What is the purpose of __slots__
in Python — especially with respect to when I would want to use it, and when not?
14 Answers
In Python, what is the purpose of
__slots__
and what are the cases one should avoid this?
TLDR:
The special attribute __slots__
allows you to explicitly state which instance attributes you expect your object instances to have, with the expected results:
- faster attribute access.
- space savings in memory.
The space savings is from
- Storing value references in slots instead of
__dict__
. - Denying
__dict__
and__weakref__
creation if parent classes deny them and you declare__slots__
.
Quick Caveats
Small caveat, you should only declare a particular slot one time in an inheritance tree. For example:
class Base:
__slots__ = 'foo', 'bar'
class Right(Base):
__slots__ = 'baz',
class Wrong(Base):
__slots__ = 'foo', 'bar', 'baz' # redundant foo and bar
Python doesn't object when you get this wrong (it probably should), problems might not otherwise manifest, but your objects will take up more space than they otherwise should. Python 3.8:
>>> from sys import getsizeof
>>> getsizeof(Right()), getsizeof(Wrong())
(56, 72)
This is because the Base's slot descriptor has a slot separate from the Wrong's. This shouldn't usually come up, but it could:
>>> w = Wrong()
>>> w.foo = 'foo'
>>> Base.foo.__get__(w)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: foo
>>> Wrong.foo.__get__(w)
'foo'
The biggest caveat is for multiple inheritance - multiple "parent classes with nonempty slots" cannot be combined.
To accommodate this restriction, follow best practices: Factor out all but one or all parents' abstraction which their concrete class respectively and your new concrete class collectively will inherit from - giving the abstraction(s) empty slots (just like abstract base classes in the standard library).
See section on multiple inheritance below for an example.
Requirements:
To have attributes named in
__slots__
to actually be stored in slots instead of a__dict__
, a class must inherit fromobject
(automatic in Python 3, but must be explicit in Python 2).To prevent the creation of a
__dict__
, you must inherit fromobject
and all classes in the inheritance must declare__slots__
and none of them can have a'__dict__'
entry.
There are a lot of details if you wish to keep reading.
Why use __slots__
: Faster attribute access.
The creator of Python, Guido van Rossum, states that he actually created __slots__
for faster attribute access.
It is trivial to demonstrate measurably significant faster access:
import timeit
class Foo(object): __slots__ = 'foo',
class Bar(object): pass
slotted = Foo()
not_slotted = Bar()
def get_set_delete_fn(obj):
def get_set_delete():
obj.foo = 'foo'
obj.foo
del obj.foo
return get_set_delete
and
>>> min(timeit.repeat(get_set_delete_fn(slotted)))
0.2846834529991611
>>> min(timeit.repeat(get_set_delete_fn(not_slotted)))
0.3664822799983085
The slotted access is almost 30% faster in Python 3.5 on Ubuntu.
>>> 0.3664822799983085 / 0.2846834529991611
1.2873325658284342
In Python 2 on Windows I have measured it about 15% faster.
Why use __slots__
: Memory Savings
Another purpose of __slots__
is to reduce the space in memory that each object instance takes up.
My own contribution to the documentation clearly states the reasons behind this:
The space saved over using
__dict__
can be significant.
SQLAlchemy attributes a lot of memory savings to __slots__
.
To verify this, using the Anaconda distribution of Python 2.7 on Ubuntu Linux, with guppy.hpy
(aka heapy) and sys.getsizeof
, the size of a class instance without __slots__
declared, and nothing else, is 64 bytes. That does not include the __dict__
. Thank you Python for lazy evaluation again, the __dict__
is apparently not called into existence until it is referenced, but classes without data are usually useless. When called into existence, the __dict__
attribute is a minimum of 280 bytes additionally.
In contrast, a class instance with __slots__
declared to be ()
(no data) is only 16 bytes, and 56 total bytes with one item in slots, 64 with two.
For 64 bit Python, I illustrate the memory consumption in bytes in Python 2.7 and 3.6, for __slots__
and __dict__
(no slots defined) for each point where the dict grows in 3.6 (except for 0, 1, and 2 attributes):
Python 2.7 Python 3.6
attrs __slots__ __dict__* __slots__ __dict__* | *(no slots defined)
none 16 56 + 272† 16 56 + 112† | †if __dict__ referenced
one 48 56 + 272 48 56 + 112
two 56 56 + 272 56 56 + 112
six 88 56 + 1040 88 56 + 152
11 128 56 + 1040 128 56 + 240
22 216 56 + 3344 216 56 + 408
43 384 56 + 3344 384 56 + 752
So, in spite of smaller dicts in Python 3, we see how nicely __slots__
scale for instances to save us memory, and that is a major reason you would want to use __slots__
.
Just for completeness of my notes, note that there is a one-time cost per slot in the class's namespace of 64 bytes in Python 2, and 72 bytes in Python 3, because slots use data descriptors like properties, called "members".
