Redirect to same page after POST method using class based views

Question

I'm making a Django app that keeps track of tv show episodes. This is for a page on a certain Show instance. When a user clicks to add/subtract a season, I want the page to redirect them to the same detail view, right now I have it on the index that shows the list of all Show instances.

show-detail.html

<form action="{% url 'show:addseason' show=show %}" method="post">
    {% csrf_token %}

    <button class="btn btn-default" type="submit">+</button>
</form> 

<form action="{% url 'show:subtractseason' show=show %}" method="post">
    {% csrf_token %}

    <button class="btn btn-default" type="submit">-</button>
</form>

views.py

class ShowDetail(DetailView):
    model = Show
    slug_field = "title"
    slug_url_kwarg = "show"
    template_name = 'show/show-detail.html'

class AddSeason(UpdateView):
    model = Show
    slug_field = 'title'
    slug_url_kwarg = 'show'
    fields = []

    def form_valid(self, form):
        instance = form.save(commit=False)
        instance.season += 1
        instance.save()

        return redirect('show:index')

class SubtractSeason(UpdateView):
    model = Show
    slug_field = 'title'
    slug_url_kwarg = 'show'
    fields = []

    def form_valid(self, form):
        instance = form.save(commit=False)
        if (instance.season >= 0):
            instance.season -= 1
        else:
            instance.season = 0

        instance.save()

        return redirect('show:index')

urls.py

url(r'^$', views.IndexView.as_view(), name='index'),

url(r'^about/$', views.AboutView.as_view(), name='about'),

# form to add show
url(r'^add/$', views.ShowCreate.as_view(), name='show-add'),

# edit show
#url(r'^(?P<show>[\w ]+)/edit/$', views.ShowUpdate.as_view(), name='show-update'),

# delete show
url(r'^(?P<show>[\w ]+)/delete/$', views.ShowDelete.as_view(), name='show-delete'),

# signup
url(r'^register/$', views.UserFormView.as_view(), name='register'),

# login
url(r'^login/$', views.LoginView.as_view(), name='login'),

# logout
url(r'^logout/$', views.LogoutView.as_view(), name='logout'),

url(r'^error/$', views.ErrorView.as_view(), name='error'),

url(r'^(?P<show>[\w ]+)/$', views.ShowDetail.as_view(), name='show-detail'),

url(r'^(?P<show>[\w ]+)/addseason/$', views.AddSeason.as_view(), name='addseason'),

url(r'^(?P<show>[\w ]+)/subtractseason/$', views.SubtractSeason.as_view(), name='subtractseason'),

url(r'^(?P<show>[\w ]+)/addepisode/$', views.AddEpisode.as_view(), name='addepisode'),

url(r'^(?P<show>[\w ]+)/subtractepisode/$', views.SubtractEpisode.as_view(), name='subtractepisode'),

I get an error when I try

return redirect('show:detail')

This is the error

NoReverseMatch at /Daredevil/addseason/
Reverse for 'detail' with arguments '()' and keyword arguments '{}' not found. 0 pattern(s) tried: []

score 64 · Answer 1 · answered Nov 23 '17 at 14:56

64

For CBV:

from django.http import HttpResponseRedirect


return HttpResponseRedirect(self.request.path_info)

For function view:

from django.http import HttpResponseRedirect


return HttpResponseRedirect(request.path_info)

answered Nov 23 '17 at 14:56

Dmitriy Sintsov

3,821
32
20

1

Please, what do you mean by " path_info "? Is it the path name? – ThunderBird Jun 06 '18 at 11:01
3

`path_info` is a variable stored in request. It has the current url that you're on. It's just like reloading the page. – Vineeth Sai Jan 24 '19 at 08:42
1

wouldn't `path_info` store the CBV url (i.e /subtractseason in OP's example) whereas OP wants to go back to the URL that the user is 'on' (not the URL that was hyperlinked to the item that was clicked) – Anupam Aug 06 '20 at 15:00

FKLC · Answer 2 · 2020-07-23T13:01:31.823

24

You can achieve this by redirecting to HTTP_REFERER header and for fallback just add another path.

