How do I add a delay in a JavaScript loop?

Question

I would like to add a delay/sleep inside a while loop:

I tried it like this:

alert('hi');

for(var start = 1; start < 10; start++) {
  setTimeout(function () {
    alert('hello');
  }, 3000);
}

Only the first scenario is true: after showing alert('hi'), it will be waiting for 3 seconds then alert('hello') will be displayed but then alert('hello') will be repeatedly constantly.

What I would like is that after alert('hello') is shown 3 seconds after alert('hi') then it needs to wait for 3 seconds for the second time alert('hello') and so on.

Answer 1

The setTimeout() function is non-blocking and will return immediately. Therefore your loop will iterate very quickly and it will initiate 3-second timeout triggers one after the other in quick succession. That is why your first alerts pops up after 3 seconds, and all the rest follow in succession without any delay.

You may want to use something like this instead:

var i = 1;                  //  set your counter to 1

function myLoop() {         //  create a loop function
  setTimeout(function() {   //  call a 3s setTimeout when the loop is called
    console.log('hello');   //  your code here
    i++;                    //  increment the counter
    if (i < 10) {           //  if the counter < 10, call the loop function
      myLoop();             //  ..  again which will trigger another 
    }                       //  ..  setTimeout()
  }, 3000)
}

myLoop();                   //  start the loop

You could also neaten it up, by using a self invoking function, passing the number of iterations as an argument:

(function myLoop(i) {
  setTimeout(function() {
    console.log('hello'); //  your code here                
    if (--i) myLoop(i);   //  decrement i and call myLoop again if i > 0
  }, 3000)
})(10);                   //  pass the number of iterations as an argument

Answer 2

Since ES7 theres a better way to await a loop:

// Returns a Promise that resolves after "ms" Milliseconds
const timer = ms => new Promise(res => setTimeout(res, ms))

async function load () { // We need to wrap the loop into an async function for this to work
  for (var i = 0; i < 3; i++) {
    console.log(i);
    await timer(3000); // then the created Promise can be awaited
  }
}

load();

When the engine reaches the await part, it sets a timeout and halts the execution of the async function. Then when the timeout completes, execution continues at that point. That's quite useful as you can delay (1) nested loops, (2) conditionally, (3) nested functions:

async function task(i) { // 3
  await timer(1000);
  console.log(`Task ${i} done!`);
}

async function main() {
  for(let i = 0; i < 100; i+= 10) {
    for(let j = 0; j < 10; j++) { // 1
      if(j % 2) { // 2
        await task(i + j);
      }
    }
  }
}
    
main();

function timer(ms) { return new Promise(res => setTimeout(res, ms)); }

Reference on MDN

While ES7 is now supported by NodeJS and modern browsers, you might want to transpile it with BabelJS so that it runs everywhere.

Answer 3

If using ES6, you could use a for loop to achieve this:

for (let i = 1; i < 10; i++) {
  setTimeout(function timer() {
    console.log("hello world");
  }, i * 3000);
}

It declares i for each iteration, meaning the timeout is what it was before + 1000. This way, what is passed to setTimeout is exactly what we want.

Answer 4

Try something like this:

var i = 0, howManyTimes = 10;

function f() {
  console.log("hi");
  i++;
  if (i < howManyTimes) {
    setTimeout(f, 3000);
  }
}

f();

Answer 5

Another way is to multiply the time to timeout, but note that this is not like sleep. Code after the loop will be executed immediately, only the execution of the callback function is deferred.

for (var start = 1; start < 10; start++)
    setTimeout(function () { alert('hello');  }, 3000 * start);

The first timeout will be set to 3000 * 1, the second to 3000 * 2 and so on.