>>> Foo.foo
<member 'foo' of 'Foo' objects>
>>> type(Foo.foo)
<class 'member_descriptor'>
>>> getsizeof(Foo.foo)
72
Demonstration of __slots__
:
To deny the creation of a __dict__
, you must subclass object
. Everything subclasses object
in Python 3, but in Python 2 you had to be explicit:
class Base(object):
__slots__ = ()
now:
>>> b = Base()
>>> b.a = 'a'
Traceback (most recent call last):
File "<pyshell#38>", line 1, in <module>
b.a = 'a'
AttributeError: 'Base' object has no attribute 'a'
Or subclass another class that defines __slots__
class Child(Base):
__slots__ = ('a',)
and now:
c = Child()
c.a = 'a'
but:
>>> c.b = 'b'
Traceback (most recent call last):
File "<pyshell#42>", line 1, in <module>
c.b = 'b'
AttributeError: 'Child' object has no attribute 'b'
To allow __dict__
creation while subclassing slotted objects, just add '__dict__'
to the __slots__
(note that slots are ordered, and you shouldn't repeat slots that are already in parent classes):
class SlottedWithDict(Child):
__slots__ = ('__dict__', 'b')
swd = SlottedWithDict()
swd.a = 'a'
swd.b = 'b'
swd.c = 'c'
and
>>> swd.__dict__
{'c': 'c'}
Or you don't even need to declare __slots__
in your subclass, and you will still use slots from the parents, but not restrict the creation of a __dict__
:
class NoSlots(Child): pass
ns = NoSlots()
ns.a = 'a'
ns.b = 'b'
And:
>>> ns.__dict__
{'b': 'b'}
However, __slots__
may cause problems for multiple inheritance:
class BaseA(object):
__slots__ = ('a',)
class BaseB(object):
__slots__ = ('b',)
Because creating a child class from parents with both non-empty slots fails:
>>> class Child(BaseA, BaseB): __slots__ = ()
Traceback (most recent call last):
File "<pyshell#68>", line 1, in <module>
class Child(BaseA, BaseB): __slots__ = ()
TypeError: Error when calling the metaclass bases
multiple bases have instance lay-out conflict
If you run into this problem, You could just remove __slots__
from the parents, or if you have control of the parents, give them empty slots, or refactor to abstractions:
from abc import ABC
class AbstractA(ABC):
__slots__ = ()
class BaseA(AbstractA):
__slots__ = ('a',)
class AbstractB(ABC):
__slots__ = ()
class BaseB(AbstractB):
__slots__ = ('b',)
class Child(AbstractA, AbstractB):
__slots__ = ('a', 'b')
c = Child() # no problem!
Add '__dict__'
to __slots__
to get dynamic assignment:
class Foo(object):
__slots__ = 'bar', 'baz', '__dict__'
and now:
>>> foo = Foo()
>>> foo.boink = 'boink'
So with '__dict__'
in slots we lose some of the size benefits with the upside of having dynamic assignment and still having slots for the names we do expect.
When you inherit from an object that isn't slotted, you get the same sort of semantics when you use __slots__
- names that are in __slots__
point to slotted values, while any other values are put in the instance's __dict__
.
Avoiding __slots__
because you want to be able to add attributes on the fly is actually not a good reason - just add "__dict__"
to your __slots__
if this is required.
You can similarly add __weakref__
to __slots__
explicitly if you need that feature.
Set to empty tuple when subclassing a namedtuple:
The namedtuple builtin make immutable instances that are very lightweight (essentially, the size of tuples) but to get the benefits, you need to do it yourself if you subclass them:
from collections import namedtuple
class MyNT(namedtuple('MyNT', 'bar baz')):
"""MyNT is an immutable and lightweight object"""
__slots__ = ()
usage:
>>> nt = MyNT('bar', 'baz')
>>> nt.bar
'bar'
>>> nt.baz
'baz'
And trying to assign an unexpected attribute raises an AttributeError
because we have prevented the creation of __dict__
:
>>> nt.quux = 'quux'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'MyNT' object has no attribute 'quux'
You can allow __dict__
creation by leaving off __slots__ = ()
, but you can't use non-empty __slots__
with subtypes of tuple.
Biggest Caveat: Multiple inheritance
Even when non-empty slots are the same for multiple parents, they cannot be used together:
class Foo(object):
__slots__ = 'foo', 'bar'
class Bar(object):
__slots__ = 'foo', 'bar' # alas, would work if empty, i.e. ()
>>> class Baz(Foo, Bar): pass
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: Error when calling the metaclass bases
multiple bases have instance lay-out conflict
Using an empty __slots__
in the parent seems to provide the most flexibility, allowing the child to choose to prevent or allow (by adding '__dict__'
to get dynamic assignment, see section above) the creation of a __dict__
:
class Foo(object): __slots__ = ()
class Bar(object): __slots__ = ()
class Baz(Foo, Bar): __slots__ = ('foo', 'bar')
b = Baz()
b.foo, b.bar = 'foo', 'bar'
You don't have to have slots - so if you add them, and remove them later, it shouldn't cause any problems.
