I can't find an answer in the standard documentation. Does the C++ language standard require sizeof(bool)
to always be 1 (for 1 byte), or is this size implementation-defined?
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If your code depends on `bool` to be 1 byte, you can check it at compile-time: `static_assert(sizeof(bool) == 1, "OMG bool is big here");`. – nielsen Jun 29 '23 at 06:49
5 Answers
sizeof(bool)
is implementation defined, and the standard puts notable emphasis on this fact.
§5.3.3/1, abridged:
sizeof(char)
,sizeof(signed char)
andsizeof(unsigned char)
are 1; the result ofsizeof
applied to any other fundamental type is implementation-defined. [Note: in particular,sizeof(bool)
andsizeof(wchar_t)
are implementation-defined.69)]
Footnote 69):
sizeof(bool)
is not required to be 1.

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is there a flag that i need to compile my program with, that my compiler will use only 1 byte for `bool`? – Eagle May 30 '11 at 09:29
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3@Eagle: That's up to your compiler, I'm not sure. It's probably best you left it up to your compiler. – GManNickG May 30 '11 at 10:02
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9note that std::vector
is optimized to a vector containing 1bit bools by the standard. – user3063349 Feb 10 '16 at 16:40 -
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@user3063349 is it standard really? [This](https://en.cppreference.com/w/cpp/container/vector_bool) mentions implementation-dependence – Szymon Brych Jan 07 '22 at 07:57
http://msdn.microsoft.com/en-us/library/tf4dy80a.aspx
"In Visual C++4.2, the Standard C++ header files contained a typedef that equated bool with int. In Visual C++ 5.0 and later, bool is implemented as a built-in type with a size of 1 byte. That means that for Visual C++ 4.2, a call of sizeof(bool) yields 4, while in Visual C++ 5.0 and later, the same call yields 1. This can cause memory corruption problems if you have defined structure members of type bool in Visual C++ 4.2 and are mixing object files (OBJ) and/or DLLs built with the 4.2 and 5.0 or later compilers."

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2You do realize that this is somewhat related to the question, but clearly not an answer, since 0xbadf00d asked about the standard, not some specific/arbitrarily selected compiler implementation, right? – Christopher Creutzig Dec 12 '13 at 22:27
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16
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19@kinokijuf It's not a counterexample. There are many things in Visual C++ that are not standard-compliant. – 0xbadf00d May 13 '16 at 15:43
It's implementation defined. Only sizeof(char)
is 1
by the standard.

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3pls note that the 1 in the standard can mean 4 byte. Than every type is a product of 4. So care that the standard ONLY defines char is the 1, but not defines the measurment. – user3063349 Feb 10 '16 at 16:39
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181 byte. The number of bits per byte is not defined by the standard (it needs to be at least 8 IIRC), but can be found in `CHAR_BIT`, defined in `climits`. – peoro Jul 02 '16 at 02:13
See 5.3.3 paragraph 1 :
[Note: in particular, sizeof(bool) and sizeof(wchar_t) are implementation-defined.69) ]

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Boolean occupy 8bit in a memomry. As per the recent development
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1Please cite your source for this. Current C++ draft does not indicate what you state. – Mat Jan 08 '23 at 09:41
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1As other answers have correctly noted, and @Mat has implied, this is clearly false. Just because the implementation *you* used uses an 8-bit section of memory, does not mean that is always the case. I know for a fact that a custom compiler we use, uses a 4-bit "microword" for booleans on their microprocessor. – SimonC Jan 08 '23 at 18:37