Answer 6

This will work

for (var i = 0; i < 10; i++) {
  (function(i) {
    setTimeout(function() { console.log(i); }, 100 * i);
  })(i);
}

Try this fiddle: https://jsfiddle.net/wgdx8zqq/

Answer 7

I think you need something like this:

var TimedQueue = function(defaultDelay){
    this.queue = [];
    this.index = 0;
    this.defaultDelay = defaultDelay || 3000;
};

TimedQueue.prototype = {
    add: function(fn, delay){
        this.queue.push({
            fn: fn,
            delay: delay
        });
    },
    run: function(index){
        (index || index === 0) && (this.index = index);
        this.next();
    },
    next: function(){
        var self = this
        , i = this.index++
        , at = this.queue[i]
        , next = this.queue[this.index]
        if(!at) return;
        at.fn();
        next && setTimeout(function(){
            self.next();
        }, next.delay||this.defaultDelay);
    },
    reset: function(){
        this.index = 0;
    }
}

Test code:

var now = +new Date();

var x = new TimedQueue(2000);

x.add(function(){
    console.log('hey');
    console.log(+new Date() - now);
});
x.add(function(){
    console.log('ho');
    console.log(+new Date() - now);
}, 3000);
x.add(function(){
    console.log('bye');
    console.log(+new Date() - now);
});

x.run();

Note: using alerts stalls javascript execution till you close the alert. It might be more code than you asked for, but this is a robust reusable solution.

Answer 8

You can create a sleep function that promisifies setTimeout. This enables you to use async/await to write code without callbacks and the familiar for loop control flow.

const sleep = ms => new Promise(resolve => setTimeout(resolve, ms));

(async () => {
  for (let i = 0; i < 10; i++) {
    console.log(i);
    await sleep(1000);
  }

  console.log("done");
})();

In Node, you can use timers/promises to avoid the promisification step (if the feature isn't supported on your older Node version, the above code works just as well):

const {setTimeout: sleep} = require("timers/promises");

// same code as above

Regardless, since JS is single-threaded, it's a good thing that timeouts are asynchronous. If they weren't, the browser wouldn't get a chance to repaint the UI, leading to a frozen interface for the user.

Answer 9

I would probably use setInterval, like this:

var period = 1000; // ms
var endTime = 10000;  // ms
var counter = 0;
var sleepyAlert = setInterval(function(){
    alert('Hello');
    if(counter === endTime){
       clearInterval(sleepyAlert);
    }
    counter += period;
}, period);

Answer 10

In my opinion, the simpler and most elegant way to add a delay in a loop is like this:

names = ['John', 'Ana', 'Mary'];

names.forEach((name, i) => {
 setTimeout(() => {
  console.log(name);
 }, i * 1000);  // one sec interval
});

Answer 11

In ES6 (ECMAScript 2015) you can iterate with delay with generator and interval.

Generators, a new feature of ECMAScript 6, are functions that can be paused and resumed. Calling genFunc does not execute it. Instead, it returns a so-called generator object that lets us control genFunc’s execution. genFunc() is initially suspended at the beginning of its body. The method genObj.next() continues the execution of genFunc, until the next yield. (Exploring ES6)

Code example:

let arr = [1, 2, 3, 'b'];
let genObj = genFunc();

let val = genObj.next();
console.log(val.value);

let interval = setInterval(() => {
  val = genObj.next();
  
  if (val.done) {
    clearInterval(interval);
  } else {
    console.log(val.value);
  }
}, 1000);

function* genFunc() {
  for(let item of arr) {
    yield item;
  }
}

So if you are using ES6, that the most elegant way to achieve loop with delay (for my opinion).

Answer 12

Dead-simple, one-line solution with an actual async-await delay (no queued setTimeout):

await new Promise((resolve) => {setTimeout(() => {resolve(true)}, 190)});

An actual delay inside an async function, as an alternative ot commonly used multiple setTimeouts with different timeout intervals, which might mess up memory. 190ms delay in case of this snippet.

Example:

• In each of the 100 loops, it awaits for a new Promise to resolve.
• This happens only after setTimeout 'allows' it after 190ms. Until then, code is blocked by the async-await / pending Promise.

async function delayTest() {
  for (let i=0; i<100; i++) {
    await new Promise((resolve) => {setTimeout(() => {document.write(`${i} `); resolve(true)}, 190)});
  }
};

delayTest()

Answer 13

I do this with Bluebird’s Promise.delay and recursion.

function myLoop(i) {
  return Promise.delay(1000)
    .then(function() {
      if (i > 0) {
        alert('hello');
        return myLoop(i -= 1);
      }
    });
}

myLoop(3);