Going out on a limb here: If you're composing mixins or using abstract base classes, which aren't intended to be instantiated, an empty __slots__
in those parents seems to be the best way to go in terms of flexibility for subclassers.
To demonstrate, first, let's create a class with code we'd like to use under multiple inheritance
class AbstractBase:
__slots__ = ()
def __init__(self, a, b):
self.a = a
self.b = b
def __repr__(self):
return f'{type(self).__name__}({repr(self.a)}, {repr(self.b)})'
We could use the above directly by inheriting and declaring the expected slots:
class Foo(AbstractBase):
__slots__ = 'a', 'b'
But we don't care about that, that's trivial single inheritance, we need another class we might also inherit from, maybe with a noisy attribute:
class AbstractBaseC:
__slots__ = ()
@property
def c(self):
print('getting c!')
return self._c
@c.setter
def c(self, arg):
print('setting c!')
self._c = arg
Now if both bases had nonempty slots, we couldn't do the below. (In fact, if we wanted, we could have given AbstractBase
nonempty slots a and b, and left them out of the below declaration - leaving them in would be wrong):
class Concretion(AbstractBase, AbstractBaseC):
__slots__ = 'a b _c'.split()
And now we have functionality from both via multiple inheritance, and can still deny __dict__
and __weakref__
instantiation:
>>> c = Concretion('a', 'b')
>>> c.c = c
setting c!
>>> c.c
getting c!
Concretion('a', 'b')
>>> c.d = 'd'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'Concretion' object has no attribute 'd'
Other cases to avoid slots:
- Avoid them when you want to perform
__class__
assignment with another class that doesn't have them (and you can't add them) unless the slot layouts are identical. (I am very interested in learning who is doing this and why.) - Avoid them if you want to subclass variable length builtins like long, tuple, or str, and you want to add attributes to them.
- Avoid them if you insist on providing default values via class attributes for instance variables.
You may be able to tease out further caveats from the rest of the __slots__
documentation (the 3.7 dev docs are the most current), which I have made significant recent contributions to.
Critiques of other answers
The current top answers cite outdated information and are quite hand-wavy and miss the mark in some important ways.
Do not "only use __slots__
when instantiating lots of objects"
I quote:
"You would want to use
__slots__
if you are going to instantiate a lot (hundreds, thousands) of objects of the same class."
Abstract Base Classes, for example, from the collections
module, are not instantiated, yet __slots__
are declared for them.
Why?
If a user wishes to deny __dict__
or __weakref__
creation, those things must not be available in the parent classes.
__slots__
contributes to reusability when creating interfaces or mixins.
It is true that many Python users aren't writing for reusability, but when you are, having the option to deny unnecessary space usage is valuable.
__slots__
doesn't break pickling
When pickling a slotted object, you may find it complains with a misleading TypeError
:
>>> pickle.loads(pickle.dumps(f))
TypeError: a class that defines __slots__ without defining __getstate__ cannot be pickled
This is actually incorrect. This message comes from the oldest protocol, which is the default. You can select the latest protocol with the -1
argument. In Python 2.7 this would be 2
(which was introduced in 2.3), and in 3.6 it is 4
.
>>> pickle.loads(pickle.dumps(f, -1))
<__main__.Foo object at 0x1129C770>
in Python 2.7:
>>> pickle.loads(pickle.dumps(f, 2))
<__main__.Foo object at 0x1129C770>
in Python 3.6
>>> pickle.loads(pickle.dumps(f, 4))
<__main__.Foo object at 0x1129C770>
So I would keep this in mind, as it is a solved problem.
Critique of the (until Oct 2, 2016) accepted answer
The first paragraph is half short explanation, half predictive. Here's the only part that actually answers the question
The proper use of
__slots__
is to save space in objects. Instead of having a dynamic dict that allows adding attributes to objects at anytime, there is a static structure which does not allow additions after creation. This saves the overhead of one dict for every object that uses slots
The second half is wishful thinking, and off the mark:
While this is sometimes a useful optimization, it would be completely unnecessary if the Python interpreter was dynamic enough so that it would only require the dict when there actually were additions to the object.
Python actually does something similar to this, only creating the __dict__
when it is accessed, but creating lots of objects with no data is fairly ridiculous.
The second paragraph oversimplifies and misses actual reasons to avoid __slots__
. The below is not a real reason to avoid slots (for actual reasons, see the rest of my answer above.):
They change the behavior of the objects that have slots in a way that can be abused by control freaks and static typing weenies.
It then goes on to discuss other ways of accomplishing that perverse goal with Python, not discussing anything to do with __slots__
.
The third paragraph is more wishful thinking. Together it is mostly off-the-mark content that the answerer didn't even author and contributes to ammunition for critics of the site.
