I was following a video for this little project but i encountered this error
Traceback (most recent call last):
File "C:/Users/Dell/Desktop/Pygame/games/pong.py", line 92, in <module>
ball.setx(ball.xcor()+ball.dx)
File "C:\Users\Dell\AppData\Local\Programs\Python\Python37-32\lib\turtle.py", line 1808, in setx
self._goto(Vec2D(x, self._position[1]))
File "C:\Users\Dell\AppData\Local\Programs\Python\Python37-32\lib\turtle.py", line 3158, in _goto
screen._pointlist(self.currentLineItem),
File "C:\Users\Dell\AppData\Local\Programs\Python\Python37-32\lib\turtle.py", line 755, in _pointlist
cl = self.cv.coords(item)
File "<string>", line 1, in coords
File "C:\Users\Dell\AppData\Local\Programs\Python\Python37-32\lib\tkinter\__init__.py", line 2469, in coords
self.tk.call((self._w, 'coords') + args))]
_tkinter.TclError: invalid command name ".!canvas"
This happens when I press the exit button to close the window. How to solve this?
Here's the code:
import turtle
wn = turtle.Screen()
wn.title("Pong")
wn.bgcolor('black')
wn.setup(width=800, height=600)
wn.tracer(0)
#Score
score_a = 0
score_b = 0
#paddle A
paddle_a = turtle.Turtle()
paddle_a.speed(0)
paddle_a.shape("square")
paddle_a.color("white")
paddle_a.shapesize(stretch_wid=5, stretch_len = 1)
paddle_a.penup()
paddle_a.goto(-350,0)
#paddle B
paddle_b = turtle.Turtle()
paddle_b.speed(0)
paddle_b.shape("square")
paddle_b.color("white")
paddle_b.shapesize(stretch_wid=5, stretch_len = 1)
paddle_b.penup()
paddle_b.goto(350,0)
#Ball
ball = turtle.Turtle()
ball.speed(0)
ball.shape("circle")
ball.color("white")
ball.penup()
ball.goto(0,0)
ball.dx = 0.5
ball.dy = 0.5
#pen
pen = turtle.Turtle()
pen.speed(0)
pen.color("white")
pen.penup()
pen.hideturtle()
pen.goto(0,260)
pen.write("Player A: 0 Player B: 0", align="center", font=('Courier', 24, "normal"))
#Function
def paddle_a_up():
y = paddle_a.ycor()
y+=20
paddle_a.sety(y)
def paddle_a_down():
y = paddle_a.ycor()
y-=20
paddle_a.sety(y)
def paddle_b_up():
y = paddle_b.ycor()
y+=20
paddle_b.sety(y)
def paddle_b_down():
y = paddle_b.ycor()
y-=20
paddle_b.sety(y)
#Keyboard binding
wn.listen()
wn.onkeypress(paddle_a_up, "w")
wn.onkeypress(paddle_a_down, "s")
wn.onkeypress(paddle_b_up, "Up")
wn.onkeypress(paddle_b_down, "Down")
running = True
#main game loop
while running:
wn.update()
#move the ball
ball.setx(ball.xcor()+ball.dx)
ball.sety(ball.ycor()+ball.dy)
#border
if ball.ycor() > 280:
ball.sety(280)
ball.dy*=-1
if ball.ycor() < -280:
ball.sety(-280)
ball.dy*=-1
if ball.xcor() > 380:
ball.goto(0,0)
ball.dx*=-1
score_a+=1
pen.clear()
pen.write(f"Player A: {score_a} Player B: {score_b}", align="center", font=('Courier', 24, "normal"))
if ball.xcor() < -380:
ball.goto(0,0)
ball.dx*=-1
score_b += 1
pen.clear()
pen.write(f"Player A: {score_a} Player B: {score_b}", align="center", font=('Courier', 24, "normal"))
#colliosion
if (ball.xcor() > 330 and ball.xcor() < 340) and (ball.ycor() < paddle_b.ycor() + 50 and ball.ycor() > paddle_b.ycor() -50):
ball.setx(330)
ball.dx*=-1
if (ball.xcor() < -330 and ball.xcor() > -340) and (ball.ycor() < paddle_a.ycor() + 50 and ball.ycor() > paddle_a.ycor() -50):
ball.setx(-330)
ball.dx*=-1
i read about putting the .mainloop() method but i couldn't figure out where do i put it. I understand this much that the while loop runs forever and has no condition to stop here so how do i make the loop stop? How do i tell python to stop the loop and quit the window after pressing the exit button?