Proper way to wait for one function to finish before continuing?

Question

I have two JS functions. One calls the other. Within the calling function, I'd like to call the other, wait for that function to finish, then continue on. So, for example/pseudo code:

function firstFunction(){
    for(i=0;i<x;i++){
        // do something
    }
};

function secondFunction(){
    firstFunction()
    // now wait for firstFunction to finish...
    // do something else
};

I came up with this solution, but don't know if this is a smart way to go about it.

var isPaused = false;

function firstFunction(){
    isPaused = true;
    for(i=0;i<x;i++){
        // do something
    }
    isPaused = false;
};

function secondFunction(){
    firstFunction()
    function waitForIt(){
        if (isPaused) {
            setTimeout(function(){waitForIt()},100);
        } else {
            // go do that thing
        };
    }
};

Is that legit? Is there a more elegant way to handle it? Perhaps with jQuery?

Answer 1

One way to deal with asynchronous work like this is to use a callback function, eg:

function firstFunction(_callback){
    // do some asynchronous work
    // and when the asynchronous stuff is complete
    _callback();    
}

function secondFunction(){
    // call first function and pass in a callback function which
    // first function runs when it has completed
    firstFunction(function() {
        console.log('huzzah, I\'m done!');
    });    
}

---

As per @Janaka Pushpakumara's suggestion, you can now use arrow functions to achieve the same thing. For example:

firstFunction(() => console.log('huzzah, I\'m done!'))

---

Update: I answered this quite some time ago, and really want to update it. While callbacks are absolutely fine, in my experience they tend to result in code that is more difficult to read and maintain. There are situations where I still use them though, such as to pass in progress events and the like as parameters. This update is just to emphasise alternatives.

Also the original question doesn't specificallty mention async, so in case anyone is confused, if your function is synchronous, it will block when called. For example:

doSomething()
// the function below will wait until doSomething completes if it is synchronous
doSomethingElse()

If though as implied the function is asynchronous, the way I tend to deal with all my asynchronous work today is with async/await. For example:

const secondFunction = async () => {
  const result = await firstFunction()
  // do something else here after firstFunction completes
}

IMO, async/await makes your code much more readable than using promises directly (most of the time). If you need to handle catching errors then use it with try/catch. Read about it more here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function .

Answer 2

Use async/await :

async function firstFunction(){
  for(i=0;i<x;i++){
    // do something
  }
  return;
};

then use await in your other function to wait for it to return:

async function secondFunction(){
  await firstFunction();
  // now wait for firstFunction to finish...
  // do something else
};

Answer 3

An elegant way to wait for one function to complete first is to use Promises with async/await function.

---

1. Firstly, create a Promise. The function I created will be completed after 2s. I used setTimeout in order to demonstrate the situation where the instructions would take some time to execute.
2. For the second function, you can use async/await a function where you will await for the first function to complete before proceeding with the instructions.

---

Example:

    //1. Create a new function that returns a promise
    function firstFunction() {
      return new Promise((resolve, reject) => {
          let y = 0
          setTimeout(() => {
            for (i=0; i<10; i++) {
               y++
            }
             console.log('Loop completed.')  
             resolve(y)
          }, 2000)
      })
    }
    
    //2. Create an async function
    async function secondFunction() {
        console.log('Before promise call.')
        //3. Await for the first function to complete
        const result = await firstFunction()
        console.log('Promise resolved: ' + result)
        console.log('Next step.')
    }; 

    secondFunction()

---

Note:

You could simply resolve the Promise without any value like so resolve(). In my example, I resolved the Promise with the value of y that I can then use in the second function.

Answer 4

Notice

This answer is outdated by today's standards. Consider using native JavaScript Promises and async/await syntax instead.