Memory usage evidence
Create some normal objects and slotted objects:
>>> class Foo(object): pass
>>> class Bar(object): __slots__ = ()
Instantiate a million of them:
>>> foos = [Foo() for f in xrange(1000000)]
>>> bars = [Bar() for b in xrange(1000000)]
Inspect with guppy.hpy().heap()
:
>>> guppy.hpy().heap()
Partition of a set of 2028259 objects. Total size = 99763360 bytes.
Index Count % Size % Cumulative % Kind (class / dict of class)
0 1000000 49 64000000 64 64000000 64 __main__.Foo
1 169 0 16281480 16 80281480 80 list
2 1000000 49 16000000 16 96281480 97 __main__.Bar
3 12284 1 987472 1 97268952 97 str
...
Access the regular objects and their __dict__
and inspect again:
>>> for f in foos:
... f.__dict__
>>> guppy.hpy().heap()
Partition of a set of 3028258 objects. Total size = 379763480 bytes.
Index Count % Size % Cumulative % Kind (class / dict of class)
0 1000000 33 280000000 74 280000000 74 dict of __main__.Foo
1 1000000 33 64000000 17 344000000 91 __main__.Foo
2 169 0 16281480 4 360281480 95 list
3 1000000 33 16000000 4 376281480 99 __main__.Bar
4 12284 0 987472 0 377268952 99 str
...
This is consistent with the history of Python, from Unifying types and classes in Python 2.2
If you subclass a built-in type, extra space is automatically added to the instances to accomodate
__dict__
and__weakrefs__
. (The__dict__
is not initialized until you use it though, so you shouldn't worry about the space occupied by an empty dictionary for each instance you create.) If you don't need this extra space, you can add the phrase "__slots__ = []
" to your class.

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164This answer should be part of the official Python documentation about `__slots__`. Seriously! Thank you! – NightElfik May 10 '18 at 23:53
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60@NightElfik believe it or not, I contributed to the Python docs on `__slots__` about a year back: https://github.com/python/cpython/pull/1819/files – Russia Must Remove Putin Jun 28 '18 at 17:15
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6Fantastically detailed answer. I have one question: should one being using slots as default _unless_ the usage hits one of the caveats, or are slots something to consider if you know you are going to struggle for speed/memory? To put it another way, should you encourage a newbie to learn about them and use them from the start? – freethebees Jul 11 '19 at 09:59
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Great answer, thanks! One sidenote: in the current version of python (3.6 or 3.7) it looks as if subclassing a namedtuple is no longer necessary. It doesn't allow undeclared attribute assignment by default. – Antony Hatchkins Jul 11 '19 at 17:33
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Could you please rephrase _"Factor out all but one or all parents' abstraction which their concrete class respectively and your new concrete class collectively will inherit from - giving the abstraction(s) empty slots (just like abstract base classes in the standard library)._ It's difficult to parse. Do you mean "Across all parent abstract classes inherited by your concrete class, factor out _all_ or _all but one_ of the `__slots__` declarations."? The relation between "their concrete class" and "your new concrete class" is not stated -- simple inherit., or diamond again? – init_js Jul 17 '19 at 19:10
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Which answer is "the (until Oct 2, 2016) accepted answer"? The history of acceptance isn't easily accessible to normal users; perhaps that heading could be re-worded (and preferably incorporate a link)? Thanks. – Toby Speight Oct 24 '19 at 12:06
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1I'm trying to critique the material while leaving the individuals involved out of it. If you look for the words I quote, it's not hard to find... – Russia Must Remove Putin Mar 06 '20 at 13:53
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Note that Python 3 classes inherit from `object` implicitly. See https://stackoverflow.com/questions/15374857/should-all-python-classes-extend-object – ubiquibacon May 21 '20 at 14:00
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@AaronHall, quick question: If I define some dunder methods like `__str__` and `__hash__`, do I need to list them in `__slots__` as well? – pepoluan Sep 28 '20 at 04:47
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6@pepoluan no you do not need to list method names in `__slots__` - but thanks for the question! A slot declaration creates a descriptor object in the namespace (the `__dict__`) like a method definition does. – Russia Must Remove Putin Sep 28 '20 at 13:43
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My own limited testing suggests that the saving on memory usage of instances is not as large as stated in the answer. Is the suggestion in [this page](https://www.python-course.eu/python3_slots.php), that improvement in python class dictionaries have eroded the advantage of slots in this respect, true? – M Juckes Oct 19 '20 at 15:31
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I just get to know `__slots__`, so @AaronHall thank you for this detailed answer. Is `__slots__` only to handle an internal dictionary in the class? What is the difference in terms of performance between using `__slots__` and creating dynamic attributes using `__setattr__` or `setattr()`? – Pedro Pablo Severin Honorato Feb 25 '21 at 16:23