<script src="//cdnjs.cloudflare.com/ajax/libs/bluebird/2.9.4/bluebird.min.js"></script>

Answer 14

In ES6 you can do as following:

 for (let i = 0; i <= 10; i++){       
     setTimeout(function () {   
        console.log(i);
     }, i*3000)
 }

In ES5 you can do as:

for (var i = 0; i <= 10; i++){
   (function(i) {          
     setTimeout(function () {   
        console.log(i);
     }, i*3000)
   })(i);  
 }

The reason is, let allows you to declare variables that are limited to a scope of a block statement, or expression on which it is used, unlike the var keyword, which defines a variable globally, or locally to an entire function regardless of block scope.

Answer 15

A function-less solution

I am a bit late to the party, but there is a solution without using any functions:

alert('hi');

for(var start = 1; start < 10; start++) {
  setTimeout(() => alert('hello'), 3000 * start);
}

Answer 16

Just thought I'd post my two cents here as well. This function runs an iterative loop with a delay. See this jsfiddle. The function is as follows:

function timeout(range, time, callback){
    var i = range[0];                
    callback(i);
    Loop();
    function Loop(){
        setTimeout(function(){
            i++;
            if (i<range[1]){
                callback(i);
                Loop();
            }
        }, time*1000)
    } 
}

For example:

//This function prints the loop number every second
timeout([0, 5], 1, function(i){
    console.log(i);
});

Would be equivalent to:

//This function prints the loop number instantly
for (var i = 0; i<5; i++){
    console.log(i);
}

Answer 17

To my knowledge the setTimeout function is called asynchronously. What you can do is wrap the entire loop within an async function and await a Promise that contains the setTimeout as shown:

var looper = async function () {
  for (var start = 1; start < 10; start++) {
    await new Promise(function (resolve, reject) {
      setTimeout(function () {
        console.log("iteration: " + start.toString());
        resolve(true);
      }, 1000);
    });
  }
  return true;
}

And then you call run it like so:

looper().then(function(){
  console.log("DONE!")
});

Please take some time to get a good understanding of asynchronous programming.

Answer 18

In addition to the accepted answer from 10 years ago, with more modern Javascript one can use async/await/Promise() or generator function to achieve the correct behavior. (The incorrect behavior suggested in other answers would be setting series of 3 seconds alerts regardless of "accepting" the alert() - or finishing the task at hand)

Using async/await/Promise():

alert('hi');

(async () => {
  for(let start = 1; start < 10; start++) {
    await new Promise(resolve => setTimeout(() => {
      alert('hello');
      resolve();
    }, 3000));
  }
})();

Using a generator function:

alert('hi');

let func;

(func = (function*() {
  for(let start = 1; start < 10; start++) {
    yield setTimeout(() => {
      alert('hello');
      func.next();
    }, 3000);
  }
})()).next();

Answer 19

You can use the RxJS interval operator. interval emits an integer every x seconds, and take specifies the number of times it emits these numbers.

Rx.Observable
  .interval(1000)
  .take(10)
  .subscribe((x) => console.log(x))

<script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/4.1.0/rx.lite.min.js"></script>

Answer 20

    var startIndex = 0;
    var data = [1, 2, 3];
    var timeout = 1000;

    function functionToRun(i, length) {
      alert(data[i]);
    }

    (function forWithDelay(i, length, fn, delay) {
      setTimeout(function() {
        fn(i, length);
        i++;
        if (i < length) {
          forWithDelay(i, length, fn, delay);
        }
      }, delay);
    })(startIndex, data.length, functionToRun, timeout);

A modified version of Daniel Vassallo's answer, with variables extracted into parameters to make the function more reusable:

First let's define some essential variables:

var startIndex = 0;
var data = [1, 2, 3];
var timeout = 3000;

Next you should define the function you want to run. This will get passed i, the current index of the loop and the length of the loop, in case you need it:

function functionToRun(i, length) {
    alert(data[i]);
}

Self-executing version

(function forWithDelay(i, length, fn, delay) {
   setTimeout(function () {
      fn(i, length);
      i++;
      if (i < length) {
         forWithDelay(i, length, fn, delay); 
      }
  }, delay);
})(startIndex, data.length, functionToRun, timeout);

