PHP how to get the base domain/url?

Question

function url(){
    if(isset($_SERVER['HTTPS'])){
        $protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
    }
    else{
        $protocol = 'http';
    }
    return $protocol . "://" . $_SERVER['HTTP_HOST'];
}

For example with the function above, it works fine if I work with the same directory, but if I make a sub directory, and work in it, it will give me the location of the sub directory also for example. I just want example.com but it gives me example.com/sub if I'm working in the folder sub. If I'm using the main directory,the function works fine. Is there an alternative to $_SERVER['HTTP_HOST']?

Or how could I fix my function/code to get the main url only? Thanks.

Your snippet looks very similar to https://stackoverflow.com/a/14500505/2943403 — mickmackusa, Jan 11 '21 at 00:28

score 117 · Accepted Answer · answered Jun 19 '13 at 21:01

117

Use SERVER_NAME.

echo $_SERVER['SERVER_NAME']; //Outputs www.example.com

answered Jun 19 '13 at 21:01

Bad Wolf

8,206
4
34
44

3

@barbushin's answer below is better nowadays. – Robin van Baalen Oct 05 '17 at 14:24
2

Here's the link to barbushin's answer: https://stackoverflow.com/a/43911112/457268 It presupposes knowledge of the domain though, and is not useful if one wants to dynamically determine the host name. – k0pernikus Feb 17 '20 at 09:22
@barbushin's answer is not better. Its flat out wrong. Hardcoding the domain is not the correct answer. – Joel Karunungan Mar 12 '21 at 08:59
it outputs for me: example.com not www.example.com – hamburger Apr 14 '21 at 09:59

score 56 · Answer 2 · answered Jun 19 '13 at 21:00

56

You could use PHP's parse_url() function

function url($url) {
  $result = parse_url($url);
  return $result['scheme']."://".$result['host'];
}

answered Jun 19 '13 at 21:00

`$_SERVER['SERVER_NAME']` wasn't an option since we do interactive domain hosting with custom ports. (Why should we make things easy ?) – programaths Nov 07 '14 at 10:48
1

I believe parse_url return nothing, if no http. For example: $url = "example.com"; – Deepak Rajpal Feb 08 '19 at 11:15
2

Please add some explanation to your answer by editing it, such that others can learn from it - where does `$url` come from? – Nico Haase Apr 08 '20 at 13:20

score 38 · Answer 3 · answered May 11 '17 at 09:08

38

Shortest solution:

$domain = parse_url('http://google.com', PHP_URL_HOST);

answered May 11 '17 at 09:08

barbushin

5,165
5
37
43

4

This should be accepted as answer, because its cross domain capability – Naveen DA Dec 27 '17 at 05:23
14

This gives you the string "google.com". It's a flat out wrong answer. – Andrew Magill May 03 '18 at 00:59
1

@AyexeM You're supposed to change "google.com" to your website's domain. – undo Dec 02 '18 at 18:10
18

@rahuldotech That makes no sense, copy paste your domain in there and it will return your domain? How is that helpful ? OP wants the domain of the server, not how to parse a domain from a string. – Andrew Magill Feb 26 '19 at 18:34
1

How I understand the question is how to get the domain segment without knowing what the domain is. That is, relative to the page you are loading. What if you are testing locally, then uploading to production? If you already know the domain, you don't need to retrieve it dynamically. I think the assumption is we don't know the domain the resource is loading from. – TARKUS Jun 04 '19 at 11:13
You may want to use this snippet on several websites you have and dynamically always be able to insert the domain name into somewhere in your code. – Michael Moriarty Jan 30 '20 at 05:51

Jasmeen · Answer 4 · 2017-05-11T06:34:16.077

30

/**
 * Suppose, you are browsing in your localhost 
 * http://localhost/myproject/index.php?id=8
 */
function getBaseUrl() 
{
    // output: /myproject/index.php
    $currentPath = $_SERVER['PHP_SELF']; 

    // output: Array ( [dirname] => /myproject [basename] => index.php [extension] => php [filename] => index ) 
    $pathInfo = pathinfo($currentPath); 

    // output: localhost
    $hostName = $_SERVER['HTTP_HOST']; 

    // output: http://
    $protocol = strtolower(substr($_SERVER["SERVER_PROTOCOL"],0,5))=='https'?'https':'http';

    // return: http://localhost/myproject/
    return $protocol.'://'.$hostName.$pathInfo['dirname']."/";
}

edited May 11 '17 at 06:34

answered May 06 '16 at 11:17

Jasmeen

876
9
16

1

Umm... see php.net/manual/en/reserved.variables.server.php `$_SERVER["SERVER_PROTOCOL"]` returns a string like `HTTP/1.0` or `HTTP/1.1` and has nothing to do with https. You're probably looking for something like `$_SERVER['HTTPS'] == 'on'` or the undocumented `REQUEST_SCHEME`. See [this related question](https://serverfault.com/questions/827850/what-exactly-does-the-variable-server-protocol-actually-contain-apache-2-4) and here's the answer I used: http://stackoverflow.com/a/14270161/466314 – Ultimater May 10 '17 at 07:30
See, Previously I have wrote 5, It was correct but minor changes should be there like, $protocol = strtolower(substr($_SERVER["SERVER_PROTOCOL"],0,5))=='https'?'https':'http'; – Jasmeen May 11 '17 at 06:31
1