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@PedroPabloSeverinHonorato `__slots__` doesn't handle an internal dictionary. As some like to put it, it lets you avoid using a dictionary. Regarding performance versus `__slots__` and `__setattr__` or `setattr`, I do the analysis for dotted lookups, and conclude "The slotted access is almost 30% faster in Python 3.5 on Ubuntu." - can you clarify your question(s)? – Russia Must Remove Putin Feb 26 '21 at 17:22
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2This answer deserves a standing ovation. – Underoos Jun 20 '21 at 12:38
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1In Python 3 you don't need to explicitly inherit from `object` in order to use slots. Pls. fix. – greatvovan Jun 30 '21 at 17:04
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4@greatvovan thanks for bringing that to my attention, I have updated the text in two locations to make that point explicit. Let me know if that's good or if you think I've missed any other spots or any other issues as well. Much appreciated. – Russia Must Remove Putin Jun 30 '21 at 18:08
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@AaronHall I profiled the effects of slots for attribute access optimisations, and in one of my tests I included the case of a class using `__slots__` with a `__dict__` to see if we can get the best of both worlds (faster attribute lookup for some attributes while keeping dynamic assignments for the rest of the object attributes). Well, turns out adding `__dict__` makes it as slow as not using `__slots__` at all... I did not test for memory usage by I guess if you include a `__dict__` that also get thrown out the window. So, I don't see the point of `__dict__` in `__slots__`. Using python 3.8 – Axel Voitier Sep 29 '21 at 15:19
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test for memory usage also, then write it up, and if you still think you have something interesting, post it to the python dev mailing list. – Russia Must Remove Putin Sep 29 '21 at 15:26
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Are attributes set during instance construction (i.e. in `__init__`) automatically slotted since every instance would have said attributes and it seems like a reasonable optimization? Or do they have to be slotted manually (using `__slots__ = ...`? – joseville Oct 19 '21 at 17:41
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see the example `class Foo(AbstractBase)` above - all slots must be declared except for `__dict__` and `__weakref__` (which get created implicitly if you don't declare slots.) – Russia Must Remove Putin Oct 19 '21 at 18:35
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2Using Python 3.10.2 (through IPython 8.0.1) I actually get no performance increase from using `__slots__`: `%timeit get_set_delete_fn(not_slotted) -> 168 ns ± 0.367 ns per loop (mean ± std. dev. of 7 runs, 10,000,000 loops each)`, `%timeit get_set_delete_fn(slotted) -> 171 ns ± 0.106 ns per loop (mean ± std. dev. of 7 runs, 10,000,000 loops each)`. The memory advantage of course remains. – user8408080 Feb 17 '22 at 09:03
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I can confirm that I don't see a significant performance beneift in Pyhton 3.8 either. – Bashir Abdelwahed Nov 22 '22 at 09:15
Quoting Jacob Hallen:
The proper use of
__slots__
is to save space in objects. Instead of having a dynamic dict that allows adding attributes to objects at anytime, there is a static structure which does not allow additions after creation. [This use of__slots__
eliminates the overhead of one dict for every object.] While this is sometimes a useful optimization, it would be completely unnecessary if the Python interpreter was dynamic enough so that it would only require the dict when there actually were additions to the object.Unfortunately there is a side effect to slots. They change the behavior of the objects that have slots in a way that can be abused by control freaks and static typing weenies. This is bad, because the control freaks should be abusing the metaclasses and the static typing weenies should be abusing decorators, since in Python, there should be only one obvious way of doing something.
Making CPython smart enough to handle saving space without
__slots__
is a major undertaking, which is probably why it is not on the list of changes for P3k (yet).

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95I'd like to see some elaboration on the "static typing"/decorator point, sans pejoratives. Quoting absent third parties is unhelpful. `__slots__` doesn't address the same issues as static typing. For example, in C++, it is not the declaration of a member variable is being restricted, it is the assignment of an unintended type (and compiler enforced) to that variable. I'm not condoning the use of `__slots__`, just interested in the conversation. Thanks! – hiwaylon Nov 28 '11 at 17:54
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"in Python, there should be only one obvious way of doing something" So what is the one obvious way of preventing global variables (uppercase variables being named consts) using metaclasses? – dbow Feb 15 '22 at 08:21
You would want to use __slots__
if you are going to instantiate a lot (hundreds, thousands) of objects of the same class. __slots__
only exists as a memory optimization tool.
It's highly discouraged to use __slots__
for constraining attribute creation.
Pickling objects with __slots__
won't work with the default (oldest) pickle protocol; it's necessary to specify a later version.
Some other introspection features of python may also be adversely affected.

