python - Variable scope after using a 'with' statement

Question

I didn't find the answer for this question on stackoverflow, so I thought it might be helpful to ask it, and have it here -

I am declaring a new dictionary after I open a file, in the following way -

with open('some_file.txt','r') as f:
    dict = json.loads(f.read()) #converts text to a dictionary

my question is - will I be able to reach dict content's even after the 'with' scope ends.

Thanks

1) thought would be helpful to have it here for others 2) also looking for why it is the way it is (i.e. why is it different from the variable's scope inside the 'if' statements for example) — Viktor Karsakov, Oct 25 '18 at 15:07

score 15 · Accepted Answer · answered Oct 25 '18 at 14:59

Yes, in Python the scope of a variable ends only when the code block it's defined in ends, and the with statement is not a code block per the documentation:

The following are blocks: a module, a function body, and a class definition. Each command typed interactively is a block. A script file (a file given as standard input to the interpreter or specified as a command line argument to the interpreter) is a code block. A script command (a command specified on the interpreter command line with the ‘-c’ option) is a code block. The string argument passed to the built-in functions eval() and exec() is a code block.

score 1 · Answer 2 · answered Oct 25 '18 at 14:59

1

In python scope is defined by functions. There is no indentation scope (similar to "bracket" scope in other languages). The with part affects just the f object.

answered Oct 25 '18 at 14:59

blue_note

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The `with` statement only *assigns* to `f`, introducing the name into the current containing scope if necessary. The name remains in scope after the `with` statement completes. – chepner Oct 25 '18 at 15:03
@chepner: yes, but exiting the context manager *affects* the object assigned to `f`. I didn't say it disappears – blue_note Oct 25 '18 at 15:04

score -1 · Answer 3 · answered Oct 25 '18 at 14:58

-1

Yes you will, you will not be able to access f, everything else is fair game.

answered Oct 25 '18 at 14:58

Pykler

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`f` remains in scope. The underlying file is closed, but in general whatever object is bound by the `as` keyword in the `with` statement remains available after the `with`, until the end of the enclosing block. – chepner Oct 25 '18 at 15:02

python - Variable scope after using a 'with' statement

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