Functional version

function forWithDelay(i, length, fn, delay) {
   setTimeout(function () {
      fn(i, length);
      i++;
      if (i < length) {
         forWithDelay(i, length, fn, delay); 
      }
  }, delay);
}

forWithDelay(startIndex, data.length, functionToRun, timeout); // Lets run it

Answer 21

Just try this

 var arr = ['A','B','C'];
 (function customLoop (arr, i) {
    setTimeout(function () {
    // Do here what you want to do.......
    console.log(arr[i]);
    if (--i) {                
      customLoop(arr, i); 
    }
  }, 2000);
})(arr, arr.length);

Result

A // after 2s
B // after 2s
C // after 2s

Answer 22

This script works for most things

function timer(start) {
    setTimeout(function () { //The timer
        alert('hello');
    }, start*3000); //needs the "start*" or else all the timers will run at 3000ms
}

for(var start = 1; start < 10; start++) {
    timer(start);
}

Answer 23

Here is how I created an infinite loop with a delay that breaks on a certain condition:

  // Now continuously check the app status until it's completed, 
  // failed or times out. The isFinished() will throw exception if
  // there is a failure.
  while (true) {
    let status = await this.api.getStatus(appId);
    if (isFinished(status)) {
      break;
    } else {
      // Delay before running the next loop iteration:
      await new Promise(resolve => setTimeout(resolve, 3000));
    }
  }

The key here is to create a new Promise that resolves by timeout, and to await for its resolution.

Obviously you need async/await support for that. Works in Node 8.

Answer 24

for common use "forget normal loops" and use this combination of "setInterval" includes "setTimeOut"s: like this (from my real tasks).

        function iAsk(lvl){
            var i=0;
            var intr =setInterval(function(){ // start the loop 
                i++; // increment it
                if(i>lvl){ // check if the end round reached.
                    clearInterval(intr);
                    return;
                }
                setTimeout(function(){
                    $(".imag").prop("src",pPng); // do first bla bla bla after 50 millisecond
                },50);
                setTimeout(function(){
                     // do another bla bla bla after 100 millisecond.
                    seq[i-1]=(Math.ceil(Math.random()*4)).toString();
                    $("#hh").after('<br>'+i + ' : rand= '+(Math.ceil(Math.random()*4)).toString()+' > '+seq[i-1]);
                    $("#d"+seq[i-1]).prop("src",pGif);
                    var d =document.getElementById('aud');
                    d.play();                   
                },100);
                setTimeout(function(){
                    // keep adding bla bla bla till you done :)
                    $("#d"+seq[i-1]).prop("src",pPng);
                },900);
            },1000); // loop waiting time must be >= 900 (biggest timeOut for inside actions)
        }

PS: Understand that the real behavior of (setTimeOut): they all will start in same time "the three bla bla bla will start counting down in the same moment" so make a different timeout to arrange the execution.

PS 2: the example for timing loop, but for a reaction loops you can use events, promise async await ..

Answer 25

   let counter =1;
   for(let item in items) {
        counter++;
        setTimeout(()=>{
          //your code
        },counter*5000); //5Sec delay between each iteration
    }

Answer 26

const autoPlayer = (arr = [1, 2, 3, 4, 5]) => {
  // Base case:
  if (arr.length < 1) return

  // Remove the first element from the array.
  const item = arr.shift()

  // Set timout 
  setTimeout(() => {
    console.log('Hello, world!', item)  // Visualisation.
    autoPlayer() // Call function again.
  }, 1000) // Iterate every second.
}

Hey, I know this post is very old, but this code "loops" and adds a delay to it using a recursive method. I don't think you can 'actually' delay a loop itself from iterating based on reading various comments from other people. Maybe this can help someone out! Basically the function accepts an array (in this example). On each iteration the setTimeout Javascript method is called. The function calls itself again indefinitely when the timer of the setTimeout function expires, but on each call the array becomes smaller until it reaches the base-case. I hope this can help anyone else out.

