@MarcB mentioned that it is dirty to use regex to remove an url parameter. And yes it is, because it's not as easy as it looks:
$urls = array(
'example.com/?foo=bar',
'example.com/?bar=foo&foo=bar',
'example.com/?foo=bar&bar=foo',
);
echo 'Original' . PHP_EOL;
foreach ($urls as $url) {
echo $url . PHP_EOL;
}
echo PHP_EOL . '@AaronHathaway' . PHP_EOL;
foreach ($urls as $url) {
echo preg_replace('#&?foo=[^&]*#', null, $url) . PHP_EOL;
}
echo PHP_EOL . '@SergeS' . PHP_EOL;
foreach ($urls as $url) {
echo preg_replace( "/&{2,}/", "&", preg_replace( "/foo=[^&]+/", "", $url)) . PHP_EOL;
}
echo PHP_EOL . '@Justin' . PHP_EOL;
foreach ($urls as $url) {
echo preg_replace('/([?&])foo=[^&]+(&|$)/', '$1', $url) . PHP_EOL;
}
echo PHP_EOL . '@kraftb' . PHP_EOL;
foreach ($urls as $url) {
echo preg_replace('/(&|\?)foo=[^&]*&/', '$1', preg_replace('/(&|\?)foo=[^&]*$/', '', $url)) . PHP_EOL;
}
echo PHP_EOL . 'My version' . PHP_EOL;
foreach ($urls as $url) {
echo str_replace('/&', '/?', preg_replace('#[&?]foo=[^&]*#', null, $url)) . PHP_EOL;
}
returns:
Original
example.com/?foo=bar
example.com/?bar=foo&foo=bar
example.com/?foo=bar&bar=foo
@AaronHathaway
example.com/?
example.com/?bar=foo
example.com/?&bar=foo
@SergeS
example.com/?
example.com/?bar=foo&
example.com/?&bar=foo
@Justin
example.com/?
example.com/?bar=foo&
example.com/?bar=foo
@kraftb
example.com/
example.com/?bar=foo
example.com/?bar=foo
My version
example.com/
example.com/?bar=foo
example.com/?bar=foo
As you can see only @kraftb posted a correct answer using regex and my version is a little bit smaller.