As I can see you are trying to use MVVM as a pattern for your Xamarin.Forms app. You are already using the ObservableCollection
for displaying a list of the data. When a new item is added or removed from collection UI will be refreshed accordingly and that is because the ObserverbleCollection
is implementing INotifyCollectionChanged
.
What you want to achieve with this question is next behaviour, when you want to change the particular value for the item in the collection and update the UI the best and simplest way to achieve that is to implement INotifyPropertyChanged
for a model of the item from your collection.
Bellow, I have a simple demo example on how to achieve that, your answer is working as I can see but I am sure this example would be nicer for you to use it.
I have simple Button
with command and ListView
which holds my collection data.
Here is my page, SimpleMvvmExamplePage.xaml
:
<StackLayout>
<Button Text="Set status"
Command="{Binding SetStatusCommand}"
Margin="6"/>
<ListView ItemsSource="{Binding Cars}"
HasUnevenRows="True">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout Orientation="Vertical"
Margin="8">
<Label Text="{Binding Name}"
FontAttributes="Bold" />
<StackLayout Orientation="Horizontal">
<Label Text="Seen?"
VerticalOptions="Center"/>
<CheckBox IsChecked="{Binding Seen}"
Margin="8,0,0,0"
VerticalOptions="Center"
IsEnabled="False" />
</StackLayout>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
</StackLayout>
The basic idea from this demo is to change the value of the property Seen
and set value for the CheckBox
when the user clicks on that Button above the ListView
.
This is my Car.cs
class.
public class Car : INotifyPropertyChanged
{
private string name;
public string Name
{
get { return name; }
set
{
name = value;
OnPropertyChanged();
}
}
private bool seen;
public bool Seen
{
get { return seen; }
set
{
seen = value;
OnPropertyChanged();
}
}
// Make base class for this logic, something like BindableBase
public event PropertyChangedEventHandler PropertyChanged;
protected virtual void OnPropertyChanged([CallerMemberName] string propertyName = null)
{
PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
}
}
In the full demo example which is on my Github, I am using my BindableBase
class where I handle raising the INotifyPropertyChanged
when some property value is changed with this SetProperty method in the setter of the props.
You can find the implementation here: https://github.com/almirvuk/Theatrum/tree/master/Theatrum.Mobile/Theatrum.Mobile
The last thing to show is my ViewModel
for this page, and inside of the ViewModel
, I will change the value of Seen
property to True
for items in the collection when the user clicks on the Button
above the ListView
. Here is my SimpleMvvmExamplePageViewModel.cs
public class SimpleMvvmExamplePageViewModel
{
public ObservableCollection<Car> Cars { get; set; }
public ICommand SetStatusCommand { get; private set; }
public SimpleMvvmExamplePageViewModel()
{
// Set simple dummy data for our ObservableCollection of Cars
Cars = new ObservableCollection<Car>()
{
new Car()
{
Name = "Audi R8",
Seen = false
},
new Car()
{
Name = "BMW M5",
Seen = false
},
new Car()
{
Name = "Ferrari 430 Scuderia",
Seen = false
},
new Car()
{
Name = "Lamborghini Veneno",
Seen = false
},
new Car()
{
Name = "Mercedes-AMG GT R",
Seen = false
}
};
SetStatusCommand = new Command(SetStatus);
}
private void SetStatus()
{
Car selectedCar = Cars.Where(c => c.Seen == false)
.FirstOrDefault();
if (selectedCar != null)
{
// Change the value and update UI automatically
selectedCar.Seen = true;
}
}
}
This code will help us to achieve this kind of behaviour: When the user clicks on the Button
we will change value of the property of the item from collection and UI will be refreshed, checkbox value will be checked.
The final result of this demo could be seen on this gif bellow.

P.S. I could combine this with ItemTapped
event from ListView
but I wanted to make this very simple so this example is like this.
Hope this was helpful for you, wishing you lots of luck with coding!