Answer 27

A simple, but not very elegant solution is to nest a second loop which would act as a timer (essentially, the nested loop would hold the thread). This's a dirty workaround if you're writing something temporary.

for(i=0;i<arr.length;i++){
   //you logic here

   //this will act as a timer
   for(j=0;j<25000;j++) console.log("")
}

Last week I had to download about 40 files from a website, so I wrote a short JS script to be executed through Chrome's console, and the nested loop trick did a great job in delaying the execution.

Answer 28

/* 
  Use Recursive  and setTimeout 
  call below function will run loop loopFunctionNeedCheck until 
  conditionCheckAfterRunFn = true, if conditionCheckAfterRunFn == false : delay 
  reRunAfterMs miliseconds and continue loop
  tested code, thanks
*/

function functionRepeatUntilConditionTrue(reRunAfterMs, conditionCheckAfterRunFn,
 loopFunctionNeedCheck) {
    loopFunctionNeedCheck();
    var result = conditionCheckAfterRunFn();
    //check after run
    if (!result) {
        setTimeout(function () {
            functionRepeatUntilConditionTrue(reRunAfterMs, conditionCheckAfterRunFn, loopFunctionNeedCheck)
        }, reRunAfterMs);
    }
    else  console.log("completed, thanks");    
            //if you need call a function after completed add code call callback in here
}

//passing-parameters-to-a-callback-function
// From Prototype.js 
if (!Function.prototype.bind) { // check if native implementation available
    Function.prototype.bind = function () {
        var fn = this, args = Array.prototype.slice.call(arguments),
            object = args.shift();
        return function () {
            return fn.apply(object,
              args.concat(Array.prototype.slice.call(arguments)));
        };
    };
}

//test code: 
var result = 0; 
console.log("---> init result is " + result);
var functionNeedRun = function (step) {           
   result+=step;    
       console.log("current result is " + result);  
}
var checkResultFunction = function () {
    return result==100;
}  

//call this function will run loop functionNeedRun and delay 500 miliseconds until result=100    
functionRepeatUntilConditionTrue(500, checkResultFunction , functionNeedRun.bind(null, 5));

//result log from console:
/*
---> init result is 0
current result is 5
undefined
current result is 10
current result is 15
current result is 20
current result is 25
current result is 30
current result is 35
current result is 40
current result is 45
current result is 50
current result is 55
current result is 60
current result is 65
current result is 70
current result is 75
current result is 80
current result is 85
current result is 90
current result is 95
current result is 100
completed, thanks
*/

Answer 29

Here is a function that I use for looping over an array:

function loopOnArrayWithDelay(theArray, delayAmount, i, theFunction, onComplete){

    if (i < theArray.length && typeof delayAmount == 'number'){

        console.log("i "+i);

        theFunction(theArray[i], i);

        setTimeout(function(){

            loopOnArrayWithDelay(theArray, delayAmount, (i+1), theFunction, onComplete)}, delayAmount);
    }else{

        onComplete(i);
    }
}

You use it like this:

loopOnArrayWithDelay(YourArray, 1000, 0, function(e, i){
    //Do something with item
}, function(i){
    //Do something once loop has completed
}

Answer 30

<!DOCTYPE html>
<html>
<body>

<button onclick="myFunction()">Try it</button>

<p id="demo"></p>

<script>
function myFunction() {
    for(var i=0; i<5; i++) {
     var sno = i+1;
        (function myLoop (i) {          
             setTimeout(function () {   
              alert(i); // Do your function here 
             }, 1000*i);
        })(sno);
    }
}
</script>

</body>
</html>

Answer 31

Try this...

var icount=0;
for (let i in items) {
   icount=icount+1000;
   new beginCount(items[i],icount);
}

function beginCount(item,icount){
  setTimeout(function () {

   new actualFunction(item,icount);

 }, icount);
}

function actualFunction(item,icount){
  //...runs ever 1 second
 console.log(icount);
}

Answer 32

You do it:

console.log('hi')
let start = 1
setTimeout(function(){
  let interval = setInterval(function(){
    if(start == 10) clearInterval(interval)
    start++
    console.log('hello')
  }, 3000)
}, 3000)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Answer 33

Simple implementation of showing a piece of text every two seconds as long the loop is running.

for (var i = 0; i < foo.length; i++) {
   setInterval(function(){ 
     console.log("I will appear every 2 seconds"); 
   }, 2000);
  break;
};