Example snippet:

return redirect(request.META.get('HTTP_REFERER', 'redirect_if_referer_not_found'))

edited Jul 23 '20 at 13:01

answered Jun 04 '18 at 19:18

FKLC

1,672
4
14
21

Is there a way we may send the `HTTP_REFERER` bit from the view to the template say, picking its value by someting like `redirect_frm = request.META.get('HTTP_REFERER')` and send `redirect_frm` to the template? – carla Nov 30 '22 at 18:25

score 20 · Answer 3 · answered Aug 05 '20 at 14:39

20

from django.http import HttpResponseRedirect

def someview(request):

   ...
   return HttpResponseRedirect(request.META.get('HTTP_REFERER'))

taken from: https://stackoverflow.com/a/12758859/14020019

answered Aug 05 '20 at 14:39

Kaushik Kakdey

599
4
10

Please do not repost an existing answer, when you'll have enough reputation you'll be able to flag question as duplicate. – β.εηοιτ.βε Aug 05 '20 at 17:45
1

This answer worked great for me - simple and direct. OP wants to go back to the URL that the user was 'on' – Anupam Aug 06 '20 at 15:02

David Lam · Answer 4 · 2017-12-05T02:58:53.307

18

to redirect to the same page (e.g. an http GET) after a POST, I like...

return HttpResponseRedirect("")   # from django.http import HttpResponseRedirect

it also avoids hardcoding the show:detail route name, and is a lil' clearer intention wise (for me at least!)

edited Dec 05 '17 at 02:58

answered Sep 18 '16 at 18:36

David Lam

4,689
3
23
34

What if I want to send some data too, such as a dictionary? How to achieve this? – DHRUV KAUSHAL Mar 19 '20 at 11:41
8

It opens to a **blank** page!! – Love Putin Not War Apr 26 '20 at 14:24
I'm getting a blank page as well – Brendan Metcalfe Jul 10 '20 at 17:36
1

Looks like this no longer works. The answer was originally given in 2016. – kbuilds Sep 21 '20 at 16:33
1

return HttpResponseRedirect("#") seems to be a replacement in Django ~3.2. I put it in as a placeholder in my code, and behold, it worked! – Tim Nyborg Aug 26 '21 at 13:26
I'm on Django 3.2.10 and it works in chrome – John R Perry Feb 07 '22 at 10:05

James Hiew · Answer 5 · 2016-09-18T18:35:25.340

3

I am guessing you need to provide a kwarg to identify the show when you redirect, although I can't see the code for your DetailView I would assume the kwarg is called either pk or possibly show going from the convention you've used in AddSeason and SubtractSeason. Try:

redirect('show:detail', kwargs={'show': instance.pk})

EDIT: the name of the detail url is 'show-detail', so the scoped viewname would be 'show:show-detail' (if it is in the show namespace like the other urls). I still think it would need a kwarg though, try:

redirect('show:show-detail', kwargs={'show': instance.pk})

edited Sep 18 '16 at 18:35

answered Sep 18 '16 at 17:03

James Hiew

6,040
5
27
41

Hey, I tried that it didn't work. I included my show-detail view. Please help me out if you can. – user298519 Sep 18 '16 at 17:21
What's the error you get, is it the same? Can you post your urlpatterns? – James Hiew Sep 18 '16 at 18:01
Same error, and edited my post to show my urlpatterns! – user298519 Sep 18 '16 at 18:27
Edited the answer, see above, you can try with or without the `kwargs` kwarg – James Hiew Sep 18 '16 at 18:35
Got this error Reverse for 'show-detail' with arguments '()' and keyword arguments '{}' not found. 1 pattern(s) tried: ['(?P[\\w ]+)/$'] – user298519 Sep 18 '16 at 20:02
It is finding the correct urlpattern now. Did you try with kwargs? If that doesn't work, try `redirect('show:show-detail', args=(instance.pk, ))` – James Hiew Sep 18 '16 at 20:08
Yes, I did try with kwargs. Now I tried that solution, and it's still not working. Thanks for helping though. – user298519 Sep 18 '16 at 20:27

Redirect to same page after POST method using class based views

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