If your compiler supports export
, then it doesn't. Only EDG-based compilers support export
, and it's going to be removed from C++0x because of that.
Non-exported templates require that the compiler can see the full template definition, in order to instantiate it for the particular types you supply as arguments. For example:
template<typename T>
struct X {
T t;
X(int i): t(i) {}
};
Now, when you write X<float>(5)
in some translation unit, the compiler as part of compiling that translation unit must check that the constructor of X is type-correct, generate the code for it, and so on. Hence it must see the definition of X, so that it can permit X<float>(5)
but forbid X<char*>(5)
.
The only sensible way to ensure that the compiler sees the same template definition in all translation units that use it, is to put the definition in a header file. As far as the standard is concerned, though, you're welcome to copy-and-paste it manually, or to define a template in a cpp file that is used only in that one translation unit.
export
in effect tells the compiler that it must output a parsed form of the template definition into a special kind of object file. Then the linker performs template instantiation. With normal toolchains, the compiler is smart enough to perform template instantiation and the linker isn't. Bear in mind that template instantiation has to do pretty much everything that the compiler does beyond basic parsing.