spread syntax vs slice method

Question

I was trying to understand what is the difference between spread syntax vs slice method in the following approach.

suppose I want to make an actual copy of an array, I can probably easily do it using spread syntax

var fruits = ["Banana", "Chips" , "Orange", "Lemon", "Apple", "Mango"]
var newCitrus = [...fruits]

If I console.log this

["Banana", "Chips", "Orange", "Lemon", "Apple", "Mango"] 

but I can also create a copy of an array using the slice method. Considering the same array above, if I do something like this...

var citrus = fruits.slice(0);

and then console log it, it will give me exactly the same array which I would've got through spread syntax

["Banana", "Chips", "Orange", "Lemon", "Apple", "Mango"] 

Since both of them takes about the same time to code/write, What is the difference here? which approach should I usually choose?

Answer 1

Performance aside slice is just a function on Array.prototype so it will work only for arrays and strings. Spread syntax on the other hand will work for any iterable (object which satisfy iterable protocol) so it will work out of the box on any String, Array, TypedArray, Map and Set. You can also easily create custom iterables.

There is also a difference when it comes to sliceing and spreading arrays with holes (sparse arrays). As you can see below, slice will preserve sparseness while spread will fill holes with undefined.

Array(3)         // produces sparse array: [empty × 3]
Array(3).slice() // produces [empty × 3]
[...Array(3)]    // produces [undefined, undefined, undefined]

Spread syntax can also be used to make shallow clones of objects:

const obj = { foo: 'bar', baz: 42 };
const clone = { ...obj };
obj.foo === clone.foo // true
obj.baz === clone.baz // true
obj === clone         // false (references are different)

Answer 2

Measuring in Chrome shows that slice is far more performant than the spread operator, with 67M operations per second against 4M operations per second. If you're building for Chrome or an Electron app (which uses Chromium) I'd go for slice, especially for big data and real time applications.

EDIT:

It seems like the Spread operator is now much faster, albeit still slower than Slice:

Answer 3

Performance will depend on the engine where its' running. And as with most Javscript code, it will probably be running in various different engines. So, use whatever feels aesthetically better. For me that's spread.

... is sheer beauty.

If you decide to go with slice, skip the 0, just say .slice().

Answer 4

Those two methods aren’t actually equivalent though. Slice is a function on Array.prototype and is aware of the array’s implementation. It will create a very efficient copy. More importantly though, .slice() will preserve the sparseness information of your array.

In contrast, [...Array] will simply create a new array from an iterable view of your existing array. Not necessarily as efficient.

Try this:

var a = [];
a.length = 3;
console.log("slice:", a.slice());
console.log("spread:", [...a]);

With Chrome Browser developer console, I get these results:

slice: (3) [empty × 3]
spread: (3) [undefined, undefined, undefined]

If your array is particularly huge+sparse, array.slice() will be exceptionally fast. [...array] will probably hang your browser.

Answer 5

New versions of Chrome (72+) seem to have eliminated the performance gap. https://measurethat.net/Benchmarks/ListResults/2667

Answer 6

Slice: The Slice method takes 2 arguments 1st Argument: Specifies from where the selection should be started. For Example:

let arr1 = [1,5,8,9];
arr1.slice(1); // [5,8,9]

From the first index (5) it will return the elements.

2nd Argument: Specifies at which level the endpoint should be. If you didn’t put this in the parenthesis while calling the slice method, it will return the elements from the starting index to the end of the array.

  let arr1 = [1,5,8,9];
console.log(arr1.slice(1,3));
    //[ 5, 8 ]

If you put a negative number while calling, the selection will be selected from the end of the array.

let arr1 = [1,5,8,9];
console.log(arr1.slice(-2));
//[ 8, 9 ]

Spread Operator: I can use this Spread Syntax to solve this:

let arr1 = [1,3,6,7];
let arr3 = [5,...arr1,8,9];
console.log(arr3);