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.FileWriter;

import javax.imageio.ImageIO;

public class Reader {

    public Reader() throws Exception{


        File file = new File("C:/Users/Digilog/Downloads/Test.mp4");

        FileInputStream fin = new FileInputStream(file);
        byte b[] = new byte[(int)file.length()];
        fin.read(b);

        File nf = new File("D:/K.mp4");
        FileOutputStream fw = new FileOutputStream(nf);
        fw.write(b);
        fw.flush();
        fw.close();

    }

}

I have used some of header files for other reasons. Do not bother about that — kousik Mridha, Mar 17 '15 at 08:38

score 0 · Answer 4 · answered Apr 14 '18 at 16:48

In addition to Jakub Orsula's answer, one needs to check the result of read operation to prevent garbage being written to end of file in last iteration.

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;

public class FileCopy {
public static void main(String args[]) {

    final int BUFFERSIZE = 4 * 1024;
    String sourceFilePath = "D:\\MyFolder\\MyVideo.avi";
    String outputFilePath = "D:\\OtherFolder\\MyVideo.avi";

    try(
            FileInputStream fin = new FileInputStream(new File(sourceFilePath));
            FileOutputStream fout = new FileOutputStream(new File(outputFilePath));
            ){

        byte[] buffer = new byte[BUFFERSIZE];
        int bytesRead;

        while(fin.available() != 0) {
        bytesRead = fin.read(buffer);
        fout.write(buffer, 0, bytesRead);
        }

    }
    catch(Exception e) {
        System.out.println("Something went wrong! Reason: " + e.getMessage());
    }

    }
}

Reading video data and writing to another file java

4 Answers4