How does sort function work in JavaScript, along with compare function

Question

As already asked: how does sort function work in JavaScript, along with the compare function? If I have an array, and I do array.sort(compare) now it was written in the book that if the compare function returns a-b (two indices of the array) then it works based on the fact that whether the result is greater than 0, less than 0 or equal to 0. But, how exactly does it work? I could not work it out.

Answer 1

The "compare" function must take two arguments, often referred to as a and b. Then you make the compare function return 0, greater than 0, or less than 0, based on these values, a and b.

1. Return greater than 0 if a is greater than b
2. Return 0 if a equals b
3. Return less than 0 if a is less than b

With these three return values, and only two arguments, it is possible to write a compare function that can sort any type of input data type, or complex data structures.

Then, when you call sort(), with your custom compare function, the compare function is called on pairs in your to-be-sorted list, to determine the proper ordering.

Lets walk through a simple example... Suppose you're only sorting some numbers, so we have a very simple compare function:

function compare(a,b) {
    return a - b;
}

Simply subtracting b from a will always return greater than zero if a is larger than b, 0 if they are equal, or less than zero if a is less than b. So it meets the requirements for a compare function.

Now lets suppose this is our list of numbers to sort:

var numbers = [1,5,3.14];

When you call numbers.sort(compare), internally it will actually execute:

compare(1,5);     // Returns -4, a is less than b
compare(1,3.14);  // Return -2.14, a is less than b
compare(5,3.14);  // returns 1.86, a is greater than b

If you've ever done manual sorting or alphabetizing, you've done precisely the same thing, probably without realizing it. Even though you may have dozens or hundreds of items to compare, you're constantly comparing only two numbers (or author's last names, or whatever) at a time. Going through or short list of three numbers again, you'd start by comparing the first two numbers:

1. Is 1 greater than or less than 5? Less than, so put these two numbers in our list: 1,5
2. Is 3.14 greater than or less than 1? Greater than, so it goes after 1 in the new list
3. Is 3.14 greater than or less than 5 in our new list? Less than, so it goes before 5. Our new list is now [1,3.14,5]

Because you can provide your own compare() function, it is possible to sort arbitrarily complex data, not just numbers.

Answer 2

By default, the array sort() method sorts alphabetically ascending. If you want to sort in some other order, because your array contains numbers or objects then you can pass a function in to the sort().

The function you pass in takes two parameters, often called a and b, and returns: a negative number if the first argument should be sorted before the second (a < b) 0 if the arguments are equal (a==b) a positive number if the first argument should be sorted after the second (a > b)

Now, here is the key bit: the function you pass as a parameter to sort() will be called repeatedly by sort() as it processes the whole array. sort() doesn't know or care about the datatype of the things in the array: each time it needs to know "Does item A come before item B?" it just calls your function. You don't need to worry about what type of sort algorithm is used internally by sort(), indeed one browser might use a different algorithm to another, but that's OK because you just have to provide a way for it to compare any two items from your array.

Your function could have an if / else if / else structure to decide what result to return, but for numbers simply returning (a-b) will achieve this for you because the result of the subtraction will be -ve, 0 or +ve and correctly put the numbers in ascending order. Returning (b-a) would put them descending:

  var sortedArray = myArray.sort(function(a,b){
                                    return (a-b);
                                });

If you had an array of objects and wanted to sort on some particular property or properties of the objects you could do that too. Assuming, e.g., objects in this format:

{ id : 1,
  name : "Fred",
  address : "12 Smith St",
  phone : "0262626262" }

Then you could sort an array of such objects by their 'id' attribute as follows:

var sortedArray = myArray.sort(function(a,b){
                                  return (a.id - b.id);
                              });

Or you could sort an array of such objects by their 'name' attribute (alphabetical) as follows:

var sortedArray = myArray.sort(function(a,b){
                                   if (a.name < b.name)
                                      return -1;
                                   else if (a.name == b.name)
                                      return 0;
                                   else
                                      return 1;
                               });

Note that in my final example I've put the full if / else if / else structure I mentioned earlier.

