How not to copy some attributes?

Question

I need to copy from input document to output document all attributes but one.

My input is like this:

<mylink id="nextButton" type="next" href="javascript:;" />

And I need output like this:

<a id="nextButton" href="javascript:;" />

If I use the following XSL:

<xsl:template match="mylink">
    <a><xsl:copy-of select="attribute::*"/></a>
</xsl:template>

I get all attributes to output like this:

<a id="nextButton" type="next" href="javascript:;" />

But I want to ignore the "type" attribute. I've tried the following but none of them seems to work the way I need:

<xsl:copy-of select="attribute::!type"/>
<xsl:copy-of select="attribute::!'type'"/>
<xsl:copy-of select="attribute::*[!type]"/>
<xsl:copy-of select="attribute::not(type)"/>

How should I write my stylesheet to get needed output?

vartec · Accepted Answer · 2009-03-23T11:17:58.387

41

Shortest form:

<xsl:template match="mylink">
    <a><xsl:copy-of select="@*[name()!='type']"/></a>
</xsl:template>

Longer one (that's the first thing I came up with, I leave it for reference):

<xsl:template match="mylink">
    <a>
     <xsl:for-each select="@*">
      <xsl:if test="name() != 'type'">
       <xsl:attribute name="{name()}"><xsl:value-of select="."/></xsl:attribute>
      </xsl:if> 
     </xsl:for-each>
    </a>
</xsl:template>

edited Mar 23 '09 at 11:17

answered Mar 23 '09 at 11:06

vartec

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I used the longer one to swap out the name of an attribute ("change `type` to `class`"). Is there a version of the shorter one that will accomplish the same thing? – Max Heiber Sep 22 '16 at 18:56

score 2 · Answer 2 · answered Jun 28 '17 at 07:37

2

In XSLT 2.0:

<xsl:template match="mylink">
  <a><xsl:copy-of select="@* except @type"/></a>
</xsl:template>

answered Jun 28 '17 at 07:37

yegor256

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How not to copy some attributes?

2 Answers2

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