Regex for splitting into sentences, ignoring decimal numbers as part of the split?

Question

In javascript, I'm interested in splitting a body of text into an array sentences, where it ignores decimal numbers (and ideally web sites) for the split. I've found how to do it for sentences - e.g., str.split(/[\.\!]+\s*|\n+\s*/) - but not sure how to add the extra bit to ignore decimal numbers in the split

For example, if

str = "Hello there, the ice cream is $2.00.Toppings are extra."

Would result in

["Hello there, the ice cream is $2.00", "Toppings are extra"]

Is this possible?

thanks!

There's always a caveat.... *"My favourite number is 23.23 is definitely my favourite number."* — Reinstate Monica Cellio, Sep 06 '18 at 16:38
Because some you are using Chrome? Chrome 64+ featues regex lookbehinds. — wp78de, Sep 06 '18 at 16:47

TheMaster · Accepted Answer · 2018-09-06T16:53:51.240

2

str = "Hello there, the ice cream is $2.00.Toppings are extra.";    
str.split(/[\.\!]+(?!\d)\s*|\n+\s*/); //[ 'Hello there, the ice cream is $2.00', 'Toppings are extra',]

(?!\d) Zero-width negative lookahead to match digit.

If the lookahead matches, The regex is not matched and the string is not splitted.

edited Sep 06 '18 at 16:53

answered Sep 06 '18 at 16:50

TheMaster

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This results in one empty match `""`. – Paolo Sep 06 '18 at 16:53
@|'-'| your original [\.\!]+(?!\d)\s*|\n+\s* seemed to work pretty well in some initial tests – user655489 Sep 06 '18 at 16:58
sorry - I thought I saw a difference – user655489 Sep 06 '18 at 17:02

score 0 · Answer 2 · answered Jan 25 '22 at 04:05

0

Scala :

    import java.util.regex.Pattern;
    var regPattern = "(?<!\\d)\\.(?!\\d)|(?<=\\d)\\.(?!\\d)|(?<!\\d)\\.(?=\\d)";
    val pt = regPattern.compile(pattern);
    var strList: List[String]= pt.split(input).map(_.trim)(breakOut)

answered Jan 25 '22 at 04:05

vaquar khan

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Regex for splitting into sentences, ignoring decimal numbers as part of the split?

2 Answers2

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