---

It appears you're missing an important point here: JavaScript is a single-threaded execution environment. Let's look again at your code, note I've added alert("Here"):

var isPaused = false;

function firstFunction(){
    isPaused = true;
    for(i=0;i<x;i++){
        // do something
    }
    isPaused = false;
};

function secondFunction(){
    firstFunction()

    alert("Here");

    function waitForIt(){
        if (isPaused) {
            setTimeout(function(){waitForIt()},100);
        } else {
            // go do that thing
        };
    }
};

You don't have to wait for isPaused. When you see the "Here" alert, isPaused will be false already, and firstFunction will have returned. That's because you cannot "yield" from inside the for loop (// do something), the loop may not be interrupted and will have to fully complete first (more details: Javascript thread-handling and race-conditions).

That said, you still can make the code flow inside firstFunction to be asynchronous and use either callback or promise to notify the caller. You'd have to give up upon for loop and simulate it with if instead (JSFiddle):

function firstFunction()
{
    var deferred = $.Deferred();
    
    var i = 0;
    var nextStep = function() {
        if (i<10) {
            // Do something
            printOutput("Step: " + i);
            i++;
            setTimeout(nextStep, 500); 
        }
        else {
            deferred.resolve(i);
        }
    }
    nextStep();
    return deferred.promise();
}

function secondFunction()
{
    var promise = firstFunction();
    promise.then(function(result) { 
        printOutput("Result: " + result);
    });
}

On a side note, JavaScript 1.7 has introduced yield keyword as a part of generators. That will allow to "punch" asynchronous holes in otherwise synchronous JavaScript code flow (more details and an example). However, the browser support for generators is currently limited to Firefox and Chrome, AFAIK.

Answer 5

I wonder why no one have mentioned this simple pattern? :

(function(next) {
  //do something
  next()
}(function() {
  //do some more
}))

Using timeouts just for blindly waiting is bad practice; and involving promises just adds more complexity to the code. In OP's case:

(function(next) {
  for(i=0;i<x;i++){
    // do something
    if (i==x-1) next()
  }
}(function() {
  // now wait for firstFunction to finish...
  // do something else
}))

a small demo -> http://jsfiddle.net/5jdeb93r/

Answer 6

The only issue with promises is that IE doesn't support them. Edge does, but there's plenty of IE 10 and 11 out there: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise (compatibility at the bottom)

So, JavaScript is single-threaded. If you're not making an asynchronous call, it will behave predictably. The main JavaScript thread will execute one function completely before executing the next one, in the order they appear in the code. Guaranteeing order for synchronous functions is trivial - each function will execute completely in the order it was called.

Think of the synchronous function as an atomic unit of work. The main JavaScript thread will execute it fully, in the order the statements appear in the code.

But, throw in the asynchronous call, as in the following situation:

showLoadingDiv(); // function 1

makeAjaxCall(); // function 2 - contains async ajax call

hideLoadingDiv(); // function 3

This doesn't do what you want. It instantaneously executes function 1, function 2, and function 3. Loading div flashes and it's gone, while the ajax call is not nearly complete, even though makeAjaxCall() has returned. THE COMPLICATION is that makeAjaxCall() has broken its work up into chunks which are advanced little by little by each spin of the main JavaScript thread - it's behaving asychronously. But that same main thread, during one spin/run, executed the synchronous portions quickly and predictably.

So, the way I handled it: Like I said the function is the atomic unit of work. I combined the code of function 1 and 2 - I put the code of function 1 in function 2, before the asynch call. I got rid of function 1. Everything up to and including the asynchronous call executes predictably, in order.

THEN, when the asynchronous call completes, after several spins of the main JavaScript thread, have it call function 3. This guarantees the order. For example, with ajax, the onreadystatechange event handler is called multiple times. When it reports it's completed, then call the final function you want.

I agree it's messier. I like having code be symmetric, I like having functions do one thing (or close to it), and I don't like having the ajax call in any way be responsible for the display (creating a dependency on the caller). BUT, with an asynchronous call embedded in a synchronous function, compromises have to be made in order to guarantee order of execution. And I have to code for IE 10 so no promises.

