New answer for old question.
Using C++11's <chrono>
plus this free, open-source library:
https://github.com/HowardHinnant/date
One can very easily convert these timestamps to std::chrono::system_clock::time_point
, and also convert these timestamps to human-readable format in the Gregorian calendar:
#include "date.h"
#include <iostream>
std::chrono::system_clock::time_point
from_windows_filetime(long long t)
{
using namespace std::chrono;
using namespace date;
using wfs = duration<long long, std::ratio<1, 10'000'000>>;
return system_clock::time_point{floor<system_clock::duration>(wfs{t} -
(sys_days{1970_y/jan/1} - sys_days{1601_y/jan/1}))};
}
int
main()
{
using namespace date;
std::cout << from_windows_filetime(128166372003061629) << '\n';
std::cout << from_windows_filetime(128166372016382155) << '\n';
std::cout << from_windows_filetime(128166372026382245) << '\n';
}
For me this outputs:
2007-02-22 17:00:00.306162
2007-02-22 17:00:01.638215
2007-02-22 17:00:02.638224
On Windows, you can actually skip the floor
, and get that last decimal digit of precision:
return system_clock::time_point{wfs{t} -
(sys_days{1970_y/jan/1} - sys_days{1601_y/jan/1})};
2007-02-22 17:00:00.3061629
2007-02-22 17:00:01.6382155
2007-02-22 17:00:02.6382245
With optimizations on, the sub-expression (sys_days{1970_y/jan/1} - sys_days{1601_y/jan/1})
will translate at compile time to days{134774}
which will further compile-time-convert to whatever units the full-expression requires (seconds, 100-nanoseconds, whatever). Bottom line: This is both very readable and very efficient.