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16I demonstrate pickling a slotted object in my answer and also address the first part of your answer. – Russia Must Remove Putin May 02 '16 at 15:08
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7I see your point, but slots offer faster attribute access as well (as others have stated). In that case you don't need *"to instantiate a lot (hundreds, thousands) of objects of the same class"* in order to gain performance. What you need instead are _a lot_ of accesses to the same (slotted) attribute of the same instance. (Please correct me if I'm wrong.) – Rotareti Jul 19 '17 at 04:28
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7why is it "highly discouraged"? I was recently looking for a way to constrain dynamic attribute creation. I found something but there was no mention of slots. Now I read about slots and it seems like exactly what i was looking for before. Whats wrong about using slots to prevent adding attributes at runtime? – 463035818_is_not_an_ai Jun 17 '20 at 09:08
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1@idclev463035818 I don't think there is any wrong thing about that. – Ekrem Dinçel Oct 30 '20 at 19:22
Each python object has a __dict__
atttribute which is a dictionary containing all other attributes. e.g. when you type self.attr
python is actually doing self.__dict__['attr']
. As you can imagine using a dictionary to store attribute takes some extra space & time for accessing it.
However, when you use __slots__
, any object created for that class won't have a __dict__
attribute. Instead, all attribute access is done directly via pointers.
So if want a C style structure rather than a full fledged class you can use __slots__
for compacting size of the objects & reducing attribute access time. A good example is a Point class containing attributes x & y. If you are going to have a lot of points, you can try using __slots__
in order to conserve some memory.
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11No, an instance of a class with `__slots__` defined is *not* like a C-style structure. There is a class-level dictionary mapping attribute names to indexes, otherwise the following would not be possible: `class A(object): __slots__= "value",\n\na=A(); setattr(a, 'value', 1)` I really think this answer should be clarified (I can do that if you want). Also, I'm not certain that `instance.__hidden_attributes[instance.__class__[attrname]]` is faster than `instance.__dict__[attrname]`. – tzot Oct 15 '11 at 13:56
In addition to the other answers, here is an example of using __slots__
:
>>> class Test(object): #Must be new-style class!
... __slots__ = ['x', 'y']
...
>>> pt = Test()
>>> dir(pt)
['__class__', '__delattr__', '__doc__', '__getattribute__', '__hash__',
'__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__',
'__repr__', '__setattr__', '__slots__', '__str__', 'x', 'y']
>>> pt.x
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: x
>>> pt.x = 1
>>> pt.x
1
>>> pt.z = 2
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'Test' object has no attribute 'z'
>>> pt.__dict__
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'Test' object has no attribute '__dict__'
>>> pt.__slots__
['x', 'y']
So, to implement __slots__
, it only takes an extra line (and making your class a new-style class if it isn't already). This way you can reduce the memory footprint of those classes 5-fold, at the expense of having to write custom pickle code, if and when that becomes necessary.

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Slots are very useful for library calls to eliminate the "named method dispatch" when making function calls. This is mentioned in the SWIG documentation. For high performance libraries that want to reduce function overhead for commonly called functions using slots is much faster.
Now this may not be directly related to the OPs question. It is related more to building extensions than it does to using the __slots__
syntax on an object. But it does help complete the picture for the usage of slots and some of the reasoning behind them.

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A very simple example of __slot__
attribute.
Problem: Without __slots__
If I don't have __slot__
attribute in my class, I can add new attributes to my objects.
class Test:
pass
obj1=Test()
obj2=Test()
print(obj1.__dict__) #--> {}
obj1.x=12
print(obj1.__dict__) # --> {'x': 12}
obj1.y=20
print(obj1.__dict__) # --> {'x': 12, 'y': 20}
obj2.x=99
print(obj2.__dict__) # --> {'x': 99}
If you look at example above, you can see that obj1 and obj2 have their own x and y attributes and python has also created a dict
attribute for each object (obj1 and obj2).
Suppose if my class Test has thousands of such objects? Creating an additional attribute dict
for each object will cause lot of overhead (memory, computing power etc.) in my code.
Solution: With __slots__
Now in the following example my class Test contains __slots__
attribute. Now I can't add new attributes to my objects (except attribute x
) and python doesn't create a dict
attribute anymore. This eliminates overhead for each object, which can become significant if you have many objects.
class Test:
__slots__=("x")
obj1=Test()
obj2=Test()
obj1.x=12
print(obj1.x) # --> 12
obj2.x=99
print(obj2.x) # --> 99
obj1.y=28
print(obj1.y) # --> AttributeError: 'Test' object has no attribute 'y'

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Hi, you can use `class Test: __slots__= ("x", "__dict__")` and it will work. – Jan May 13 '22 at 09:34
An attribute of a class instance has 3 properties: the instance, the name of the attribute, and the value of the attribute.