Summary: For synchronous calls, guaranteeing order is trivial. Each function executes fully in the order it was called. For a function with an asynchronous call, the only way to guarantee order is to monitor when the async call completes, and call the third function when that state is detected.

For a discussion of JavaScript threads, see: https://medium.com/@francesco_rizzi/javascript-main-thread-dissected-43c85fce7e23 and https://developer.mozilla.org/en-US/docs/Web/JavaScript/EventLoop

Also, another similar, highly rated question on this subject: How should I call 3 functions in order to execute them one after the other?

Answer 7

Can use Promise

A promise is a JavaScript construct that represents a future unknown value. It could be the result from an API call, or it could be an error object from a failed network request. You're guaranteed to get something.

const promise = new Promise((resolve, reject) => {
    // Make a network request
   if (yourcondition=="value") {
      
   } else {
      reject(error);
   }
})

promise.then(res => {
    //if not rejected, code

}).catch(err => {
    //return false; 
})

A promise can have

fulfilled - action successfully completed

rejected - action failed

pending - neither action has been completed

settled - has been fulfilled or rejected

Answer 8

Your main function will call firstFunction then on complete of it your next function will execute.

async firstFunction() {
            const promise = new Promise((resolve, reject) => {
                for (let i = 0; i < 5; i++) {
                    // do something
                    console.log(i);
                    if (i == 4) {
                        resolve(i);
                    }
                }
            });
            const result = await promise;
        }
    
        second() {
            this.firstFunction().then( res => {
                // third function call do something
                console.log('Gajender here');
            });
        }

Answer 9

I wrote this after two days of trying. This is the best way try like this:

var recv = -1;

async function First_fn() {

    var answ = await Second_fn();
    console.log(answ);
    recv = -1;

}

async function Second_fn() {
    var parm = 1;
    var adrss = 2;

    await Third_fn(adrss, parm);
    // Using the following loop will minimize the waiting time
    for (let i = 0; i < 180; i++) {
        if (recv !== -1) {
            console.log(recv);
            break;
        }
        else {
            await new Promise(resolve => setTimeout(resolve, 500));
        }
    }
    return recv;
}

async function Third_fn(adrss, parm) {
    //someting to do => result
    //for example:
    let result = adrss + parm;
    recv = result; // recv is global varable
 }
 
First_fn(); 

Answer 10

This what I came up with, since I need to run several operations in a chain.

<button onclick="tprom('Hello Niclas')">test promise</button>

<script>
    function tprom(mess) {
        console.clear();

        var promise = new Promise(function (resolve, reject) {
            setTimeout(function () {
                resolve(mess);
            }, 2000);
        });

        var promise2 = new Promise(async function (resolve, reject) {
            await promise;
            setTimeout(function () {
                resolve(mess + ' ' + mess);
            }, 2000);
        });

        var promise3 = new Promise(async function (resolve, reject) {
            await promise2;
            setTimeout(function () {
                resolve(mess + ' ' + mess+ ' ' + mess);
            }, 2000);
        });

        promise.then(function (data) {
            console.log(data);
        });

        promise2.then(function (data) {
            console.log(data);
        });

        promise3.then(function (data) {
            console.log(data);
        });
    }

</script>

Answer 11

Try this

function firstFunction(){
    
    // do something  
    X=true;
    return X;
}

function secondFunction(){
    X=false;
    X=firstFunction();
    setTimeout( function() {
        if(X==true){
            // do something else
        }else{
            // do something else
        }
        alert(X); // To check X 
       
    }, 100); // Can increase time delay 200,300, ...
}

Increase the time from 100 to 200, 300, ... Based on the time required for the firstFunction to complete

Answer 12

I had the same Issue.
My Solution was to call my second function at the end of my async function,
since you already have a For loop in your async function,
you could call your second function once the highest value of the loop condition has been reached
which in your case is
i = x-1 so:

function firstFunction(){
  for(i=0;i<x;i++){
     // do something
     if(i === x - 1){
       // do something else or call secondFunction();
     }
  }
}