For the example where you are sorting objects with multiple properties you could expand that further to include a secondary sort, that is, (in my example) if the name properties are equal you could then return a comparison of, say, the phone property.

Answer 3

This method uses the syntax and parameters of the order of Array.sort (the compareFunction the sortOptions), whose parameters are defined as follows:

compareFunction - a comparison function used to determine the sort order of the array elements. This parameter is optional. The comparison function should be used to compare the two parameters. A and B of a given element, the result of compareFunction can have a negative value, 0 or a positive value:

If the return value is negative, it means that A appears before B in the sorted sequence. If the return value is 0, then A and B have the same sort order. If the return value is positive, it means that A appears after B in the sorted sequence.

Answer 4

We can simplify for sorting in normal order and reverse order

first parameter is a.

second parameter is b.

function compare(a, b) {
  //  make some operations to calculate these variables as true or false
  //     weNeedToMoveFirstParameterInPositiveDirection
  //     weDoNotNeedToMove
  //     weNeedToMoveFirstParameterInNegativeDirection

  // just think about numerical axis <------(-1)---(0)---(1)------>
  if (weNeedToMoveFirstParameterInPositiveDirection) return 1;  
  if (weDoNotNeedToMove) return 0; 
  if (weNeedToMoveFirstParameterInNegativeDirection) return -1;  
}

Answer 5

sort method alone treat numbers as strings so if the array of strings you don't need the compare function. but if the array of numbers you need the compare function to alter the build behavior of the sort method.

ex1 :strings

var animals = ["Horse", "Cat", "Tiger", "Lion"];  
animals.sort();

ex2 : numbers

var marks = [70, 90, 60, 80 ];  
marks.sort(function(a, b){return a > b}); //ascending , a < b descending . 

Answer 6

You can use Uint32Array at the moment to create the array.

[https://i.stack.imgur.com/qBgvm.png]

but, it has some difficulties. For example, you can't add a new value to the array. Simply, you can't modify the array length.

Answer 7

Sorting has actually little to do with the compare function, in a way, because it does not resemble the algorithm but the output of it.

---

Model & Example

1. Take the array [1,4,3,5],
2. Sort it mentally first (part of it): [1, 3,...] however you want it when sorted.

This may be the tricky part:

3. Take a pair of elements in your mentally sorted array:
   • the one to the left is b, the one to the right is a

Now define compareFn to follow this model.

Example 1

(without ternary operator)

const myArray = [1,4,3,5]

function compareFn(a,b){
   if(b < a) return 1
   return -1
}

console.log(myArray.sort(compareFn))

Example 2

const myArray = [1,4,3,5]

function compareFn(a,b){
   return b > a ? 1 : -1
}

console.log(myArray.sort(compareFn))

---

(you can reverse step 3 idea, and also the sort fn.)

Answer 8

I think it may be like this(well, I am not sure about this.)：

suppose the function compare(a,b) is the compare function. It returns c. suppose we are going to sort the entries in the arrayN to get the sort result array M.

I don't know the exact sort algorithm , and different browsers even return different results if c is neither (a-b) nor (b-a) (say, if c is "b-2", "a+b" or some other expressions).

But according to ECMA-262 , the sort result should be like this:

a , b can be any two of the indexes. this means we actually passed an ordered pair to the compare function. eg: (0,1),(1,4), or even (2,0) , (2,1).

The ECMAScript Language Specification says the result should have this property: (a,b)is an ordered pair passed to the compare function.

• if c (what the function returns) is less than zero, then M(a)< M(b) must be satisfied.

And the specification talks nothing about what would happen if c is zero or bigger than zero.

I am not sure whether this is right. At least this can easily explain why when c is "a-b" , the entries are sorted to be numerically and ascending, and why when c is "b-a",the entries are sorted to the opposite.

Are the js engines of the browsers are not really designed strictly according to `ECMA-262 or am I totally wrong?

Reference：

The Fifth Edition of ECMA-262 (Check page 129-130)