In regular attribute access, the instance acts as a dictionary and the name of the attribute acts as the key in that dictionary looking up value.
instance(attribute) --> value
In __slots__ access, the name of the attribute acts as the dictionary and the instance acts as the key in the dictionary looking up value.
attribute(instance) --> value
In flyweight pattern, the name of the attribute acts as the dictionary and the value acts as the key in that dictionary looking up the instance.
attribute(value) --> instance

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1This is a good share, and won't fit well in a comment on one of the answers that also suggest flyweights, but it is not a complete answer to the question itself. In particular (in just context of the question): why Flyweight, and "what are the cases one should avoid ..." `__slots__`? – Merlyn Morgan-Graham Jul 25 '14 at 06:22
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@Merlyn Morgan-Graham, it serves as a hint on which to pick: regular access, \_\_slots\_\_, or flyweight. – Dmitry Rubanovich Jul 26 '14 at 23:04
Beginning in Python 3.9, a dict
may be used to add descriptions to attributes via __slots__
. None
may be used for attributes without descriptions, and private variables will not appear even if a description is given.
class Person:
__slots__ = {
"birthday":
"A datetime.date object representing the person's birthday.",
"name":
"The first and last name.",
"public_variable":
None,
"_private_variable":
"Description",
}
help(Person)
"""
Help on class Person in module __main__:
class Person(builtins.object)
| Data descriptors defined here:
|
| birthday
| A datetime.date object representing the person's birthday.
|
| name
| The first and last name.
|
| public_variable
"""

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Was just looking if someone [mentioned it](https://docs.python.org/3/reference/datamodel.html#slots) *If a dictionary is used to assign __slots__, the dictionary keys will be used as the slot names. The values of the dictionary can be used to provide per-attribute docstrings that will be recognised by inspect.getdoc() and displayed in the output of help().* – Thingamabobs Jul 03 '22 at 05:04
In addition to the other answers, __slots__
also adds a little typographical security by limiting attributes to a predefined list. This has long been a problem with JavaScript which also allows you to add new attributes to an existing object, whether you meant to or not.
Here is a normal unslotted object which does nothing, but allows you to add attributes:
class Unslotted:
pass
test = Unslotted()
test.name = 'Fred'
test.Name = 'Wilma'
Since Python is case sensitive, the two attributes, spelled the same but with different case, are different. If you suspect that one of those is a typing error, then bad luck.
Using slots, you can limit this:
class Slotted:
__slots__ = ('name')
pass
test = Slotted()
test.name = 'Fred' # OK
test.Name = 'Wilma' # Error
This time, the second attribute (Name
) is disallowed because it’s not in the __slots__
collection.
I would suggest that it’s probably better to use __slots__
where possible to keep more control over the object.

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Another somewhat obscure use of __slots__
is to add attributes to an object proxy from the ProxyTypes package, formerly part of the PEAK project. Its ObjectWrapper
allows you to proxy another object, but intercept all interactions with the proxied object. It is not very commonly used (and no Python 3 support), but we have used it to implement a thread-safe blocking wrapper around an async implementation based on tornado that bounces all access to the proxied object through the ioloop, using thread-safe concurrent.Future
objects to synchronise and return results.
By default any attribute access to the proxy object will give you the result from the proxied object. If you need to add an attribute on the proxy object, __slots__
can be used.
from peak.util.proxies import ObjectWrapper
class Original(object):
def __init__(self):
self.name = 'The Original'
class ProxyOriginal(ObjectWrapper):
__slots__ = ['proxy_name']
def __init__(self, subject, proxy_name):
# proxy_info attributed added directly to the
# Original instance, not the ProxyOriginal instance
self.proxy_info = 'You are proxied by {}'.format(proxy_name)
# proxy_name added to ProxyOriginal instance, since it is
# defined in __slots__
self.proxy_name = proxy_name
super(ProxyOriginal, self).__init__(subject)
if __name__ == "__main__":
original = Original()
proxy = ProxyOriginal(original, 'Proxy Overlord')
# Both statements print "The Original"
print "original.name: ", original.name
print "proxy.name: ", proxy.name
# Both statements below print
# "You are proxied by Proxy Overlord", since the ProxyOriginal
# __init__ sets it to the original object
print "original.proxy_info: ", original.proxy_info
print "proxy.proxy_info: ", proxy.proxy_info
# prints "Proxy Overlord"
print "proxy.proxy_name: ", proxy.proxy_name
# Raises AttributeError since proxy_name is only set on
# the proxy object
print "original.proxy_name: ", proxy.proxy_name

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In addition to the myriad advantages described in other answers herein – compact instances for the memory-conscious, less error-prone than the more mutable __dict__
-bearing instances, et cetera – I find that using __slots__
offers more legible class declarations, as the instance variables of the class are explicitly out in the open.
To contend with inheritance issues with __slots__
declarations I use this metaclass:
import abc
class Slotted(abc.ABCMeta):
""" A metaclass that ensures its classes, and all subclasses,
will be slotted types.
"""
def __new__(metacls, name, bases, attributes, **kwargs):
""" Override for `abc.ABCMeta.__new__(…)` setting up a
derived slotted class.
