How do I get the current working directory with the least amount of dependencies possible?

Question

I have a Rust application which works as a shell. I want to get the working directory the user is in using as little dependencies as possible.

I tried using

let path = env::current_dir();
print!("{} > ",path.display());

But it gives me the following error: method not found in `Result<PathBuf, std::io::Error>'

I tried running this in the rust playground and it worked alright, so I was wondering if any of you could help me with this

Do you want the executable's path or the user's current working directory? — John Kugelman, Feb 25 '22 at 18:34
Notably "the path the executable is in" and "the current folder the user is in" aren't always the same. — Shepmaster, Feb 25 '22 at 19:01
Please [edit] your question to specify which of the two you want. — Kevin Reid, Feb 25 '22 at 21:15
As for the error about `Result`, see the paragraph I added to [my answer](https://stackoverflow.com/a/71270401/5445670). — Solomon Ucko, Feb 26 '22 at 04:19

Solomon Ucko · Accepted Answer · 2022-02-26T04:18:28.557

2

You can use std::env::current_dir to get the current working directory.

You also need to use match, std::result::Result::unwrap, std::result::Result::expect, ?, or something else to handle the Err variant of the Result and access the value inside the Ok variant.

edited Feb 26 '22 at 04:18

answered Feb 25 '22 at 18:43

Solomon Ucko

1 Answers1