No, `strtolower(substr($_SERVER["SERVER_PROTOCOL"],0,5))=='https'‌` is always false because $_SERVER["SERVER_PROTOCOL"] doesn't work the way you think it does. It will never contain HTTPS anywhere in it. The example given in the apache documentation `` is wrong as it's always true: https://httpd.apache.org/docs/2.4/rewrite/remapping.html#canonicalhost – Ultimater May 12 '17 at 23:29

score 11 · Answer 5 · answered Jun 19 '13 at 21:01

11

Use parse_url() like this:

function url(){
    if(isset($_SERVER['HTTPS'])){
        $protocol = ($_SERVER['HTTPS'] && $_SERVER['HTTPS'] != "off") ? "https" : "http";
    }
    else{
        $protocol = 'http';
    }
    return $protocol . "://" . parse_url($_SERVER['REQUEST_URI'], PHP_URL_HOST);
}

Here is another shorter option:

function url(){
    $pu = parse_url($_SERVER['REQUEST_URI']);
    return $pu["scheme"] . "://" . $pu["host"];
}

answered Jun 19 '13 at 21:01

Get Off My Lawn

34,175
38
176
338

parse_url returns nothing, if there is no http or https, i.e example.com – Asfandyar Khan Apr 25 '19 at 11:29

score 6 · Answer 6 · answered Nov 28 '17 at 09:22

Step-1

First trim the trailing backslash (/) from the URL. For example, If the URL is http://www.google.com/ then the resultant URL will be http://www.google.com

$url= trim($url, '/');

Step-2

If scheme not included in the URL, then prepend it. So for example if the URL is www.google.com then the resultant URL will be http://www.google.com

if (!preg_match('#^http(s)?://#', $url)) {
    $url = 'http://' . $url;
}

Step-3

Get the parts of the URL.

$urlParts = parse_url($url);

Step-4

Now remove www. from the URL

$domain = preg_replace('/^www\./', '', $urlParts['host']);

Your final domain without http and www is now stored in $domain variable.

Examples:

http://www.google.com => google.com

https://www.google.com => google.com

www.google.com => google.com

http://google.com => google.com

what if other subdomain is used instead www? – bksi Jun 11 '19 at 22:13 — bksi, Jun 11 '19 at 22:13

score 2 · Answer 7 · answered Apr 20 '19 at 20:35

2

2 lines to solve it

$actual_link = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on' ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$myDomain = preg_replace('/^www\./', '', parse_url($actual_link, PHP_URL_HOST));

answered Apr 20 '19 at 20:35

Fadi

267
2
6

This answer is missing its educational explanation. – mickmackusa Jan 11 '21 at 00:15

Aasif khan · Answer 8 · 2019-05-22T06:35:26.050

/* Get sub domain or main domain url
 * $url is $_SERVER['SERVER_NAME']
 * $index int remove subdomain if acceess from sub domain my current url is https://support.abcd.com ("support" = 7 (char))
 * $subDomain string 
 * $issecure string https or http
 * return url
 * call like echo getUrl($_SERVER['SERVER_NAME'],7,"payment",true,false);
 * out put https://payment.abcd.com
 * second call echo getUrl($_SERVER['SERVER_NAME'],7,null,true,true);
*/
function getUrl($url,$index,$subDomain=null,$issecure=false,$www=true) {
  //$url=$_SERVER['SERVER_NAME']
  $protocol=($issecure==true) ?  "https://" : "http://";
  $url= substr($url,$index);
  $www =($www==true) ? "www": "";
  $url= empty($subDomain) ? $protocol.$url : 
  $protocol.$www.$subDomain.$url;
  return $url;
}

score 2 · Answer 9 · answered Jan 11 '21 at 00:02

2

Use this code is whork :

if (!preg_match('#^http(s)?://#', $url)) {
         $url = 'http://' . $url;
}
$urlParts = parse_url($url);
$url = preg_replace('/^www\./', '', $urlParts['host']);

answered Jan 11 '21 at 00:02

lookly Dev

325
3
5

This answer is missing its educational explanation. Also, I would prepare the url with a single preg call instead of two. ...and please use correct spelling. – mickmackusa Jan 11 '21 at 00:19

score 1 · Answer 10 · answered Apr 18 '20 at 07:52

1

This works fine if you want the http protocol also since it could be http or https. $domainURL = $_SERVER['REQUEST_SCHEME']."://".$_SERVER['SERVER_NAME'];

answered Apr 18 '20 at 07:52

Rudolph

139
1
8

score 0 · Answer 11 · edited Jul 14 '16 at 18:38

0

Please try this:

$uri = $_SERVER['REQUEST_URI']; // $uri == example.com/sub
$exploded_uri = explode('/', $uri); //$exploded_uri == array('example.com','sub')
$domain_name = $exploded_uri[1]; //$domain_name = 'example.com'

I hope this will help you.

edited Jul 14 '16 at 18:38

Ismail RBOUH

10,292
2
24
36

answered Jul 14 '16 at 14:49

Charles

320
2
8

In here $domain_name = 'sub' not 'example.com'. If need to get 'example.com' , then change the last code to $domain_name = $exploded_uri[0]; – Udara Herath Jan 04 '17 at 11:58

score -2 · Answer 12 · answered Oct 02 '18 at 17:09

-2

Tenary Operator helps keep it short and simple.

echo (isset($_SERVER['HTTPS']) ? 'http' : 'https' ). "://" . $_SERVER['SERVER_NAME']  ;

answered Oct 02 '18 at 17:09

Oluwaseye

685
8
20

^ What they said. You probably also want to check the value of `$_SERVER` – M. Eriksson Dec 05 '18 at 09:44

score -3 · Answer 13 · answered May 13 '20 at 01:44

-3

If you're using wordpress, use get_site_url:

get_site_url()

answered May 13 '20 at 01:44

Elron

1,235
1
13
26

PHP how to get the base domain/url?

13 Answers13

Step-1

Step-2

Step-3

Step-4

Linked