"""
if '__slots__' not in attributes:
attributes['__slots__'] = tuple()
return super(Slotted, metacls).__new__(metacls, name, # type: ignore
bases,
attributes,
**kwargs)
… which, if declared as the metaclass of the base class in an inheritance tower, ensures that everything that derives from that base class will properly inherit __slots__
attributes, even if an intermediate class fails to declare any. Like so:
# note no __slots__ declaration necessary with the metaclass:
class Base(metaclass=Slotted):
pass
# class is properly slotted, no __dict__:
class Derived(Base):
__slots__ = 'slot', 'another_slot'
# class is also properly slotted:
class FurtherDerived(Derived):
pass

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The original question was about general use cases not only about memory. So it should be mentioned here that you also get better performance when instantiating large amounts of objects - interesting e.g. when parsing large documents into objects or from a database.
Here is a comparison of creating object trees with a million entries, using slots and without slots. As a reference also the performance when using plain dicts for the trees (Py2.7.10 on OSX):
********** RUN 1 **********
1.96036410332 <class 'css_tree_select.element.Element'>
3.02922606468 <class 'css_tree_select.element.ElementNoSlots'>
2.90828204155 dict
********** RUN 2 **********
1.77050495148 <class 'css_tree_select.element.Element'>
3.10655999184 <class 'css_tree_select.element.ElementNoSlots'>
2.84120798111 dict
********** RUN 3 **********
1.84069895744 <class 'css_tree_select.element.Element'>
3.21540498734 <class 'css_tree_select.element.ElementNoSlots'>
2.59615707397 dict
********** RUN 4 **********
1.75041103363 <class 'css_tree_select.element.Element'>
3.17366290092 <class 'css_tree_select.element.ElementNoSlots'>
2.70941114426 dict
Test classes (ident, appart from slots):
class Element(object):
__slots__ = ['_typ', 'id', 'parent', 'childs']
def __init__(self, typ, id, parent=None):
self._typ = typ
self.id = id
self.childs = []
if parent:
self.parent = parent
parent.childs.append(self)
class ElementNoSlots(object): (same, w/o slots)
testcode, verbose mode:
na, nb, nc = 100, 100, 100
for i in (1, 2, 3, 4):
print '*' * 10, 'RUN', i, '*' * 10
# tree with slot and no slot:
for cls in Element, ElementNoSlots:
t1 = time.time()
root = cls('root', 'root')
for i in xrange(na):
ela = cls(typ='a', id=i, parent=root)
for j in xrange(nb):
elb = cls(typ='b', id=(i, j), parent=ela)
for k in xrange(nc):
elc = cls(typ='c', id=(i, j, k), parent=elb)
to = time.time() - t1
print to, cls
del root
# ref: tree with dicts only:
t1 = time.time()
droot = {'childs': []}
for i in xrange(na):
ela = {'typ': 'a', id: i, 'childs': []}
droot['childs'].append(ela)
for j in xrange(nb):
elb = {'typ': 'b', id: (i, j), 'childs': []}
ela['childs'].append(elb)
for k in xrange(nc):
elc = {'typ': 'c', id: (i, j, k), 'childs': []}
elb['childs'].append(elc)
td = time.time() - t1
print td, 'dict'
del droot

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You have — essentially — no use for __slots__
.
For the time when you think you might need __slots__
, you actually want to use Lightweight or Flyweight design patterns. These are cases when you no longer want to use purely Python objects. Instead, you want a Python object-like wrapper around an array, struct, or numpy array.
class Flyweight(object):
def get(self, theData, index):
return theData[index]
def set(self, theData, index, value):
theData[index]= value
The class-like wrapper has no attributes — it just provides methods that act on the underlying data. The methods can be reduced to class methods. Indeed, it could be reduced to just functions operating on the underlying array of data.

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3@oefe: I certainly don't get your question. I can quote my answer, if it helps "when you think you might need __slots__, you actually want to use ... Flyweight design pattern". That's what Flyweight has to do with __slots__. Do you have a more specific question? – S.Lott Jan 24 '09 at 23:41
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22@oefe: Flyweight and `__slots__` are both optimization techniques to save memory. `__slots__` shows benefits when you have many many objects as well as Flyweight design pattern. The both solve the same problem. – jfs Nov 29 '09 at 20:51
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7Is there a available comparison between using slots and using Flyweight regarding memory consumption and speed? – kontulai Apr 23 '13 at 04:11
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... are both optimisation techniques to save memory ... and `__slots__` can be implemented as an afterthought. – Evgeni Sergeev Jun 03 '15 at 07:30
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9Although Flyweight is certainly useful in some contexts, believe it or not, the answer to "how can I reduce memory usage in Python when I create a zillion objects" is not always "don't use Python for your zillion objects." Sometimes `__slots__` really is the answer, and as Evgeni points out, it can be added as a simple afterthought (e.g. you can focus on correctness first, and then add performance). – Patrick Maupin Jul 25 '15 at 16:19
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You can save a lot of memory using Flyweight when you aim to share attributes with identic values between instances, but this may not be the case with `__slots__`. – Nuno André Oct 07 '15 at 15:44
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S.Lott, would you reconsider or rewrite any of this answer? – Russia Must Remove Putin Jan 23 '16 at 01:15